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random
we know what could happen, but you don’t know what will happen
trial
one attempt at a random phenomenon
outcome
the result of a trial
sample space
set of all possible outcomes (S = {1, 2, 3, …})
the sum of all probabilities equals 1
probability of an event
P(A) = (number of favored outcomes) / (number of possible outcomes)
always between 0 and 1 (100%)
complement of A (A’)
P(not A) = 1 - P(A)
mutually exclusive (disjoint)
events that don’t share any outcomes in common
addition rule
mutually exclusive: P(AuB) = P(A) + P(B)
general: P(AuB) = P(A) + P(B) - P(AnB)
union (u)
“or” A or B or both
intersection (n)
“and” both A and B
multiplication rule
multiply the probabilities of two events if there are multiple things happening
independence
events A and B are independent if P(B|A) = P(B)
conditional probability
P(A|B) = P(AnB) / P(B)
| = “given”
tree diagram
a way of showing all possible outcomes and their probabilities, works well with conditional probability
probability of “at least one”
probability of not 0
P(not 0) = 1 - P(0)
law of averages
the probability of something occurring increases if you are further from the average (due for a…)
this rule is false
law of large numbers
as we repeat a random process over and over, the true probability will emerge
random variable (X)
a number based on a random event
expected value of a random variable E(X)
ÎŁ[x * P(x)]
standard deviation of a random variable SD(X)
sqrt {ÎŁ[(x - x-bar)^2 * P(x)]}
probability model
outcome, x, P(X = x)
shifting a random variable
add/subtract from the mean, does not affect standard deviation
rescaling a random variable
multiply mean/standard deviation by the factor
adding two random variables
E(X + Y) = E(X) + E(Y)
SD(X + Y) = sqrt [SD(X)^2 + SD(Y)^2]
subtracting two random variables
E(X - Y) = E(X) - E(Y)
SD(X - Y) = sqrt [SD(X)^2 + SD(Y)^2]
summing a series
E(X1, X2…Xn) = n * E(X)
SD (X1, X2…Xn) = sqrt [n * SD(X)^2]
using a normal model to find probability
find the expected value and standard deviation, find the z-score, use normal cdf