Formule Trigonometrice - cls XI, actualizat cls X

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Last updated 2:06 PM on 5/3/26
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29 Terms

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formula fundamentala a trigonometriei

cos2x+sin2x=1

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cosx (cu sin)

cosx=sin(π/2-x)

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sinx (cu cos)

sinx=cos(π/2-x)

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cos(a-b)

cos(a-b)=cosa*cosb+sina*sinb

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cos(a+b)

cos(a+b)=cosa*cosb-sina*sinb

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sin(a+b)

sin(a+b)=sina*cosb+cosa*sinb

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sin(a-b)

sin(a-b)=sina*cosb-cosa*sinb

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tg(a+b)

tg(a+b)=(tga+tgb)/(1-tga*tgb)

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tg(a-b)

tg(a-b)=(tga-tgb)/(1+tga*tgb)

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sin2x

sin2x=2*sinx*cosx

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cos2x

cos2x = cos2x - sin2x = 1 - 2sin2x = 2cos2x - 1

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tg2x=

tg2x=2tgx/(1-tg2x)

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tgx*ctgx=

tgx*ctg=1

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cos a*cos b=

cos a*cos b= ½ [ cos(a-b) + cos(a+b) ]

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sin a*sin b=

sin a*sin b= ½ [ cos(a-b) - cos(a+b)]

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sin a*cos b=

sin a*sin b= ½ [ sin(a-b) + sin(a+b) ]

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cos x+cos y

cos x+cos y=2*cos((x+y)/2)*cos((y-x)/2)

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cos x-cos y=

cos x+cos y=2*sin((x+y)/2)*cos((y-x)/2)

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sin x+sin y=

sin x+sin y=2*sin((x+y)/2)*sin((x-y)/2)

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sin x-sin y=

sin x-sin y=2*sin((x-y)/2)*cos((x+y)/2)

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ctg x (cu tg)

ctg x=tg (π/2-x)

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cos x (cu tg)

cos x = ± 1/(1+tg2x)

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cos(arcsin y)

cos(arcsin y) = √(1-y2)

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sin (arccos x)

sin (arccos x) = √(1-x2)

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tg (arccosx) =

tg (arccosx) = √(1-x2)/x

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arccos x + arcsin x =

arccos x + arcsin x = π/2

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tg (arcctg x) =

tg (arcctg x) = 1/x

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arctg x + arcctg x =

arctg x + arcctg x = π/2

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sin x (cu tg)

sin x = tg x / (√1+tg2x)