1/28
Name | Mastery | Learn | Test | Matching | Spaced | Call with Kai |
|---|
No analytics yet
Send a link to your students to track their progress
formula fundamentala a trigonometriei
cos2x+sin2x=1
cosx (cu sin)
cosx=sin(π/2-x)
sinx (cu cos)
sinx=cos(π/2-x)
cos(a-b)
cos(a-b)=cosa*cosb+sina*sinb
cos(a+b)
cos(a+b)=cosa*cosb-sina*sinb
sin(a+b)
sin(a+b)=sina*cosb+cosa*sinb
sin(a-b)
sin(a-b)=sina*cosb-cosa*sinb
tg(a+b)
tg(a+b)=(tga+tgb)/(1-tga*tgb)
tg(a-b)
tg(a-b)=(tga-tgb)/(1+tga*tgb)
sin2x
sin2x=2*sinx*cosx
cos2x
cos2x = cos2x - sin2x = 1 - 2sin2x = 2cos2x - 1
tg2x=
tg2x=2tgx/(1-tg2x)
tgx*ctgx=
tgx*ctg=1
cos a*cos b=
cos a*cos b= ½ [ cos(a-b) + cos(a+b) ]
sin a*sin b=
sin a*sin b= ½ [ cos(a-b) - cos(a+b)]
sin a*cos b=
sin a*sin b= ½ [ sin(a-b) + sin(a+b) ]
cos x+cos y
cos x+cos y=2*cos((x+y)/2)*cos((y-x)/2)
cos x-cos y=
cos x+cos y=2*sin((x+y)/2)*cos((y-x)/2)
sin x+sin y=
sin x+sin y=2*sin((x+y)/2)*sin((x-y)/2)
sin x-sin y=
sin x-sin y=2*sin((x-y)/2)*cos((x+y)/2)
ctg x (cu tg)
ctg x=tg (π/2-x)
cos x (cu tg)
cos x = ± 1/(√1+tg2x)
cos(arcsin y)
cos(arcsin y) = √(1-y2)
sin (arccos x)
sin (arccos x) = √(1-x2)
tg (arccosx) =
tg (arccosx) = √(1-x2)/x
arccos x + arcsin x =
arccos x + arcsin x = π/2
tg (arcctg x) =
tg (arcctg x) = 1/x
arctg x + arcctg x =
arctg x + arcctg x = π/2
sin x (cu tg)
sin x = tg x / (√1+tg2x)