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electric potential =
work done per positive test charge as q -> 0
most general formula
V =-∞∫p E-> · dl->
why is electric potential the same regardless of the path, and which path should be taken =
E field is a conservative field, so V is same regardless of path
take straight path or along E field lines
What happens to test charge if Q is positive? Negative?
Q > 0, repulsion and positive work
Q < 0, attraction and negative work
electric potential formula for a point charge =
V = kQ/r
k = 1/4πε₀
If no Gaussian symmetry at all, how to find E-field and electric potential =
Find E-field with E = ∫(k dQ / r²) r̂
Find V_p = ∫(k dQ / r)
where k = 1 / (4πε₀)
If Gaussian symmetry exists, how to find E-field and electric potential =
Find E-field w/ Gauss Law
Find V_p = -∫(∞ to r) E dr
Potential energy change bringing charge q to a point at potential V_P =
ΔU_e = qΔV_P
Work to Potential Energy relation =
W = -ΔU_e
What is ΔV_A→B if E field IS and ISNT uniform =
V_B - V_A, opposite direction of ece 140
Uniform
kQ(1/[r_B] - 1/[r_A])
Non-uniform
-∫(∞ to B) E→ · dl→ + ∫(∞ to A) E→ · dl→ = V_B - V_A
Relation of E and V =
E→ = −∇V
E_x = −∂V/∂x, E_y = −∂V/∂y, E_z = −∂V/∂z
What is E-field in Equipotential Surfaces =
E→ is ALWAYS perpendicular to equipotential surfaces
constant V = no work is done moving a charge along one