OCHEM EXAM ONE

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Last updated 5:06 PM on 9/18/26
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72 Terms

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methane

C H4

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ethane

C2 H6

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propane

C3 H8

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butane

C4 H10

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pentane

C5 H12

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hexane

C6 H14

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heptane

C7 H16

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octane

C8 H18

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nonane

C9 H20

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decane

C10 H22

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undecane

C11 H24

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dodecane

C12 H26

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eicosane

C20 H42

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<p></p>


isopropyl

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<p></p>


isobutyl

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<p></p>


secbutyl

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<p></p>


tertbutyl

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<p></p>


neopentyl

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principal quantum number

n = 1,2,3…

tells us how much ENERGY the orbital has (1s vs 2s)

describes how willing the electrons in that orbital are to leave

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angular momentum quantum number

l = 0→(n-1)

tells us the SHAPE of the orbital (s=0, p=1, d=2)

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magnetic quantum number

ml = -l → +l

tells us how many ORBITALS there are

  • n² = ml

  • 2l + 1 = ml


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nodes

nodes are where e- density = 0

orbitals have n-1 nodes

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planer node

2p orbital

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spherical node

3p orbital (consists of spherical and planar node)

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best lewis structure

formal charge = 0

if there has to be formal charges, lowest # is better

neg formal charge should be on most electroneg atom

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resonance structures

hybrid (combo of equally valid structures) will have partial bonds and partial charge

bond order = total bonds / attached atoms

charge = charge on each atom / # of atoms

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hybridization (VBT)

look @ molecule and count e- groups around the atom

  • bonds (single, double or triple) count as one, lone pairs are one


sp³ = tetrahedral - 109.5

sp² = trigonal planar = 120

sp = linear = 180


ex) CH4 = sp³ (bc C has 4 bonds)


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dihedral angle

angle btw atoms from rotating a plane

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major resonance structures

  • lone pair next to a pi bond

  • pos charge next to a pi bond

  • lone pair next to pos charge

  • pi bond btw 2 atoms w diff electronegativity


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molecular orbital theory (MO)

  • if e- sin waves add constructively, e- density will incr btw the nuclei (bond!)

  • if they add destructively, e- will decr btw the nucli (antibonding)


each bond (sigma or pi) has bonding and antibonding (*) orbitals

on energy level, antibonding is above bonding


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checking if molecule exists with MO

if the bond order from MO (#e in bonding - #e in antibonding)/2

is the same as the bond shown in the lewis structure, then molecule exists

if BO from MO = 0 then molecule doesnt exist

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paragmagnitism of O2

there are unpaired e- in the pi*2py orbital of O2, giving the paramagnietic (its affected by magnetic fields) properties to the molecule

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frontier molecular orbital (FMO)

for rxn to occur, reactants have to overcome a significant energy barrier to get products

energy barriers exist bc of transition state - stablization of TS can allow rxn to happen, otherwise TS is very large


HOMO - highest occupied orbital

LUMO - lowest unoccupied orbital


after drawing MO, you can determine HOMO and LUMO → can see flow of e- bc HOMO goes into LUMO (can determine nucleophile and electrophile)


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aliphatic hydrocarbons

alkanes, alkenes, alkynes

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aromatic hydrocarbons

hydrocarbons in a benzene ring

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formula for cycloalkanes vs unbranched alkane

cyclo: CnH2n

unbranched alkane: CnH2n+2

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constitutional isomer

diff compounds with the same molecular formula

  • differ in atom connectivity (structural isomers)


diff than resonance because single bonds are broken and no curved arrows can be drawn


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conformational isomers

rotation around a single bond = conformers

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staggered newman projection

staggered has a 60 degree dihedral angle

  • if the two largest groups are 180 apart: anti

  • if two largest groups are 60 apart: gauche

largest groups HAVE to be on diff carbons for there to be gauche/anti


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eclipsed newman projection

dihedral angle is 0

always has TORSIONAL strain

less stable than staggered

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steric strain

large functional groups close together

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nomenclature tips

  • same principle chain length = choose one with more substituents

  • if chains the same - number the chain so that the first point of diff is smallest number

    • 3,3,5 trimethylpentane vs 5,5,3 trimethylpentane

    • if numbers still the same - lower number goes to first alphabetical group

  • cyclo, neo iso = prefixes INCLUDED

  • if noncylcic carbon chain has more Cs than the ring = treat it as a subsitituent


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classification of carbons

primary carbon = bonded to 1 other carbon

secondary carbon = bonded to 2 other carbons

etc.

(classification of hydrogen depends on classification of the carbon it’s bonded to

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<p></p>


ether (-oxy , - ane)

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term image

epoxide (-ene oxide)

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term image

aldehyde (-al)

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term image

ketone (-one)

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term image

carboxylic acid (-aic acid)

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term image

ester (-yl , -oate)

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<p></p>


amide (-amide)

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term image

amine (-amine)

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term image

thiol

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phenyl group

benzene ring acting as a substituent

can be represented by Ph-

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alkyl groups

any alkane group as a substituent

can be represented by R

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highly subsituted rings

use Ar-

aromatic ring acting as a substituent

(Ph is a specific type of Ar)

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dotted vs solid lines

dotted = going AWAY

solid = coming TOWARDS

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trend btw carbons and boiling pt

More carbons → higher boiling point because larger molecules have stronger London dispersion forces.

More branching → lower boiling point because branching decreases surface area/contact between molecules

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melting pt

more symmetry = higher mp because the molecule can pack

even number of carbons = higher mp than odd number of carbons (when comparing adjacenty numbers)

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lewis acid

accepts e- pair

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lewis base

donates e- pair

nucleophile if it dontates e- pair to an atom thats NOT H

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bronstead acid

proton donor

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bronstead base

proton acceptor

always also a lewis base

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curved arrows for lewis acid/base

gores from lewis base to lewis acid

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strength of acid (pKa and Ka)

incr strength = DECR pka and INCR ka

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equilibria in acid-base rxns

side with weaker acid and weaker base is favored

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1) charge effect

pos charged compounds attract e- easier than neutral charged ones

pos charge makes compound more acidic

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2) element effect

stronger acid = acidic proton is attached to an element thats more electroneg OR larger radius

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3) hybridization effect

sp3 < sp2 < sp (incr acid strength)

sp is 50% s properties so therefore e-s are held closer to the nuecleus

want conj base to be more stable bc means smaller deltaG and therefore smaller pKa

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4) resonance effect

resonance stabilization of conj base makes it more acidic

so if theres resonance structures - molecule is more acidic than one without any

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5) polar effect

the more electronegative atoms = more partial pos charge to balance out a neg charge = stronger acid

  • these are electron-withdrawing groups

closer the electroneg group is to the acidic proton = greater effect on its acidity

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electron withdrawing group order of strength

O2N

(CH3)3N

N (triple bond) C

F

Cl

Br

I

CH3O

phenyl

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electron donating substituents

carboxy

trimethyl siyl

ethyl