babternatives to babametric burbaces

0.0(0)
Studied by 1 person
call kaiCall Kai
Locked
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/5

flashcard set

Earn XP

Description and Tags

| 14-24: advanced shading stuff | 30-32: mesh and widgets (?) (arcball, mover) | 33-36: bezier curves | 42-45: bezier patches | 55-61: alternative to parametric surfaces

Last updated 7:08 AM on 6/5/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai
Chat

No analytics yet

Send a link to your students to track their progress

6 Terms

1
New cards

alternatives to parametric surfaces (3)

subdivision surfaces, implicit surfaces, particle systems

2
New cards

subdivision surfaces def +

  • who came up with them? (2)

  • how do they work? (3 steps)

  • what do the surfaces become?

blend via recursive smoothing of a polygonal mesh

  1. ed catmull, jim clark (silicon graphics guy)

  2. e.g. for a rectangle defined by 4 points:

    1. add midpoints on each edge

    2. move each point halfway toward its cw neighbor

    3. repeat

  3. surfaces become more smooth with each iteration

3
New cards

implicit surfaces def +

  • compare to what?

  • how are they different?

  • what is the implicit equation for a circle/ what does it mean?

blend via summation of primitives

  1. parametric, where you have a single alpha and p = cos alpha, sin alpha

  2. parametric: give me parameters, i give you the point
    implicit: give me a test so i can check if a point is on it

  3. {p } : px^2 + py^2 − 1 = 0 → set of all p that fit this equation, exact same circle as parametric

    1. if = 0, on circle. positive = outside circle, negative = inside circle

4
New cards

use of implicit surfaces

  1. allows you to blend!! see blinn’s blobbies, merging two sphere together. way easier than trying to do it parametrically

  2. blue slime blob bob

5
New cards

in implicit surfaces, how do you know where there is an intersection?

if one point is positive and another is negative, you know there MUST be a boundary there somewhere, need to find where it equals 0, repeatedly subdivide and keep testing until you get 0

<p>if one point is positive and another is negative, you know there MUST be a boundary there somewhere, need to find where it equals 0, repeatedly subdivide and keep testing until you get 0</p>
6
New cards

particle systems def

individual points acting independently, individually displayed