Biological Molecules – Carbohydrates, Lipids, Proteins & Water

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These flashcards review key concepts on carbohydrates, lipids, proteins, and water properties for the upcoming exam, covering definitions, structures, bonding, and biological significance.

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85 Terms

1
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What is a macromolecule?

A very large molecule (≥1000 atoms) with high molecular mass, e.g., proteins, carbohydrates, lipids, nucleic acids.

2
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Define a polymer.

A macromolecule made of many repeating sub-units (monomers) joined by covalent bonds.

3
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Give one example of a macromolecule that is NOT a polymer and explain why.

Lipids; they are large but are built from glycerol and fatty acids, not a long chain of identical repeating monomers.

4
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Name the monomer of proteins.

Amino acid.

5
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Name the monomer of polysaccharides.

Monosaccharide.

6
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Name the monomer of nucleic acids.

Nucleotide.

7
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State the general formula of a monosaccharide.

CnH2nOn (or (CH2O)n).

8
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How many sugar units does an oligosaccharide contain?

3–10 sugar units.

9
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Formula of a disaccharide derived from two hexoses.

C12H22O11 (general form CnH2n−2On−1).

10
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General formula of a polysaccharide produced from glucose.

(C6H10O5)n (because each condensation removes H2O).

11
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List three common monosaccharides.

Glucose, fructose, galactose.

12
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Which monosaccharide exists as α- and β-anomers important in biology?

Glucose.

13
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Compare solubility of mono-, di- and polysaccharides.

Mono: highly soluble; Di: soluble but less than mono; Poly: insoluble (no osmotic effect).

14
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Why do monosaccharides taste sweet but starch does not?

Monosaccharides interact with sweet taste receptors; large polysaccharides cannot, so they are not sweet.

15
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What two monosaccharides form maltose?

Two α-glucose molecules.

16
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Type of glycosidic bond in maltose.

α(1→4) glycosidic bond.

17
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Monomers that form lactose.

β-galactose and β-glucose.

18
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Type of glycosidic bond in lactose.

β(1→4) glycosidic bond.

19
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Monomers that form sucrose.

α-glucose and β-fructose.

20
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Type of glycosidic bond in sucrose.

α(1→2) glycosidic bond (often written just 1→2).

21
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Define a reducing sugar.

A sugar with a free aldehyde or ketone group able to reduce Benedict’s reagent.

22
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Give one disaccharide that is non-reducing.

Sucrose.

23
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Why is sucrose non-reducing?

Its aldehyde/ketone groups are involved in the 1→2 glycosidic bond, so no free reducing end.

24
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Name the three main polysaccharides in plants and animals covered.

Starch, glycogen, cellulose.

25
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Which two polysaccharides make up starch?

Amylose and amylopectin.

26
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Bonding pattern in amylose.

α(1→4) glycosidic bonds only; unbranched helix.

27
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Bonding pattern in amylopectin.

α(1→4) main chain with α(1→6) branch points; branched.

28
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Why is amylose more compact than amylopectin?

It coils into a spiral helix with no branches, packing tightly.

29
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Give two advantages of branching in amylopectin.

(1) Many terminal glucose units for rapid hydrolysis, (2) more compact storage.

30
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State two reasons starch is an ideal storage molecule.

Insoluble (no osmotic effect) and highly compact store of chemical energy.

31
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Why is glycogen broken down faster than starch?

It is more highly branched, providing more ends for enzyme action.

32
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Where is glycogen stored in the human body?

Liver and muscle cells.

33
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State the three elements present in all lipids.

Carbon, hydrogen and oxygen (with relatively little oxygen).

34
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Why are lipids insoluble in water?

They are non-polar/hydrophobic and cannot form hydrogen bonds with water.

35
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Define a triglyceride.

A lipid formed by condensation of one glycerol molecule with three fatty acids, producing three ester bonds.

36
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What type of bond links fatty acids to glycerol?

Ester bond.

37
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Difference between saturated and unsaturated fatty acids regarding C=C bonds.

Saturated: no C=C double bonds; Unsaturated: one or more C=C double bonds.

38
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Why do unsaturated fatty acids have lower melting points?

Cis double bonds create kinks, preventing close packing, weakening hydrophobic interactions and lowering melting point.

39
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State two features shared by saturated and unsaturated fatty acids.

Both contain C, H, O and possess a carboxyl (COOH) group.

40
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Explain why fatty acids are poorly soluble in blood.

Their long non-polar hydrocarbon tails cannot form hydrogen bonds with polar water, so they aggregate.

41
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How are triglycerides transported in blood?

Attached to proteins as lipoproteins (LDL or HDL).

42
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What replaces one fatty acid in a phospholipid?

A phosphate group, creating a hydrophilic head.

43
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Number of ester bonds in a phospholipid.

Two ester bonds (because only two fatty acids).

44
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Compare triglycerides and phospholipids by presence of phosphate.

Triglycerides lack phosphate; phospholipids contain a phosphate group.

45
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Define lipoprotein.

A conjugated protein–lipid complex that transports triglycerides and cholesterol in blood.

46
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Role difference between LDL and HDL.

LDL delivers cholesterol to tissues/arteries; HDL removes excess cholesterol back to liver.

47
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General formula parts of an amino acid.

Central carbon attached to an amino group (NH2), carboxyl group (COOH), hydrogen, and variable R group.

48
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Primary protein structure definition.

Linear sequence of amino acids in a polypeptide, linked by peptide bonds.

49
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Type of bond characteristic of the primary structure.

Peptide bond (covalent, strong).

50
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Secondary structure definition.

Regular folding (α-helix or β-pleated sheet) stabilized by hydrogen bonds between C=O and N–H groups of backbone.

51
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Tertiary structure definition.

Overall 3-D folding of a single polypeptide due to interactions between R groups (H-bonds, ionic, disulfide, hydrophobic).

52
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Quaternary structure definition.

3-D arrangement of two or more polypeptide chains held by R-group interactions.

53
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List four types of R-group interactions in tertiary/quaternary structure.

Hydrogen bonds, ionic bonds, disulfide bridges, hydrophobic interactions.

54
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Which bond is strongest in proteins?

Peptide bond.

55
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Which interaction is weakest in proteins?

Hydrophobic interaction.

56
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Define a globular protein.

Compact, spherical protein with hydrophilic R groups facing outwards; soluble and metabolically active.

57
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Define a fibrous protein.

Long, parallel polypeptide chains forming insoluble structural proteins with limited tertiary structure.

58
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Give one example of a globular protein.

Enzyme (e.g., amylase) or haemoglobin.

59
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Give one example of a fibrous protein.

Collagen.

60
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Why are globular proteins water-soluble?

Hydrophilic R groups on surface form hydrogen bonds with water.

61
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Describe the basic structure of collagen.

Three helical polypeptides rich in glycine form a triple helix, molecules cross-linked into fibrils and fibres for tensile strength.

62
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Why is glycine at every third residue in collagen?

Its small size allows tight packing of the three helices.

63
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Describe the quaternary structure of haemoglobin.

Four polypeptides (2α, 2β) each with a haem prosthetic group containing Fe²⁺ that binds O2.

64
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Maximum number of O₂ molecules one haemoglobin can carry.

Four.

65
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What makes haemoglobin a conjugated protein?

Presence of non-protein haem groups (prosthetic groups).

66
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Define a glycoprotein and give one role.

Protein covalently linked to carbohydrate; functions as receptor, antigen, or transport protein.

67
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State two properties of water arising from hydrogen bonding important to life.

High specific heat capacity and high latent heat of vaporisation.

68
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Explain why water is an excellent solvent for ions.

Dipolar water molecules surround ions; Oδ− attracts cations, Hδ+ attracts anions, separating and dissolving them.

69
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How does high specific heat capacity benefit organisms?

Buffers temperature changes, maintaining stable internal and aquatic environments.

70
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Why does ice float on water?

Water becomes less dense below 4 °C as hydrogen bonds arrange molecules into an open lattice.

71
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Give one biological advantage of ice floating.

Insulates water beneath, preventing aquatic life from freezing.

72
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Define cohesion in water and state its effect.

Attraction between water molecules via hydrogen bonds creates high surface tension.

73
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State the heat required to raise 1 kg of water by 1 °C.

4,200 J (high specific heat capacity).

74
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Why is evaporation of sweat effective at cooling?

High latent heat of vaporisation means large heat energy is removed when water molecules escape.

75
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Explain how primary structure determines tertiary structure.

Sequence dictates R-group positions, which decide which bonds form, leading to specific folding.

76
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Which level(s) of protein structure involve disulfide bonds?

Tertiary and quaternary structures.

77
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What type of bond joins two cysteine residues?

Disulfide (covalent) bond.

78
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Why are fibrous proteins less sensitive to pH/temperature changes than globular proteins?

They lack extensive tertiary interactions that are easily disrupted; stability relies on strong cross-linking.

79
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List two reasons triglycerides provide more energy per gram than carbohydrates.

Higher proportion of C–H bonds and lower mass of water associated (they are hydrophobic).

80
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Name the bond formed in a condensation reaction between two amino acids.

Peptide bond.

81
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What is the melting point trend with increasing C=C bonds in fatty acids?

More double bonds ⇒ lower melting point.

82
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Explain the term ‘hydrophobic interaction’ in proteins.

Non-polar R groups cluster away from water, stabilising the protein’s interior.

83
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State two reasons starch does not affect cell water potential.

It is insoluble and has no significant osmotic effect.

84
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Why can amylopectin be hydrolysed faster than amylose?

Branch points offer multiple sites for enzyme attachment, speeding hydrolysis.

85
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Give two structural similarities between triglycerides and phospholipids.

Both contain glycerol backbone and ester bonds linking fatty acids.