Reactivity 3.3: Organic Chemistry~hydrocarbons

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26 Terms

1

Define Homologous Series

A series of compounds of the SAME family, with the same general formula, which differ by a common structural unit

  • successive members differ from each other by −CH2−. group

  • They show a gradual change in physical properties (for example their melting-/boiling points increase as a result of increasingly stronger London dispersion forces).

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2

What are Alkanes? What is its Formula

Homologous series of SATAURATED hydrocarbons containing carbon-carbon single bonds

Formula: CnH2n+2

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3

What are Alkenes? What is its Formula?

Homologous series of UNSATURATED carbon-carbon-carbon double bonds

Formula:CnH2n

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4

What are Alkynes? What is its Formula?

Homologous series of UNSATURATED carbon-carbon-carbon triple bonds

Formula:CnH2n-2

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5

What are Aromatic Compounds

Contain at least 1 benzene ring

<p>Contain at least 1 benzene ring</p>
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6

What are Aliphatic Compounds

Compounds WITHOUT benzene rings

<p>Compounds WITHOUT benzene rings</p>
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7

Be able to Identify Functional groups and structures

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8

Define Homolytic bond fission

  • A covalent bond between 2 atoms in a molecule breaks with each atom taking 1 electron from the bond

  • Results in free radicals, which are HIGHLY reactive as they are unpaired

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9

Define Heterolytic Bond fission

  • Covalent bond between 2 atoms in a molecule breaks with on atom taking both bonding electrons

  • Results in cation/anions

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10

Why do Alkanes have LOW reactivity

  • Due to strong C-C and C-H bonds and they are non-polar which makes them unreactive to common(polar) reactants

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11

What reaction do alkANES undergo?

  • Free radical substitutions (halogenation)

  • Combustion

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12

Formula for Complete Combustion

CxHy + O2 —> CO2 + H2O

  • When oxygen supply is sufficient

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13

Formula for Incomplete Combustion

CxHy + O2 —> CO + H2O

  • When Oxygen supply is limited

  • Carbon is sometimes produced in extreme conditions

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14

What are the 3 processes Alkanes go through to undergo halogenation

  • Initiation

  • Propagation

  • Termination

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15

Describe Initiation

  • UV light is needed to break the bond through homolytic fission to produce free radicals

<ul><li><p>UV light is needed to break the bond through <strong><u>homolytic fission </u></strong>to produce free radicals </p></li></ul><p></p>
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16

Describe Propagation

  • Series of rxn between radicals to produce non-radicals to produce different non-radicals and free radicals

  • the number of free radicals stays the same

<ul><li><p>Series of rxn between radicals to produce non-radicals to produce different non-radicals and free radicals </p></li><li><p><span>the number of free radicals stays the same</span></p></li></ul><p></p>
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17

Describe Termination

  • Free radicals react with each other to form molecules and reaction stops when there are no more radicals

  • Number of free radicals decreases

<ul><li><p>Free radicals react with each other to form molecules and reaction stops when there are no more radicals </p></li><li><p>Number of free radicals decreases </p></li></ul><p></p>
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18

Why do alkenes have higher reactivity than alkanes

  • Because double bonds are the site of reactivity

  • pi bonds have electron density farther nuclei, so it is more easily broken

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19

What reaction do AlkENES

Electrophilic addition rxn, where 2 molecules combine to produce larger molecule

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20

Describe the steps of electrophilic addition steps

  1. Molecule being added (e.g. halogen) NEEDS to be polarized(slightly (+), slightly (-)). Allows electrons in molecule to be repel electron-rich double bond as molecule approaches it

  2. Double bonded carbons is attached by atom with partial positive charge, and the molecule splits HETEROLYTICALLY (creates a negative atom).

  3. Positive atom is attached and adjacent carbons become + charged (carbocation intermediate)

  4. Unstable carbocation and anion form a bond creating a stable product

<ol><li><p>Molecule being added (e.g. halogen) NEEDS to be polarized(slightly (+), slightly (-)). Allows electrons in molecule to be repel electron-rich double bond as molecule approaches it</p></li><li><p>Double bonded carbons is attached by atom with partial positive charge, and the molecule splits <strong><u>HETEROLYTICALLY</u></strong> (creates a negative atom). </p></li><li><p>Positive atom is attached and adjacent carbons become + charged (carbocation intermediate)</p></li><li><p>Unstable carbocation and anion form a bond creating a stable product  </p></li></ol><p></p>
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21

what reactions do alkenes undergo

  • Hydrogenation (hydrogen gas reacts with alkene)

  • Hydration

  • Halogenation(Alkenes react with halogens to produce disubstituted halogenoalkanes)

  • Hydrohalogenation

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22

Describe hydrohalogenation (symmetric addition)

  • Hydrogen halides react with alkenes to produce monosubstituted hydrogenoalkanes

  • H—X is polar molecule that undergoes heterolytic fission as well to form H+ and X- . Therefore molecule does NOT need to be polarized first

  • H+ (electrophile) attacks double bond, then carbocation intermediate reacts with X-.

  • Reactivity of hydrogen halides: HI>HBr>HCl(bonds increases in strength as reactivity decreases)

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23

Describe asymmetric addition reaction

  • When an asymmetric alkene (such as propene CH2 −−CH−CH3 ) reacts with an asymmetric reactant (such as H X or H OH), two structural isomers are formed from two different competing reactions.

  • According to Markovnikov’s rule: the + δ H or + δ X gets attached to the carbon with more hydrogen substituents, and the halide − δ X attaches to the carbon with more alkyl substituents (more stabilised carbocation aka secondary carbocation).

<ul><li><p>When an asymmetric alkene (such as propene CH2 −−CH−CH3 ) reacts with an asymmetric reactant (such as H X or H OH), two structural isomers are formed from two different competing reactions.</p></li></ul><p></p><ul><li><p>According to <span style="color: green"><strong><u>Markovnikov’s rule:</u></strong></span><span> </span>the + δ H or + δ X gets attached to the carbon with more hydrogen substituents, and the halide − δ X attaches to the carbon with more alkyl substituents (more stabilised carbocation aka secondary carbocation).</p></li></ul><p></p>
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24

Describe hydration

  • Reaction between water and alkene to form alcohol

  • Uses heat and concentrated sulfuric acid as catalyst

  • This electrophilic addition produces wither 1 or 2 products (depending if alkene is symmetric or asymmetric)

<ul><li><p>Reaction between water and alkene to form alcohol </p></li><li><p>Uses <strong>heat</strong> and <strong>concentrated sulfuric acid </strong>as catalyst </p></li><li><p>This electrophilic addition produces wither 1 or 2 products (depending if alkene is symmetric or asymmetric) </p></li></ul><p></p>
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25

Describe hydration (electrophilic addition of water) steps

  1. The double C=C bond is broken because it is attacked by H+ present in sulfuric acid, which converts into a C-C single bond, making a carbocation.

  2. Water then acts as nucleophile(electron-rich) and attacks the carbocations, forming the alcohol

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26

Describe polymerization of alkenes

  • Formed when smaller unsaturated molecules aka alkenes (monomers) react together

  • In addition polymerization, small monomers that contain a C=C double bond link together to form a longer polymer

  • During the process the double bonds in the monomers are converted into single bonds in the polymer

<ul><li><p><span>F</span><span style="font-family: Calibri, sans-serif">ormed when smaller unsaturated molecules aka alkenes (monomers) react together</span></p></li><li><p><span style="font-size: 7pt; font-family: &quot;Times New Roman&quot;"> </span><span style="font-family: Calibri, sans-serif">In addition polymerization, small monomers that contain a C=C double bond link together to form a longer polymer</span></p></li><li><p><span style="font-size: 7pt; font-family: &quot;Times New Roman&quot;"> </span><span style="font-family: Calibri, sans-serif">During the process the double bonds in the monomers are converted into single bonds in the polymer</span></p></li></ul><p></p>
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