Empirical and molecular formula

A sample of a compound contains 1.27g of Cu and 0.16g of O. Calculate the empirical formula (relative mass = Cu =63.5 and 0=16)

1.27 / 63.5 =0.02 (Copper moles)

0.16 / 16 =0.01 (Oxygen moles)

now create a ratio by dividing the mole numbers by the smallest number between then to. The smallest number is 0.01 so we are going to divide both numbers by 0.01.

0.02/0.01 =2

0.01/0.01 =1

empirical formula is 2:1

what is the step by step?

Mass / Ar value to get moles

divide by smallest number to get ratio

23

23

23

23