Proton transfer reactions (acids and bases)

0.0(0)
studied byStudied by 0 people
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/35

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

36 Terms

1
New cards

bronsted lowry acids and bases

  • bronsted lowry acid: gives away a proton

  • bronsted lowry base: accepts a proton using its lone pair of electrons

2
New cards

conjugate acids and bases

  • conjugate base of an acid: species remaining after the acid donates a proton

  • conjugate acid of a base: species remaining after the base accepts a proton

3
New cards

amphiprotic species

  • species that can act as both proton donors and proton acceptors

  • e.g water

4
New cards

the pH scale

  • the acidity of an aqueous solution depends on the number of H+ ions in the solution

  • pH = – log10[H+]

  • [H+] = 10–pH

    • pH usually given to 2 d.p

    • logarithmic scale, each pH value is 10 times the value below it

  • the lower pH, the more acidic, the higher pH, the more alkaline

5
New cards

pH of acids, bases and water explained

  • acidic solutions

    • always have more H+ than OH- ions

    • [H+] always greater than 10-7 mol dm-3, so pH always below 7

  • basic solutions

    • always have more OH- ions than H+ ions

    • [H+] is always smaller than 10-7 mol dm-3, so pH always above 7

  • pH of water

    • at 298K, water has equal amounts of OH- and H+ ions with concs of 10-7 mol dm-3

6
New cards

how to measure pH

  • pH meter:

    • most accurate

    • connected to pH electrode which shows the pH value of solution

  • universal indicator

    • less accurate

    • dipped into solution of acid and changes colour

    • colour is compared to a chart which shows different pH values

7
New cards

the ion product of water (Kw)

  • an equilibrium exists in water, where a few water molecules dissociate into H+ and OH- ions

    • H2O (l) ⇌ H+ (aq) + OH– (aq)

  • equilibrium constant for this reaction is:

    • Kc = [H+][OH-] / [H2O]

    • Kc x [H2O] = [H+][OH-]

  • since the conc of H+ and OH- ions is very small, conc of water is considered to be a constant

  • so Kw = [H+] [OH-]

  • Kw (ion product of water) =  Kc x [H2O] =  1.00 x 10-14 at 298K

8
New cards

how does temp affect Kw

  • ionisation of water is an endothermic process, so due to le chateliers principle, an increase in temp will favour the forward reaction

    • [H+][OH-] increases

    • magnitude of Kw increases

    • pH decreases

  • increasing temp decreases pH of water (more acidic)

  • decrease temp increases pH of water (more basic)

9
New cards

strong and weak acids

  • strong acid: dissociates almost completely in aqueous solutions

    • position of equilibrium extremely right, irreversible

    • e.g HCl, HBR, HI, HNO3, H2SO4

    • solution formed is highly acidic due to high conc of H+ ions

    • pH can be calculated if concentration of strong acid is known

  • weak acids: acids that partially dissociate in aqueous solutions

    • position of equilibrium is more to the left equilibrium is established (reversible reaction)

    • e.g ethanoic acid

    • solution formed is less acidic due to lower concentration of H+ ions

  • strength of bronsted lowry acid depends on the ease with which it dissociates to released H+ ions

10
New cards

strong and weak bases

  • strong base: base that dissociates almost completely in aqueous solution

    • position of equilibrium extremely right, irreversible

    • e.g NaOH

    • solution formed highly basic due to high conc of OH- ions

  • weak base: base that partially dissociates in aqueous solution

    • position of equilibrium more left, equilibrium is established (reversible)

    • e.g NH3

    • solution formed less basic due to lower conc of OH- ions

11
New cards

strength of conjugate acids and bases

  • strong acids produce weak conjugate bases

    • because reverse reaction is virtually non existent

  • weak acids produce strong conjugate bases

  • strong bases produce weak conjugate acids

  • weak bases produce strong conjugate acids

12
New cards

distinction between strong and weak acid

  • pH value

    • the stronger the acid, the greater the H+ conc, the lower the pH

  • electrical conductivity

    • stronger acids give higher readings conductivity meter because they have more ions in solution

  • reactivity

    • as conc of H+ is much greater in strong acids the rate of reaction with metals and metal compounds is greater than of weak acids of the same conc

13
New cards

neutralisation reaction

  • acid + base —> salt + water

  • H+ + OH- —> H2O

  • spectator ions not involved in formation of water form the the salt

14
New cards

summary of neutralisation reactions

  • acid + metal —> salt + hydrogen gas

    • extent of reaction depends on reactivity of metal and strength of acid

  • acid + metal oxide —> salt + water

  • acid + metal carbonate —> salt + water + carbon dioxide

  • acid + metal hydrogencarbonate —> salt + water + carbon dioxide

15
New cards

SA + SB pH curve

  • e.g NaOH + HCl

  • shows how the pH of a solution changes as the acid/base is added in a strong acid/strong base titration

    • pH of acid: where the curve starts on y-axis, roughly 1

    • equivalence point: “stoichiometric end of reaction”, when the acid/base neutralisation is complete

  • calculating pH after x volume of base added:

    1. calculate moles of acid and base (conc x volume of base added)

    2. determine moles of excess acid

    3. determine new volume (vol of acid + added volume of base)

    4. [H+]= moles of excess acid / new volume

    5. -log[H+] = pH

<ul><li><p>e.g NaOH + HCl</p></li><li><p>shows how the pH of a solution changes as the acid/base is added in a strong acid/strong base titration</p><ul><li><p>pH of acid: where the curve starts on y-axis, roughly 1</p></li><li><p>equivalence point: “stoichiometric end of reaction”, when the acid/base neutralisation is complete</p></li></ul></li><li><p>calculating pH after x volume of base added:</p><ol><li><p>calculate moles of acid and base (conc x volume of base added)</p></li><li><p>determine moles of excess acid</p></li><li><p>determine new volume (vol of acid + added volume of base)</p></li><li><p>[H+]= moles of excess acid / new volume</p></li><li><p>-log[H+] = pH</p></li></ol></li></ul><p></p>
16
New cards

pOH scale

  • basicity of aqueous solution depends on number of hydroxide ions

  • pOH = -log [OH-]

  • pH = 14 - pOH

17
New cards

relationship between H+ OH- pH and pOH

knowt flashcard image
18
New cards

dissociation of a weak acid

  • weak acids HA dissociate partially in water

    • HA (aq) ⇌  A- (aq) + H+ (aq)

  • at equilibrium, majority of HA molecules remain unreacted

  • position of equilibrium is more left, equilibrium is established

  • acid dissociation constant, Ka = [A-][H+] / [HA]

    • values of Ka are very small

19
New cards

dissociation of a weak base

  • weak bases (B) ionise in water

    • B (aq) + H2O (l) ⇌  BH+ (aq) + OH- (aq)

  • equilibrium is established

  • base dissociation constant Kb = [BH-][OH-] / [B]

20
New cards

assumptions made when calculating pKb, Kb, pKa, Ka

  • initial conc of acid is about the equilibrium conc of acid

  • [A-] = [H+]

  • negligible ionisation of the water, so [H+] is not affected

  • The temperature is 298 K

21
New cards

pKa and pKb

  • pKa = -logKa

  • pKb = -logKb

<ul><li><p>pKa = -logKa</p></li><li><p>pKb = -logKb</p></li></ul><p></p>
22
New cards

Ka and Kb of conjugate acid-base pairs

  • Ka x Kb = Kw

23
New cards

salt hydrolysis

  • ionic salt is formed from neutralisation of acid and base

    • HA (parent acid) + MOH (parent base) —> M+A- (salt) + H2O

  • ionic salt formed will dissociate in water

    • hydrolysis is where water is used to break a bond within compound, resulting in aqueous ions

  • pH of salt depends on the strength of parent acid and base used

24
New cards

summary of salt hydrolysis reactions

  • SA + SB

    • neutral

    • weak conjugate acid and base ions therefore no hydrolysis occurs

    • equivalence point= pH 7

  • SA + WB

    • acidic

    • strong conjugate acid of WB is formed, which reacts with water to form H+ ions, therefore solution becomes more acidic

      • M+ + H2O —> MOH + H+

    • equivalence point = <7 pH

  • WA + SB

    • alkaline

    • strong conjugate base of WA is formed, which reacts with water to form OH- ions, therefore solution becomes more basic

      • A- + H2O —> HA + OH-

    • equivalence point = >7 pH

  • WA + WB

    • depends on relative Ka and Kb

25
New cards

WA + SB pH curve

  • e.g NaOH + CH3COOH

  • starting pH roughly 3 because WA

  • initial rise in pH steep as neutralisation of WA by strong base is rapid

  • ethanoate ions (conjugate base to weak acid) are formed, creating a buffer

  • buffer formed will resist changes in pH so pH rises gradually in buffer region

  • pKa = pH [H+] = Ka at half equivalence point

  • equivalence point = >7 pH

<ul><li><p>e.g NaOH + CH3COOH</p></li><li><p>starting pH roughly 3 because WA</p></li><li><p>initial rise in pH steep as neutralisation of WA by strong base is rapid</p></li><li><p>ethanoate ions (conjugate base to weak acid) are formed, creating a buffer</p></li><li><p>buffer formed will resist changes in pH so pH rises gradually in buffer region</p></li><li><p>pKa = pH  [H+] = Ka at half equivalence point</p></li><li><p>equivalence point = &gt;7 pH</p></li></ul><p></p>
26
New cards

SA + WB pH curve

  • e.g NH3 + HCl

  • starting pH roughly 11 (WB)

  • pH falls as WB begins to be neutralised and forms conjugate acid

    • creates buffer region so pH falls slowly

  • half equivalence point (where half the amnt of WB has been neutralised)

  • pKb = pOH [OH-] = Kb at half equivalence point

  • equivalence point = <7 pH

27
New cards

acid-base indicators

  • weak acid which dissociates to make anion of a different colour

  • e. g HInd ⇌ H+ (aq) + Ind– (aq)

  • HIn and its conjugate base Ind- are different colours

  • if solution acidic, equilibrium shifts left and HInd colour is shown

  • if solution basic, equilibrium shifts right, and Ind- colour is shown

  • universal indicator is a mix of many indicators with a wide pH range of colour

28
New cards

indicator calculations

  • pH at which transitions between colours occur:

    • Ka

  • endpoint of reaction is when there is balance of [HIn] and [In-]

    • Ka = [H+][Ind-] / [HInd] = [H+]

  • take negative logs of both sides

    • pKa = pH

    • pKa of an indicator is the same as its pH at end point

  • colour change takes place over range of pH = pKa ± 1

29
New cards

choosing the right indicator

  • indicator is appropriate if it has an endpoint range that coincides with pH at equivalence point

30
New cards

buffer solutions

  • solution which resists changes in pH when small amounts of acid/base are added

  • used to keep the pH almost constant

  • consists of weak acid- conjugate base or weak base conjugate acid

31
New cards

acidic buffers

  • e.g aqueous mixture of sodium ethanoate and ethanoic acid

  • ethanoic acid is weak, ionises in solution to form relatively low conc of ethanoate ions

  • sodium ethanaote is salt, fully ionises in solution

  • contains reserves supplies of the acid and its conjugate base

    • high conc of ethanoic acid due to partial ionisation

    • high conc of ethanoate ions due to full ionisation of sodium ethanaote

  • in buffer solution, ethanoic acid in equilibrium with hydrogen and ethanoate ions

32
New cards

adding H+ to acidic buffer

  • equilibrium shifts left as H+ ions react with CH3COO- to form more CH3COOH until equilibrium reestablished

  • large reserve supplies of both CH3COO- and CH3COOH so pH remains relatively constant

33
New cards

adding OH- to acidic buffer

  • reacts with H+ to form water

  • equilibrium position shifts right, more CH3COOh molecules ionise to form more H+ and ethanoate ions until equilibrium reestablished

  • pH remains constant

34
New cards

basic buffers

  • made by mixing a solution of a weak base with its salt

    • e.g NH3 and NH4Cl

  • ammonia partially dissociate in water forming NH4+ and OH-

  • NH4Cl fully dissociates forming NH4+ and Cl- ions

  • adding acid/base will result in no change in pH

    • additional H+ will combine with NH3 to make NH4+

    • additional OH- will combine with NH4+ to form NH3 and H2O

35
New cards

buffer calculations

  • to determine pH of buffer:

    • [H+] needed, found using:

      • [H+]= Ka [acid]/[salt]

      • pH = pKa + log[salt] /[ acid]

  • to determine pOH

    • [OH-] needed, found using

      • [OH-] =Kb [base] / [salt]

      • pOH = pKb + log[salt] / [base]

36
New cards

factors affecting buffers

  • dilution

    • Ka and Kb are equilibrium constants so not changed by dilution

    • doesn’t change ratio of acid/base conc to salt conc

  • temperature

    • constant temp must be maintained when using buffers

    • temp affects values of Ka and Kb