Calc 3 Chapter 12

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Last updated 2:35 AM on 9/21/26
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24 Terms

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how to represent x,y coordinates on a circle with radius R using cos and sin?

(Rcos(t), Rsin(t)) = Rcos(t)i + Rsin(t)J

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circle centered at 0,0 using x and y formula

x2 + y2 = r2

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center shifts w/ cos and sin

2 + cost would be if the center is at x=2

cost - 2 would be if the center is at x=-2

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r(t) = *as a coordinate

(x(t), y(t), z(t))

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<p></p>


don’t forget the constant of integration (which is a vector meaning that it adds a constant c1 c2 and c3 to the ijk respectively. the constants can be different so you need to solve for them!)

<p>don’t forget the constant of integration (which is a vector <strong>meaning that it adds a constant c<sub>1</sub> c<sub>2</sub> and c<sub>3</sub> to the ijk respectively. the constants can be different so you need to solve for them!</strong>)</p>
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what is a zero vector

all the values for (x,y,z) are (0,0,0)

<p>all the values for (x,y,z) are (0,0,0)</p>
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speed =

magnitude of velocity aka take derivative of the position function then take norm of that

<p>magnitude of velocity aka take derivative of the position function then take norm of that</p>
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what does the vector r’(t) represent if r(t) is continuous and differentiable

r’(t) is a vector tangent to the motion of the curve traced by r(t)

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A curve is closed if it…

A curve is closed if it has all of the following:

  • a parameterization r→(t)

  • a ≤ t ≤ b

  • r→(a) = r→(b)


<p>A curve is closed if it has all of the following: </p><ul><li><p>a parameterization r<sup>→</sup>(t)</p></li><li><p>a ≤ t ≤ b</p></li><li><p>r<sup>→</sup>(a) = r<sup>→</sup>(b)</p></li></ul><p></p>
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A curve is smooth if…

A curve if smooth if for SOME parameterization r(t) along [a,b]

  • r’(t) is continuous & exists for all t in the interval [a,b]

  • r’(t) ≠ 0→ for all t in the interval [a,b] aka r’(t) isn’t a zero vector for all t in [a,b]


e.g. a circle


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piecewise smooth defn

Piecewise smooth means that the curve can be divided into a finite number of sub intervals like [a,b] [b,c] [c,d] etc where each sub interval is smooth


e.g. a square has 4 corners making it not differentiable in those spots, but the square can be broken up into pieces where each piece is a line that is smooth within its subinterval

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how to obtain new parameterizations (e.g. r(t) = (t, t2)

you can do t = t2 and get a new parameterization, q(t) which = (t2, t4)… essentially you can plug in different values

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arclength formula + what types of curves does it work for?

aka integrate speed aka integrate the magnitude of velocity

  • works for smooth and piecewise smooth curves

  • only works if r(t) traces the curve only once within [a,b]


<p>aka integrate speed aka integrate the magnitude of velocity </p><ul><li><p>works for smooth and piecewise smooth curves</p></li><li><p><strong>only works if r(t) traces the curve only once within [a,b]</strong></p></li></ul><p></p>
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Unit tangent vector (formula)

normalize velocity

<p>normalize velocity</p>
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What is a principal normal vector?

The principal normal vector is a vector of length one that is perpendicular to a curve and points toward the inside of the curvature

Note that the principal normal vector isn’t defined at inflection points bc there is no curvature so pointing “inwards” doesn’t exist

Straight lines have no curvature and therefore the principal normal vector is undefined

<p>The principal normal vector is a vector of length one that is perpendicular to a curve and points toward the inside of the curvature<br><br>Note that the principal normal vector isn’t defined at inflection points bc there is <strong>no</strong> <strong>curvature </strong>so pointing “inwards” doesn’t exist<br><br>Straight lines have no curvature and therefore the principal normal vector is undefined</p>
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principal normal vector formula

normalize the derivative of the unit tangent vector

<p>normalize <strong><em>the derivative</em></strong> of the unit tangent vector</p>
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what does the tangential component of acceleration control? what does the normal component of acceleration control?

aTT→ changes a particle’s speed

aNN→ changes a particle’s direction

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aN is ____ to 0 because ____

the normal component of acceleration is always greater than or equal to 0 because the direction can’t be negative

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tangential component of acceleration formula

[velocity dotted with acceleration] all over the magnitude of velocity

<p>[velocity dotted with acceleration] all over the magnitude of velocity</p>
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normal component of acceleration formula

the magnitude of the [velocity crossed with acceleration] all over the magnitude of velocity

<p>the magnitude of the [velocity crossed with acceleration] all over the magnitude of velocity </p>
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a→(t) =

where:

  • aT and aN get evaluated as the tangential and normal components, respectively, of acceleration

  • the symbols T→ and N→ stay as they are written as if were variables such as x and y


<p>where:</p><ul><li><p>a<sub>T</sub> and a<sub>N</sub> get evaluated as the tangential and normal components, respectively, of acceleration </p></li><li><p>the symbols T<sup>→</sup> and N<sup>→</sup> stay as they are written as if were variables such as x and y</p></li></ul><p></p>
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How to use Pythagorean theorem to get the tangential or normal component of acceleration easier (FORMULA)


<p></p>
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how to find where a plane and some parameterization r(t) written in ijk form intersect

plug in the different components from r(t) into x,y, and z in the plane equation

e.g.

r(t) = 5t²i - (t+1)j + (t2+1)k

8x+7y+0z = 5

8(5t2) + 7( -(t+1) ) + 0(t2 + 1) = 5 now solve for t