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3.1-3.10
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Primary Alcohols
have their Hydroxyl groups at the end of a chain(terminal (are only connected to one carbon
Secondary Alcohols
have their hydroxyl groups within the chain (are connected to two carbons)
Tertiary Alcohols
have their hydroxyl group within a chain which a substituent is branching (connected to three carbons)
Alcohols oxidise to lose
Two hydrogens, allowing for a Carbon-oxygen double bond to be formed
A primary Alcohol is oxidised (in acidic conditions) into a
Aldehyde
A secondary Alcohol is oxidised (in acidic conditions) into a
Ketone
An Aldehyde can be oxidised further in acidic conditions to form
Carboxylic acid
An Aldehyde can be further oxidised in alkaline conditions to form
carboxyl ion
If an acidified potassium dichromate solution turns from orange to green with an alcohol,
it is a primary or secondary Alcohol (as it can be oxidised)
if a silver Mirror forms when tollen’s reagent and silver is added to this Alcohol
It is an Aldehyde
If nothing happens within the acidified potassium dichromate
The Alcohol is tertiary
If nothing happens when Tollen’s reagent is added to the Alcohol
it is a Ketone
How does Tollen’s reagent work?
Tollen’s reagent allows for the alkaline oxidation of Aldehydes, forming carboxylate ions. The aldehyde’s ions are donated to the Silver ions, making them solid
in any structure lines linking to O or OH
do not indicate new carbons
Monosaccharides
are individual sugar molecules, which are monomers for complex carbohydrates
Examples of Monosaccharides
Glucose, Fructose
Disaccharides
Two monosaccharide sugars bonded together with covalent bonds
Example of Disaccharides
Lactose, Sucrose, Maltose
disaccharides are formed through
condensation( which releases water to bond the two sugars together)
carbohydrates are
classified as polyhydroxyl aldehydes or polyhydroxyl ketones
what are polyhydroxy Aldehydes
Aldehydes with multiple hydroxyl function groups
What are polyhydroxy Ketones
Ketones with multiple hydroxyl function groups
in aqueous equilibrium, monosaccharides exist in
cyclical and chain form
At equilibrium, monosaccharide’s
cyclical structure is heavily favoured (only 0.02% is chain form )
Suffix for Alcohols
-ol
Suffix for Aldehydes
___-N-al
suffix for Ketones
___-N-one
Suffix for Carboxylic acids
-ioc acid
Suffix for double carboxyl group carboxylic acids
alkane name+dioic acid
Carboxylic acids have
a high melting/boiling point, and good solubility
Carboxylic acids are miscible from
Methanoic to butanoic
When Carboxylic acid reacts with metals
it is not always soluble (+1 charges are)
When Benzene (aromatic) is used as a function group, it is called
phenyl
How are Carbohydrates indentified?
As Polyhydroxy-Aldehydes or Polyhydrox-Ketones
(or substances that will form these during hydrolysis)
What is the reaction name when two monosaccharides join to form a disaccharide?
Condensation
What is the name of the reaction when a disaccharide breaks into two monosaccharides?
hydrolysis
Acidified Potassium Dichromate changes colour from Orange to Green by
converting the primary or secondary Alcohol into either a Aldehyde or a Ketone
What are Esters formed from?
A condensation reaction between Carboxylic acid (ROOH) and an alcohol (ROH)
Naming esters
Alkyl group is named first (-yl) then carbonic acid group (-oate)
Esters have
a lower boiling point than their carboxylic acid and alcohol counterparts
Alcohol functional group
-OH (Hydroxyl
Ketone functional group
C=O ( non terminal carbonyl
What is the functional group of an amine
-NH2
Primary amines are
covalently bonded to one carbon and have two hydrogens
Secondary amines are
covalently bonded to two carbons and have one hydrogen
Amines can
accept protons,forming a covalent bond with the proton with nitrogen’s lone pair of electrons
What is the name of amines after they have accepted a proton?
protonated amine
What is the ester functional group?
COOC
how are poly esters made?
between condensation between a diol and a dicarboxylic acid
What is the name of one of the Esterification reactions
Fischer esterification
Esterification requires an
acid catalyst of concentrated sulphuric acid
Esterification is
a reversible reaction, so it reaches equilibrium
Esterification’s Kc value is
<1, so favours the reverse
How is Le Châtlier’s principle and collision theory used to optimise esterification
an excess of alcohol is use to shift the equilibrium to the right, favouring the products, while increasing the temperature increases the rate that condensation occurs
Esters can only interact between eachother with
dipole-dipole bonds
Ester’s boiling point
are much lower than carboxylic acids or alcohols
Small esters are
soluable in water
The result of ester Hydrolysis is
dependent on the pH
Acidic hydrolysis
requires a strong acid catalyst, and forms the orginal carboxylic acid and alcohol(reversible
Alkaline Hydrolysis
Requires a strong base catalyst, the alcohol and a carboxylate ion are formed (not reversible)
How are Amides formed?
Amides are formed between a condesation reaction between an amine and a carboxylic acid.
What is the amide functional group?
C=O-N(H)-R
Naming amides is not required, although
they are named by naming N, the alkyl group from N and the amine, changing the suffix to amide
Primary amides
have one carbon directly attached to the Nitrogen
Secondary Amides have
two carbon bonded to the nitrogen
Tertiary amides have
3 carbons bonded to the nitrogen
the amide functional group is
polar, and it can form hydrogen bonds with water, meaning with small chain lengths it is soluable
Polyamides are formed through
a condensation reaction between diamines and dicarboxylic acids
Acid Hydrolysis of Amides
requires an acid catalyst and hot water under reflux
what products are formed from acid hydrolysis
the original Carboxylic acid, and a protonated amine (reversible
Alkaline Hydrolysis
requires a strong base (usually NaOH) and is done under reflux
products from Alkaline hydrolysis
the reaction forms a carboxylate anion and an amine. The carboxylate anion forms a salt with the catalyst’s cation
What is the standardised name for gylcerol?
propane-1,2,3-triol
What are triglycerides?
Esters that are formed from a Glycerol backbone and three fatty acids (long carboxylic acid chains)
What are fatty acids?
Carboxylic acids with an even number of carbon from 12-22
What is a saturated fatty acid?
A fatty acid with only single bonds
What is an unsaturated fatty acid?
a fatty acid with double or tripple bonds.
Monounsaturated
1 double or triple bond
What reaction causes the formation of trigylcerides?
condensation
when a triglyceride is formed, the fatty acids are
not always the same
under acidic hydrolysis, triglycerides form
glycerol and fatty acids
under alkaline hydrolysis, triglycerides form
glycerol and carboxylate anions
Edible fats are mostly made up of
saturated fatty acids
In saturated triglycerides,
Hydrocarbon chains lie parallel, allowing for neat and ordered stacking
Why do hydrocarbons lie parallel in saturated triglycerides
The carbon’s geometry is tetrahedral, and changes in the presence of a double or triple bond
Saturated Triglycerides neat chains,
they have an increased dispersion forces between chains
Saturated Triglycerides have
a high melting point due to strong dispersion forces
Edible oils are mostly made up of
unsaturated fatty acids
Unsaturated triglycerides’ carbons have a combination of
tetrahedral and trigonal planar geometry
Unsaturated triglycerides’ double bonds
cause the trigonal planar geometry, as the chain twists.
Unsaturated triglycerides have
decreased dispersion forces due to their twisted chains not aligning neatly
Unsaturated triglycerides
have a lower melting point than saturated triglycerides
the general formula for a saturated fatty acid is
CnH2nO2
for every double bond
2 hydrogen atoms are displaced
Bromine and iodine
undergo addition reactions and bond to hydrocarbons, changing double bonds into single bonds
Bromine turns from
colourless to brown when all double bonds are taken up
bromine/ iodine number is
the mass of bromine or iodine that reacts with exactly 100g of the compound.jhg
Bromine/ iodine number steps- finding iodine number
1 determine molar mass of iodine/ bromine and compound
2: arrange in a ratio of I2:compound
3 divide both sides of the ratio by the compound’s molar mass to get a gram to gram ratio
4 multiply by 100 for grams of iodine or bromine used
Bromine/ iodine number steps- determining double bonds
1 determine moles of iodine/ bromine and compound present (mass/ molar mass
2: arrange in a ratio of I2:compound
3 to get one mole of the compound, divide both sides of the ratio by the compound’s mole.
4 ratio is complete
Hydrogenation
The addition of H2 molecules into a double bond, replacing them with single bonds