AP Bio Unit 5 - Chapter 11

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23 Terms

1

Why did Mendel continue some of his experiments to the F2 generation?

to observe whether or not a recessive trait would reappear

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2

which of the following statements correctly describes one difference between the Law of Independent Assortment and the law of segregation?

The Law of Independent Assortment explains the segregation of two or more genes relative to one another

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3

two plants are crossed resulting in a Offspring with a 3:1 ratio for a particular trait. what does a suggest about the trait?

 that the parents were both heterozygous for a single trait

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4

a sexually reducing animal has two unlinked genes one for head shape (H) and one for tail length (T),  it's genotype is HhTt. which of the following genotypes is possible from this organism

HT

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5

When Crossing an organism that is homozygous recessive for a single trait was the one that is heterozygous for the same trait what is the chance of producing an offspring with the homozygous recessive phenotype?

50%

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6

What was Mendel's explanation for his observation that traits had disappeared in the F1 generation reappeared in the F2 generation of the pea plants he used in his experiments?

traits can be dominant or recessive and the recessive traits were hidden by the dominant ones in the F1

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7

why did the F1 offspring of Mendel's classic Peak cross always look like one of the two parental varieties?

one allele was dominant

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8

 in certain plants the tall trait is dominant to the short trait. if a heterozygous plant is crossed with a homozygous tall plant what is the probability that The Offspring will be short?

0

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9

phenylketonuria is a disease and humans that results from the abnormal metabolism of the amino acid phenylalanine. if untreated it can lead to severe brain damage in infants. two normal parents have a child who has PKU. what can you determine about the inheritance of PKU allele from this information?

 It is recessive

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10

 in humans wavy hair occurs and heterozygotes offspring of people with straight hair and curly hair. which of the following crosses would produce Offspring with the ratio of one straight to two wavy to one curly?

wavy and wavy

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11

which of the following describes the ability of a single Gene to have multiple phenotypic effects?

pleiotropy

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12

skin color in humans has a wide variety of phenotypes the expression of this trait is caused by more than two genes. what type of inheritance pattern is responsible for this expression?

Polygenic Inheritance

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13

Which of the following statements correctly describes an example of epistasis?

rabbits and many other mammals one genotype prevents any fur color from developing

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14

 achondroplastia a form of dwarfism in humans is caused by dominant allele what is the probability of a heterozygous dwarf man in a normal homozygous woman having a child who's a heterozygous dwarf?

50%

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15

in a particular plant leaf color is controlled by Gene Locus D. plants with at least one D allele have dark green leaves and plants with the homozygous recessive dd genotype have light green leaves. a true-breeding dark-leaf plant is crossed with a light-leaved one in the F1 Offspring is allowed to self-pollinate. the predicted outcome of the F2 is diagrammed at the Punnett Square shown in the figure above where 1, 2, 3, and 4 represent the genotypes corresponding to each box within the square. which of the boxes marked 1-4 corresponds to plants with dark leaves?

1, 2, 3

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16

in a particular plant leaf color is controlled by Gene Locus D. plants with at least one D allele have dark green leaves and plants with the homozygous recessive dd genotype have light green leaves. a true-breeding dark-leaf plant is crossed with a light-leaved one in the F1 Offspring is allowed to self-pollinate. the predicted outcome of the F2 is diagrammed at the Punnett Square shown in the figure above where 1, 2, 3, and 4 represent the genotypes corresponding to each box within the square. Which of the boxes corresponds to plants with a heterozygous genotype?

2 and 3

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17

 a particular plant leaf color is controlled by Gene Locus D. plants with at least one D allele have dark green leaves and plants with the homozygous recessive dd genotype have light green leaves. a true-breeding dark-leaf plant is crossed with a light-leaved one in the F1 Offspring is allowed to self-pollinate. the predicted outcome of the F2 is diagrammed at the Punnett Square shown in the figure above where 1, 2, 3, and 4 represent the genotypes corresponding to each box within the square. Which of the plants will be true breeding?

1 and 4 only

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18

Labrador Retrievers are black brown or yellow. in a cross of a black female with a brown male results can be all black puppies, half black to half brown puppies, or 3/4 black to 1/4 yellow puppies. these results indicate which of the following about inheritance pattern of fur color and Labrador retrievers?

Epistasis is involved

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19

Labrador retrievers are black brown or yellow. and a cross of a black female with a brown male, the results can be all black puppies, half black to half brown puppies, or 3/4 black to 1/4 yellow puppies. how many genes must be responsible for these coat colors and Labrador Retrievers?

2

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20

Labrador retrievers have Blackie brown or yellow fur. for colors controlled by two genes one of which exhibits epistasis. black is dominant over Brown in one gene, and E is dominant over lowercase e in the other Gene. the uppercase E is epistatic to the black Gene in a cross of a black female with a brown male result can be all black puppies, half black to half brown puppies, or 3/4 black to 1/4 yellow puppies. and a cross of black and black the results were as follows:  9/16 black, 4/16 yellow and 3/16 brown.  is the genotype eebb must result in which of the following?

Yellow

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21

A woman who has blood type A positive has a daughter who is Type O positive and a son who is type B negative. which of the following is a possible genotype for the son?

 IBi

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22

A woman who has blood type A positive has a daughter who is Type O positive and a son who is type B negative. Which of the following is a possible partial genotype for the mother?

 IAi

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23

A woman who has blood type A positive has a daughter who is Type O positive and a son who is type B negative. Which of the following is a possible phenotype for the father?

B positive

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