The Wave Particle Duality of Light

0.0(0)
Studied by 0 people
call kaiCall Kai
Locked
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/23

flashcard set

Earn XP

Description and Tags

Flashcards covering the wave-particle duality of light, photon energy, the photoelectric effect, Compton scattering, and the Heisenberg uncertainty principle.

Last updated 7:12 PM on 9/19/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai
Chat

No analytics yet

Send a link to your students to track their progress

24 Terms

1
New cards

What four physical phenomena demonstrate that light behaves like a wave?

Reflection, refraction, diffraction, and interference.

2
New cards

What is meant by the wave-particle duality of light?

The concept that light exhibits both wave-like behaviors (such as interference and diffraction) and particle-like behaviors (such as the photoelectric effect and Compton scattering) depending on the situation.

3
New cards

How are photons defined in the particle model of light?

Photons are fundamental particles of light described as tiny packets or bundles of light energy.

4
New cards

What are the mass and electric charge of a photon?

A photon has zero mass and zero electric charge.

5
New cards

At what speed do photons travel in a vacuum?

In a vacuum, photons travel at the speed of light, c=3×108 m/sc = 3 \times 10^8\text{ m/s}.

6
New cards

How are frequency (ff) and wavelength (λ\lambda) related for a photon traveling at speed cc?

They are indirectly proportional and related by the formula f=cλf = \frac{c}{\lambda}.

7
New cards

What is Planck's equation for calculating photon energy (EE) using frequency (ff)?

E=hfE = h f, where h=6.626×10−34 J⋅sh = 6.626 \times 10^{-34}\,J \cdot s is Planck's constant.

8
New cards

What is Planck's equation for calculating photon energy (EE) using wavelength (λ\lambda)?

E=hcλE = \frac{h c}{\lambda}, where c=3×108 m/sc = 3 \times 10^8\text{ m/s} is the speed of light.

9
New cards

How does photon energy change as frequency increases or wavelength decreases?

Higher frequency produces higher photon energy, and shorter wavelength produces higher photon energy.

10
New cards

What is the photoelectric effect?

The phenomenon where light shining on a metal surface ejects electrons (photoelectrons) instantly if the photon energy is sufficiently high.

11
New cards
<p>What physical phenomenon is depicted in this diagram showing incident photons ejecting photoelectrons from a surface?</p>

What physical phenomenon is depicted in this diagram showing incident photons ejecting photoelectrons from a surface?

The photoelectric effect.

12
New cards

How is the threshold frequency (f0f_0) defined?

The minimum frequency of light required to eject electrons from a specific metal surface.

13
New cards

How is the work function (W0W_0) of a metal defined?

The minimum energy that an electron in a metal needs to be emitted from the metal surface.

14
New cards

What happens in the photoelectric effect if incident light has a frequency below the threshold frequency (f0f_0)?

No electrons are emitted, regardless of the light intensity.

15
New cards

What effect does increasing light intensity have when light frequency is above the threshold frequency (f0f_0)?

It increases the number of photoelectrons emitted.

16
New cards

Why did the photoelectric effect challenge classical wave theory?

Classical wave theory could not explain the existence of a threshold frequency or the immediate emission of photoelectrons.

17
New cards

What occurs during Compton scattering?

An X-ray or gamma-ray photon collides with an electron in an inelastic collision, transferring energy to the electron and scattering with a longer wavelength.

18
New cards
<p>What collision process between a photon and an electron is illustrated in this diagram?</p>

What collision process between a photon and an electron is illustrated in this diagram?

The Compton effect (or Compton scattering).

19
New cards

Why does a photon's wavelength increase after colliding with an electron in Compton scattering?

The photon loses energy to the electron, and since energy is inversely proportional to wavelength (E=hcλE = \frac{h c}{\lambda}), losing energy increases the wavelength.

20
New cards

What does the Heisenberg Uncertainty Principle state?

It states that both the exact position and exact momentum of a quantum particle (such as an electron or photon) cannot be known simultaneously.

21
New cards

What is the formula for the Heisenberg Uncertainty Principle?

Δx⋅Δp≥h4π\Delta x \cdot \Delta p \ge \frac{h}{4\pi}, where Δx\Delta x is position uncertainty, Δp\Delta p is momentum uncertainty, and hh is Planck's constant.

22
New cards

According to the Heisenberg Uncertainty Principle, how does reducing position uncertainty (Δx\Delta x) affect momentum uncertainty (Δp\Delta p)?

Making position more certain (smaller Δx\Delta x) increases momentum uncertainty (larger Δp\Delta p).

23
New cards

What is the energy of a photon with a wavelength of 500 nm500\text{ nm}?

E=3.98×10−19 JE = 3.98 \times 10^{-19}\,J, calculated using E=hcλE = \frac{h c}{\lambda} with h=6.626×10−34 J⋅sh = 6.626 \times 10^{-34}\,J \cdot s, c=3.0×108 m/sc = 3.0 \times 10^8\text{ m/s}, and λ=500×10−9 m\lambda = 500 \times 10^{-9}\text{ m}.

24
New cards

An electron is confined to a region of space with Δx=1.0×10−10 m\Delta x = 1.0 \times 10^{-10}\text{ m}. What is the minimum uncertainty in its momentum (Δp\Delta p)?

Δp≥5.27×10−25 kg⋅m/s\Delta p \ge 5.27 \times 10^{-25}\,kg \cdot m/s, solved using Δx⋅Δp≥h4π\Delta x \cdot \Delta p \ge \frac{h}{4\pi}.