3.2.3 Group 7 - the halogens

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Last updated 4:27 PM on 8/24/26
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35 Terms

1
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What are the formulas, colours, physical states & electron configuration of the first 4 halogens?

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What is the trend in boiling point down group 7?

Increases:

  • the strength of the Van der Waals forces increases as the size & relative mass of the molecules increases → this trend is shown in the changes of physical state from fluorine (gas) to iodine (solid)


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What is the definition of electronegativity?

The ability for an atom to attract electrons towards itself in a covalent bond

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What is the trend in electronegativity down group 7?

Decreases:

  • atoms gets larger, so the distance between the positive nucleus & the outer electrons increases, due to increased electron shielding

  • larger atoms attract electrons less than smaller ones as their outer electrons are further from the nucleus & are more shielded, as they have more inner electrons


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What will a more reactive halogen do in a displacement reaction?

A more reactive halogen will displace a less reactive halide ion from its compound in solution

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Are halogens more or less oxidising down group 7 & why?

Less oxidising:

  • when halogens react, they gain an electron (oxidising agents)

  • they get less reactive down the group, as the atoms become larger & the outer shells gets further from the nucleus


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<p>Complete this table of the displacement reactions</p>

Complete this table of the displacement reactions

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How can displacement reactions be used to help identify which halogen (or halide) is present in a solution?

Halide ions are colourless in solution, but when the halogen is displaced it shows a distinctive colour

  • bromine: orange

  • iodine: brown


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What would happen if chlorine is added to a solution containing bromide ions (e.g. potassium bromide) ?

Chlorine will displace the bromide ions, resulting in a colour change from colourless to orange:

  • the equation for this reaction is: Cl2 (aq) + 2KBr (aq) → 2KCl (aq) + Br2 (aq)

  • the ionic equation for this reaction is: Cl2 (aq) + 2Br- (aq) → 2Cl- (aq) + Br2 (aq)


<p>Chlorine will displace the bromide ions, resulting in a colour change from colourless to orange:</p><ul><li><p>the equation for this reaction is: Cl<sub>2</sub> (aq) + 2KBr (aq) → 2KCl (aq) + Br<sub>2</sub> (aq)</p></li><li><p>the ionic equation for this reaction is: Cl<sub>2</sub> (aq) + 2Br<sup>-</sup> (aq) → 2Cl<sup>-</sup> (aq) + Br<sub>2</sub> (aq)</p></li></ul><p></p>
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What would happen if chlorine is added to a solution of potassium iodide ions?

Chlorine will displace the iodide ions, resulting in a colour change from colourless to brown:

  • the equation for this reaction is: Cl2 (aq) + 2KI (aq) → 2KCl (aq) + I2 (aq)

  • the ionic equation for this reaction is: Cl2 (aq) + 2I- (aq) → 2Cl- (aq) + I2 (aq)


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What would happen if bromine is added to a solution of potassium iodide?

Bromine will displace the iodide ions, resulting in a colour change from colourless to brown:

  • the equation for the reaction is: Br2 (aq) + 2KI (aq) → 2KBr (aq) + I2 (aq)

  • the ionic reaction for the equation is: Br2 (aq) + 2I- (aq) → 2Br- (aq) + I2 (aq)


<p>Bromine will displace the iodide ions, resulting in a colour change from colourless to brown:</p><ul><li><p>the equation for the reaction is: Br<sub>2</sub> (aq) + 2KI (aq) → 2KBr (aq) + I<sub>2</sub> (aq)</p></li><li><p>the ionic reaction for the equation is: Br<sub>2</sub> (aq) + 2I<sup>-</sup> (aq) → 2Br<sup>-</sup> (aq) + I<sub>2</sub> (aq)</p></li></ul><p></p>
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Why is there no reaction if bromine water is added to a solution of chloride ions?

Chlorine is above bromine in group 7, so is more reactive & can’t be displaced

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Why won’t iodine displace neither chlorine nor bromine?

Iodine is below chlorine & bromine in group 7, so it’s less reactive than them & won’t displace either halide

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How is bleach made & what is the equation for the reaction?

Mix chlorine gas with cold, dilute NaOH solution at room temperature to form sodium chlorate(I) solution (NaClO):

  • 2NaOH(aq) + Cl2(g) → NaClO(aq) + NaCl(aq) + H2O(l)

    • chlorine is both oxidised & reduced (0 to +1 & -1), so this is a disproportionation reaction


<p>Mix chlorine gas with cold, dilute NaOH solution at room temperature to form sodium chlorate(I) solution (NaClO):</p><ul><li><p>2NaOH(aq) + Cl<sub>2</sub>(g) → <strong>NaClO(aq)</strong> + NaCl(aq) + H<sub>2</sub>O(l)</p><ul><li><p>chlorine is both oxidised &amp; reduced (0 to +1 &amp; -1), so this is a disproportionation reaction</p></li></ul></li></ul><p></p>
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What are some uses of sodium chlorate(I) solution (bleach) ?

  • Water treatment

  • Bleaching paper & fabrics

  • Cleaning agents


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What is the equation for the reaction of chlorine with water?

Cl2 + H2O ⇌ HCl + HClO

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How is water treated in the UK?

Chlorate(I) ions kill bacteria, so adding chlorine or a compound containing chlorate(I) ions is added to water to kill to make it safe to drink or swim in:

  • chlorine kills disease-causing microorganisms & some chlorine persists in the water, preventing reinfection further down the supply

  • it also prevents the growth of algae, removing bad tastes & smells, as well as removing discolouration caused by organic compounds


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What are the risks from using chlorine to treat water?

Accidents involving chlorine can be really serious, even fatal:

  • chlorine gas is very harmful if it’s breathed in → it irritates the respiratory system

  • liquid chlorine on the skin or eyes causes severe chemical burns

  • water contains a variety of organic compounds & chlorine reacts with these to form chlorinated hydrocarbons (e.g. chloromethane) → many of these chlorinated hydrocarbons are carcinogenic


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Why do the benefits of chlorinating drinking water outweigh its toxic effects?

The risk of not chlorinating water could lead to a cholera epidemic, which could kill thousands of people

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Why are halide ions reducing agents?

They lose an electron in reactions, becoming oxidised themselves & reduce something else

  • how easy it is for a halide ion to lose an electron depends on the attraction between the nucleus & the outer electrons


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What is the trend in the reducing ability down group 7?

Increases:

  • as you go down group 7, the attraction gets weaker as the ions get bigger, so the electrons are further away from the positive nucleus

  • there are extra inner electron shells too, so there’s a greater shielding effect


<p><strong>Increases:</strong></p><ul><li><p>as you go down group 7, the attraction gets weaker as the ions get bigger, so the electrons are further away from the positive nucleus</p></li><li><p>there are extra inner electron shells too, so there’s a greater shielding effect</p></li></ul><p></p>
22
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What are the equations to show how:

  • all the halides react with concentrated H2SO4

  • how only bromide & iodide react with concentrated H2SO4

  • how only iodide reacts (as it’s a strong enough reducing agent)



<p></p>
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<p>Complete this table</p>

Complete this table

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What is the method to test for halide ions?

  1. Add a small spatula of the halide salt to a test tube

  2. Dissolve the salt in dilute nitric acid (HNO3)

  3. Add a few drops of acidified silver nitrate (AgNO3) to make a silver halide

  4. Record any colour/precipitate

  5. Add some dilute ammonia & record any changes

  6. Add a few drops of concentrated ammonia & record any changes


<ol><li><p>Add a small spatula of the halide salt to a test tube</p></li><li><p>Dissolve the salt in dilute nitric acid (HNO<sub>3</sub>)</p></li><li><p>Add a few drops of acidified silver nitrate (AgNO<sub>3</sub>) to make a silver halide</p></li><li><p>Record any colour/precipitate</p></li><li><p>Add some dilute ammonia &amp; record any changes</p></li><li><p>Add a few drops of concentrated ammonia &amp; record any changes</p></li></ol><p></p>
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Why is nitric acid added when testing for halide ions?

Nitric acid reacts with any anions other than halides (e.g. carbonates) which could give a false positive result otherwise

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What are the observations in the tests for halide ions & what are the equations?

Fluoride ions:

  • soluble, so does not form a precipitate

Chloride ions:

  • white precipitate forms (silver chloride)

  • Ag+(aq) + Cl-(aq) → AgCl(s)

Bromide ions:

  • cream precipitate forms (silver bromide)

  • Ag+(aq) + Br-(aq) → AgBr(s)

Iodide ions:

  • yellow precipitate forms (silver iodide)

  • Ag+(aq) + I-(aq) → AgI(s)


<p><strong><u>Fluoride ions:</u></strong></p><ul><li><p>soluble, so does not form a precipitate</p></li></ul><p><strong><u>Chloride ions:</u></strong></p><ul><li><p>white precipitate forms (silver chloride)</p></li><li><p>Ag<sup>+</sup>(aq) + Cl<sup>-</sup>(aq) → AgCl(s)</p></li></ul><p><strong><u>Bromide ions:</u></strong></p><ul><li><p>cream precipitate forms (silver bromide)</p></li><li><p>Ag<sup>+</sup>(aq) + Br<sup>-</sup>(aq) → AgBr(s)</p></li></ul><p><strong><u>Iodide ions:</u></strong></p><ul><li><p>yellow precipitate forms (silver iodide)</p></li><li><p>Ag<sup>+</sup>(aq) + I<sup>-</sup>(aq) → AgI(s)</p></li></ul><p></p>
27
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What are the results of the silver halide precipitates when ammonia solution is added?

  • Chloride Cl- → precipitate dissolves in both dilute & concentrated NH3 (most soluble)

  • Bromide Br- → precipitate only dissolves in concentrated NH3

  • Iodide I- → precipitate is insoluble in concentrated NH3 (least soluble)


<ul><li><p>Chloride Cl<sup>-</sup> → precipitate dissolves in both dilute &amp; concentrated NH<sub>3 </sub>(most soluble)</p></li><li><p>Bromide Br<sup>- </sup>→ precipitate only dissolves in concentrated NH<sub>3</sub></p></li><li><p>Iodide I<sup>-</sup> → precipitate is insoluble in concentrated NH<sub>3 </sub>(least soluble)</p></li></ul><p></p>
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How are group 2 ions in a compound identified & what are the flame colours of Ca, Sr & Ba?

Flame test:

  1. Dip a nichrome wire loop in concentrated HCl to clean it

  2. Dip the wire loop into the unknown compound

  3. Hold the loop in the clear blue part of a Bunsen burner flame & observe the colour change in the flame

Flame colours:

  • Calcium, Ca2+ → brick red

  • Strontium, Sr2+ → red

  • Barium, Ba2+ → pale green


<p><strong><u>Flame test:</u></strong></p><ol><li><p>Dip a nichrome wire loop in concentrated HCl to clean it</p></li><li><p>Dip the wire loop into the unknown compound</p></li><li><p>Hold the loop in the clear blue part of a Bunsen burner flame &amp; observe the colour change in the flame</p></li></ol><p><strong><u>Flame colours:</u></strong></p><ul><li><p>Calcium, Ca<sup>2+</sup> → brick red</p></li><li><p>Strontium, Sr<sup>2+</sup> → red</p></li><li><p>Barium, Ba<sup>2+</sup> → pale green</p></li></ul><p></p>
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How can dilute NaOH solution be used to identify group 2 ions?

  1. Add NaOH dropwise to a test tube containing the metal ion solution & observe the precipitate that forms (if there is one)

  2. Keep adding the NaOH until it is in excess & record any changes that are observed

(all start off as colourless solutions)

<ol><li><p>Add NaOH dropwise to a test tube containing the metal ion solution &amp; observe the precipitate that forms (if there is one)</p></li><li><p>Keep adding the NaOH until it is in excess &amp; record any changes that are observed</p></li></ol><p>(all start off as colourless solutions)</p>
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What is the method to test for ammonium ions (NH4+)?

  1. Ammonium ions can be tested for either in a solid or in solution by adding NaOH solution & warming gently

  2. If the compound contains ammonium ions, ammonia gas will be produced which can be tested with damp red litmus paper which turns blue


<ol><li><p><span style="line-height: 115%;">Ammonium ions can be tested for either in a solid or in solution by adding NaOH solution &amp; warming gently</span></p></li><li><p class="MsoNormal"><span style="line-height: 115%;">If the compound contains ammonium ions, ammonia gas will be produced which can be tested with damp red litmus paper which turns blue</span></p></li></ol><p></p>
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What is the method to test for hydroxide ions (OH-) ?

Hydroxide ions make solutions alkaline:

  1. use a pH indicator to test the unknown solution

  2. if a piece of red litmus paper is dipped into the solution & hydroxide ions are present, the paper will turn blue


<p>Hydroxide ions make solutions alkaline:</p><ol><li><p>use a pH indicator to test the unknown solution</p></li><li><p>if a piece of red litmus paper is dipped into the solution &amp; hydroxide ions are present, the paper will turn blue</p></li></ol><p></p>
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What is the method to test for carbonate ions (CO32-) ?

  1. Add dilute HCl acid to the unknown solution & if carbonate ions are present, the solution will fizz (effervescence)

  2. The carbonate ions react with the hydrogen ions in the acid to make carbon dioxide

    • CO32- (aq) + 2H+ (aq) → CO2 (g) + H2O (l)

  3. Carbon dioxide can be tested using limewater → bubble the gas through a test tube of limewater & if the limewater goes cloudy, the solution contains carbonate ions


<ol><li><p>Add dilute HCl acid to the unknown solution &amp; if carbonate ions are present, the solution will fizz (effervescence)</p></li><li><p>The carbonate ions react with the hydrogen ions in the acid to make carbon dioxide</p><ul><li><p>CO<sub>3</sub><sup>2- </sup>(aq) + 2H<sup>+</sup> (aq) → CO<sub>2</sub> (g) + H<sub>2</sub>O (l)</p></li></ul></li><li><p>Carbon dioxide can be tested using limewater → bubble the gas through a test tube of limewater &amp; if the limewater goes cloudy, the solution contains carbonate ions</p></li></ol><p></p>
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What is the method to test for sulfate ions (SO42-) ?

  1. Add a little dilute HCl to remove any carbonates which could precipitate out after adding barium chloride, giving a false positive result

  2. Add barium chloride solution, BaCl2 (aq)

  3. If a white precipitate of barium sulfate forms, the original compound contained a sulfate: Ba2+(aq) + SO42-(aq) → BaSO4(s)


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How do you balance half-equations?

  1. Write the species before & after a reaction

  2. Balance any atoms apart from oxygen & hydrogen

  3. Balance any oxygens with H2O

  4. Balance any hydrogens with H+ ions

  5. Balance charges with electrons (e-)


<ol><li><p>Write the species before &amp; after a reaction</p></li><li><p>Balance any atoms apart from oxygen &amp; hydrogen</p></li><li><p>Balance any oxygens with H<sub>2</sub>O</p></li><li><p>Balance any hydrogens with H<sup>+</sup> ions</p></li><li><p>Balance charges with electrons (e<sup>-</sup>)</p></li></ol><p></p>
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How do you combine half-equations to make a full ionic equation?

  1. Balance the electrons by finding lowest common multiple

  2. Times everything in both equations by that number

  3. Cancel out the electrons & combine the two equations


<ol><li><p>Balance the electrons by finding lowest common multiple</p></li><li><p>Times everything in both equations by that number</p></li><li><p>Cancel out the electrons &amp; combine the two equations</p></li></ol><p></p>