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XS NaNH2 in NH3
H2O
(to an alkane)
Creates an alkyne from and alkane, the 2nd step protonates the negative charge, tends to give a terminal alkyne
Molten KOH
(to an alkane)
Creates an alkyne from an alkane, give an internal alkyne
H-X (1 eq)
Creates an alkene from the akyne and adds X to one side and H to the other side
Called hydrohalogenation
XS H-X (2 eq.)
Creates an alkane from the alkyne and adds the 2 X’s to the same carbon and the 2 H’s to the same carbon
hydrohalogenation
Regio: Markovnikov (will be anti-mark if added with peroxide)
Mechanism need to know
HgSO4 in H2SO4, H2O
Creates an alkane from the alkyne and adds -OH to one side of alkene and -H to the other side
The -OH turns into a ketone via keto-enol tautomerism (thanks to the H2O)
Will use acid catalyzed keto-enol tautomerism (need to know mechanism)
Regio: Markovnikov
H2 /Pt
Reduction of an alkyne fully to alkane
Catalytic hydrogenation
H2/Lindlars
partial reduction of the alkyne to the alkene
Gives the cis alkene
Na in NH3
partial reduction of an alkyne to an alkene
gives the cis alkene
Metal-ammonia reduction
Sia2BH • THF
H2O2, NaOH
Reduction of the alkyne to an alkene, adds the Sia2B (replaced by -OH) to the less substituted carbon (anti-mark), and then undergoes base catalyzed keto-enol tautomerism
KMnO4, H2O neutral
reduces alkyne to diketones, gives 4 -OHs initiallly, but then 2 H2Os are removed to produced diketones
to a terminal alkyne will give a ketone and a carboxylic acid
KMnO4, KOH in H2O, heat
cleaves the triple bond and gives to carboxylic acids
will initially produce two carboxide ions which will be protonated to two carboxylic acids
NaH • THF
will create an alkoxide ion
R-O-H + NaH → R-O- + Na+ + H2
Will create a strong nucleophile
Addition of H3O+ to alkenes
will add an -OH to the more substituted carbon, carbocation potenial rearrangements
Regio: Markovnikov
Hg(OAc)2, H2O
NaBH4
oxymercuration demurcuration
regio: markovnikov
adds an -OH to the more substituted carbon
BH3 • THF
H2O2, NaOH
hydroboration oxidation
adds -OH to the less substituted carbon
Regio: Anti-mark
O3
Et2S (dimethylsulfide)
will cleave the double bond in alkenes to produce ketones and aldehydes
Mechanism —> carbon will attack the O with the double bond, double bonded O electrons will go to the center O, the single bonded O (with charge) will attack the carbon/alkene
KMnO4, OH- (cold, dilute)
SYN dihydroxylation
will at -OH to both sides of the akene onto the same side (either both wedges or both dashes)
OsO4, H2O2
SYN dihydroxylation
will at -OH to both sides of the akene onto the same side (either both wedges or both dashes)
mCPBA (RCOOH), H3O+ (to alkene)
ANTI dihydroxilation
creates an epoxide first, then the acid will break the epoxide ring and give an anti dihydroxylation
Mg, ether
H3O+
creates a grignard reagents which insterts itself between the halide and the carbon
can attack carbonyl compounds via Sn2 (???) and give an alcoxide, which si protonated by H3O and turn alcohol + extend the carbon chain
addition to acid chlorides or esters will give a tertiary (3º) alcohol because the reaction will occur twice
2Li, ether
H3O
creates an organolithium reagent
will react the same as a grignard
CuI
2R-Li + CuI —> R2CuLi + LiI
makes the gilman reagent
Will attack carbonyl compounds to extend the chain and create an alkoxide ion, which will be protonated by the acid workup (H3O) to give an alcohol
LiAlH4, ether
H3O+
hydride from the compound attacks carbonyl compounds to create alkoxide ion, which is then protonated to an alcohol
This is a strong reducing agent and will reduce ketones, aldehydes, esters, and carb acids
will reduce esters and carb acids to 1º alcohols
NaBH4, ether
H3O
reduces ketones and aldehydes to alkoxides and then turns them into alcohols (with acid workup)
does not react with esters or carboxylic acids
can take place in a variety of solvents, like alcohols, ethers, and water
Raney Nickel
reduces a ketone to an -OH, as well as any alkenes to alkanes
catalytic hydrogenation
H-S
thiol
will react with alkyl halide (H-X) to create R-SH (the thiol)
thiols can be oxidized by mild oxidizing agents to disulfides that can be reduced back to thiols with a reducing agent
oxidation with strong oxidizing agenst (ex. KMnO4, HNO3, or NaOCl) converts thiols into sulfonic acids
Na2Cr2O7, H2SO4 (secondary alcohols)
will reduces secondary alcohols to ketones
PCC and NaOCL/HOAc will do the same
Na2Cr2O7, H2SO4 (primary alcohols)
will reduce primary alcohols to carboxylic acids
PCC or NaOCl/TEMPO
will reduce primary alcohols to aldehydes
DMSO, (CO)Cl2 in ET3N, CHCl2
swern oxidation
reduces alcohols to aldehydes
TsCl, pyr
Tosylate esters add to where there is an OH group to make OTs, which is a VERY good leaving group (bulky)
no interconversion when this occurs
can be used for Sn2 or E2
Reduction of alcohols
dehydrate it with H2SO4, then at H2/Pt
make a tosylate the reduce it with LiAlH4 (R-OTs + LiAlH4 —> R-H, an alkane)
ZnCl2, HCl (concentrated)
Lucas reagent
secondary and teriary alcohols react with the lucas reagent via Sn1, primary react via Sn2
Addition of a lewis acid, such as ZnCl2 will bond strongly with OH, promoting the reaction
this will replace an alcohol with a Cl
PCl3, pyr
alcohol will attack the phosphorus, displacing one of the halides
Cl will attack at the back (Sn2)
PBr3
alcohol will attack the phosphorus, displacing one of the halides
Br will attack at the back (Sn2)
P/I2
alcohol will attack the phosphorus, displacing one of the halides
I will attack at the back (Sn2)
SoCl2 (thionyl chloride)
will give retention of configuration if PYR IS NOT PRESENT
will replace the -OH on the carbon with a Cl and also create SO2 and HCl
(go over pinacol rearrangement)
dehydration of two OH with H2SO4, but due to carbocation rearrangement will give a ketone
OsO4, H2O2
HIO4
periodic acid cleavage of glycols
oxidatively cleaves glycols (-OH’s that are right next to each other) to crate ketones and aldehydes
Alcohol + carboxylic acid in H2SO4
esterification
will produce an ester
Alcohol + acyl chloride in pyr (???)
esterification
will produce an ester in higher yield and HCl will be a by-product
Williamson ether synthesis
Na and R-O- + R-CH2-X —> R-O-CH2-R + NaX
ethers can be synthesized by the rxn of alkoxide ions with primary alkyl halides