Thermodynamics & Gas Law

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Last updated 8:47 AM on 6/2/26
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67 Terms

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Structure with a greater extent of intermolecular forces have ______ boiling points because more energy is required to overcoem the attractions between molecuels during ______ from a liquid state to a gas state.

Hydrogen atoms bonded with N,O, or F form polar bonds with partial charge producing dipoles which ______ boiling point

higher

phase change

increases

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Branched structures experience fewer london forces comparable to straight chain molecules, which ____ boiling point

decreases

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A. deposition

B. Melting

C. condensation

D. Sublimation

Answer: A

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Passage A

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Passage A

Which of the following conclusions can be made based on figure 1 and data in table 1

Answer: D

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Passage A

Answer: C

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Freezing occurs when the _____ energy of the molecules can no longer overcome the _________ forces attracting nearby molecule together. As this happens, the molecules are pulled together and held as a solid.

Pure water molecuels strongly itneract rhough hydrogen bonding, which greatly assists freezing as the temperature reaches freezing point. As pure water molecules begin to freeze, molcules transition from _____ entropy (liquid0 to ____entropy (solid).

Add a salt solute disrupts some of these intermolecular interactions between the water molecules and forms new _______ interactions with salt ions. This inclusion of a salt also ____ the entropy (disrupts the usual order)

kinetic

intermolecular

High (liquid) to lower entropy (solid)

ion dipole interactions

increases the entropy

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Passage A

A. lower, because vapor pressure of briny water is higher than the vapor pressure of pure water

B. Higer, because the vapor pressure of briny water is lower than vapor pressure of pure water

C. lower, because the vapor pressure of briny water is lower than the vapor pressure of prue water

D. higher, because the vapor pressure of briny water is higher than vapor pressure of pure water.

Answer: B

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equillibrium partial pressure formula

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Kp= (product)^m/(reactant)^n

8= x/(0.5)²

x= 2 atm

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Ideal gas vs deviation (conditions)

Ideal gas

High temp

low pressure

low molecular volume

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Answer: C

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Charles law

direct relationship exists between Temp (in kelvin) and volume

V1/T1=V2/T2

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Boyle’s law

inverse relationship between volume and pressure

P1V1=P2V2

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is it greater or less than 500ml? and which law says so

Charles’s law

V1/T1=V2/T2

500/293=V2/310

so increasing T2 increases V2, V2 is greater than 500 mL

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Passage B

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Passage B

A. Both metal sample and apparatus experience an increase in entropy, resulting in an overal increase in entropy within the system

B. The entropy of the metal sampel decreases, but the entropu of the apparatus icnreases by greater amount, resulting in an overal increase in entropy within the system

C. The entropy of the mettal sample icnreases but the entropy of the apparatus decreases by a greater amount, resulting in an overal decrease in entropy within the system

Answer:B

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Passage B

100ml = 100 g

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heat capacity

amount of heat required to raise the temp of the entire smaple by 1ºC

context formula: q= CT (q=CAT)

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specific heat capcity

amount of heat required to raise the temp of 1 gram of substance by 1ºC

q=mCT (q=mCAT)

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Passage B

fomula q= CT for heat capacity (not q=MCAT— which is for specific heat capacity)

Note: -qsample = qwater + qcalorimeter

rearrange: qcal= -qwater-qsample

q/T= C

-qwater-qsample/ (change in Temp of the system) = Ccal

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And based on this conclusion, what is the unknown metal?

Passage B

No, because the calorimeter is greater than 0 in experiment 2,this is shown in experiment 1 when the calorimetet absorbs a significant amount of heat. This means that the Cp is wrong.

Because of this, the unknown sample is Ti, because caloeimeter is >0, more than 2100 J of heat is released by the metal, this means the specific heat capacity is greater than the 0.42

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Answer: A

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Dalton’s law of partial pressure

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dimensional analysis to figure out the torr of other gas and add them the sum

0.4 (Co2) + 0.2 + 0.2 ( N2 and H2O)= 0.8 torr

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effect of temperature on the quilibrium constant

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decrease

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Note: T is in kelvin

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Passage C

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Passage C

(just solve) + what order of reaction?

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Passage C

solve for the rate question first to get (rate = k [P][RSH] (2nd order)

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Passage C

solve for the rate question first to get (rate = k [P][RSH] (2nd order)

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Passage C

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passage D

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Passage D

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Passage D

in lipid, aqueous, or gaseous environemnt?

Aqueous

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regarding formation, is it thermodynamically favorable under what temp?

Passage D

becomes more favorable at lower temps

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Passage D

so its 1,2 and 3

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regarding Keq…. what happens to it?

it will decrease

the reaction is exothermic based on the figures (change in H is negative) so heat is a product, adding heat shifts the reaction to the left (reactants)

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N2

because there are mroe moles of N2(g)

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Water is a constant

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273+ (-196) = 77

so 75-79K

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Passage E

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Passage E

1,3 only

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Passage E

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Passage E

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Volatlity

how easily a substance tansitions from liquid or solid into a vapor or gas

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Volatile substances

easily evaporate or sublime

Properties: high vapro pressure, low boiling points, weak IMF

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nonvolatile substances

do not readily evaporate

negligible vapor pressure (no pressure), high boiling points, strong IMF

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At any given temp, there is enough energy for some molcules in a liquid to overcome the IMF between molecules and escape into gas phase as vapors that are in equilibrium with liquid phase. The pressure resulting from these is called ______ pressure. When the temp is high enough for that specific pressure to equal the external pressure exerted by surroundings, the liiquid boils.

Vapor

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Passage E

Nonvolatile solutes dissolved in the liquid reduce the amount of surface area availbale for liquid molecules to occupy and escape into gas phase. Nonvolatile solute also increases the boiling temp

So removing and purification of the proteins would decrease the boiling point.

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mmHg and kPA and atm equivalence

101.3 kPa= 760 mmHg = 1 atm

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state function

thermodynamic system whose value depends only on the state of the system. As such, it is independent of the path taken

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Passage F

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Passage F

C

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Passage F

2 and 3 only

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1,2,3

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Passage G

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Passage G

Answer A

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passage G