L9: Game Theory II

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24 Terms

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Sequential game

  • Players take turns in making choices

  • Previous choices are known to players - still compete information!

  • Game represented as a tree (also called extensive form)

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Decision tree/extensive form

  • Each non-leaf node represents a decision point for some player

    • Non-terminal note: not an endpoint

    • Terminal node: indicates the game is over

  • Branches represents available choices/actions

  • We can change simultaneous games into sequential games

Utilities are known to both players —> means games are very strategic

<ul><li><p><span>Each non-leaf node represents a decision point for some player</span></p><ul><li><p><span>Non-terminal note: not an endpoint</span></p></li><li><p><span>Terminal node: indicates the game is over</span></p></li></ul></li><li><p><span>Branches represents available choices/actions</span></p></li><li><p><span>We can change simultaneous games into sequential games</span></p></li></ul><p><span>Utilities are known to both players —&gt; means games are very strategic</span></p>
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Extensive form example

  • Player A goes first, player B reacts to A

  • Both Nash equilibria (3, 9) and (2, l) are still there

  • What does player A play?

    • You compare the best options on both sides of tree

      • Aka (3,9) and (2,1)

  • Which one is now likely to occur?

    • If A plays U: what would B do? L9>8

    • If A plays D: what would B do? R 1 > 0

  • What is the equilibrium?

    • (U,L) is Nash equilibrium - only one in sequential games

<ul><li><p><span>Player A goes first, player B reacts to A</span></p></li><li><p><span>Both Nash equilibria (3, 9) and (2, l) are still there</span></p></li><li><p><span>What does player A play?</span></p><ul><li><p><span>You compare the best options on both sides of tree</span></p><ul><li><p><span>Aka (3,9) and (2,1)</span></p></li></ul></li></ul></li><li><p><span>Which one is now likely to occur?</span></p><ul><li><p><span>If A plays U: what would B do? L9&gt;8</span></p></li><li><p><span>If A plays D: what would B do? R 1 &gt; 0</span></p></li></ul></li><li><p><span>What is the equilibrium?</span></p><ul><li><p><span>(U,L) is Nash equilibrium - only one in sequential games</span></p></li></ul></li></ul><p></p>
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Subgame Perfect Equilibria

  • Not all Nash equilibria are sensible in extensive form games

  • Players maximize their rewards based off what they can still obtain, not what they could have obtained

  • Subgame perfect equilibrium refines the concept of nash equilibrium accordingly

    • Sub game: if we make the equilibrium, we have to make sure is credible (it is reasonable)

      • Need to chip tree down in different games

    • Perfect: by looking at the sub game, we ensure that the threat is credible

    • Equilibrium: no one has the incentive to change their moves

  • So, in sequential games we try to rule out threats which are not credible

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How to find the subgame perfect equilibria

  • Chopping down the tree in different subgames

  • A profile of strategies in an extensive form game is a Subgame Perfect Nash equilibrium (SPNE) if it induces a Nash equilibrium in every subgame

    • Start with smaller circles and go bigger —> each little branch, then what is the best between the little branch, then what is the best for the whole tree

<ul><li><p><span>Chopping down the tree in different subgames</span></p></li><li><p><span>A profile of strategies in an extensive form game is a Subgame Perfect Nash equilibrium (SPNE) if it induces a Nash equilibrium in every subgame</span></p><ul><li><p><span>Start with smaller circles and go bigger —&gt; each little branch, then what is the best between the little branch, then what is the best for the whole tree</span></p></li></ul></li></ul><p></p>
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Escalation game background

  • Two states thinking about going to war with each other or not...

    • State I: accept the status quo or threatens

    • State 2: can responded concede or escalate the conflict

    • State I: can give up or go to war

  • To find equilibria: start at the end and move backwards

    • Backward induction

<ul><li><p><span>Two states thinking about going to war with each other or not...</span></p><ul><li><p><span>State I: accept the status quo or threatens</span></p></li><li><p><span>State 2: can responded concede or escalate the conflict</span></p></li><li><p><span>State I: can give up or go to war</span></p></li></ul></li><li><p>To find equilibria: start at the end and move backwards </p><ul><li><p><strong>Backward induction </strong></p></li></ul></li></ul><p></p>
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Escalation game equilibria

  • Back to the initial tree (minus some branches)

  • We know:

    • State I prefers war over give up

    • State 2 prefers to escalate over concede

  • All redundant branches are no longer in the picture

    • (-1, -1)

  • What is the best plan of action for State 1? Why?

    • State 1 → Accept: 0 > -1

  • What is the Subgame Perfect Equilibrium (SPE)?

    • (war accept, escalate) OR (war, accept)

      • War, accept notice of state 1 and (escalate) is choice of state 2

      • State 1 chooses to accept only bc they know that otherwise they know they will end up in war 

*SPE Looks at the path to Nash equilibrium and what happens after

<ul><li><p><span>Back to the initial tree (minus some branches)</span></p></li><li><p><span>We know:</span></p><ul><li><p><span>State I prefers war over give up</span></p></li><li><p><span>State 2 prefers to escalate over concede</span></p></li></ul></li><li><p><span>All redundant branches are no longer </span>in the picture</p><ul><li><p><span>(-1, -1)</span></p></li></ul></li><li><p><span>What is the best plan of action for State 1? Why? </span></p><ul><li><p><span>State 1 → Accept: 0 &gt; -1</span></p></li></ul></li><li><p><span>What is the Subgame Perfect Equilibrium (SPE)?</span></p><ul><li><p><span>(war accept, escalate) OR (war, accept)</span></p><ul><li><p><span>War, accept notice of state 1 and (escalate) is choice of state 2</span></p></li><li><p><span>State 1 chooses to accept only bc they know that otherwise they know they will end up in war&nbsp;</span></p></li></ul></li></ul></li></ul><p>*<span>SPE Looks at the path to Nash equilibrium and what happens after</span></p><p></p>
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Subgame perfect equilibria: details

  • A subgame perfect equilibrium is a complete (!) and contingent plan of action

    • It must state what happens on and off the equilibrium path of the game

    • Just mentioning accept, does not tell us WHY state 1 accepts

    • It is only rational in connection to the moves and actions of the other state

      • Especially if you have this weird branch (longer than the other)

  • It is important to note that all subgame perfect equilibria are Nash equilibria

    • Since backward induction ensures that each player will play his or her best option at each node, the resulting strategies will correspond to a Nash equilibrium

  • In other words:A profile of strategies in an extensive form game is a Subgame Perfect Nash Equilibrium (SPNE) if it induces a Nash equilibrium in every subgame

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Example: weird branch

C = weird branch —> think omg something happens (threat)

  • Green = NE of each sub game

  • Red = SPE

SPE = (C, H L)

  • Player 1 only play C in light of threat of H and L

<p><span>C = weird branch —&gt; think omg something happens (threat)</span></p><ul><li><p><span style="color: green">Green</span><span> = NE of each sub game</span></p></li><li><p><span style="color: red">Red</span><span> = SPE</span></p></li></ul><p><span>SPE = (C, H L)</span></p><ul><li><p><span>Player 1 only play C in light of threat of H and L</span></p></li></ul><p></p>
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Mixed strategy Nash equilibria

exists in a strategic game, when the player does not choose one definite action, but rather, chooses according to a probability distribution over his actions

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Pure vs mixed strategies

Pure = assigned 100% probability to only plan

Mixed = assigns probability to a particular action

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Matching pennies example

  • Story:

    • You and your friend simultaneously reveal a penny

    • If both pennies show heads or both show tails, your friend must pay you
      $1

    • If one penny shows head and the other shows tail, you must pay your friend $1

  • What is the PSNE? There isn’t one

<ul><li><p><span>Story:</span></p><ul><li><p><span>You and your friend simultaneously reveal a penny</span></p></li><li><p><span>If both pennies show heads or both show tails, your friend must pay you<br>$1</span></p></li><li><p><span>If one penny shows head and the other shows tail, you must pay your friend $1</span></p></li></ul></li><li><p>What is the PSNE? <strong>There isn’t one </strong></p></li></ul><p></p>
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Matching pennies solution

  • The matching pennies game is a zero-sum game

  • No clear PSNE; there is always an incentives to change...

  • John Nash again contributed to the solution of these games:

  • If the game is finite (finite number of players and finite number of strategies) and there are no Pure Strategy Nash equilibrium, then there must be a Mixed Strategy Nash Equilibrium

  • It is possible to find a randomized mutual strategies that satisfy Nash Equilibrium requirements

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Mixed strategies

  • a probability distribution over two or more pure strategies

    • If mixtures are mutual best response, the set of strategies is a mixed strategy Nash equilibrium 

    • Assigns probability distribution over pure strategies

    • It is related to expected utility theory and lotteries

  • In MSNE, each player's probability distribution makes all other player's indifferent between their pure strategies (only true for 2 x 2 games)

    • Finding point where other player is indifferent to switching

  • That is, the utility of playing strategy I must equal the utility of playing strategy 2

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Mixed strategy critique

  • Randomization, central in mixed strategies, lacks behavioural support: seldom do people make their choices following a lottery

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How to calculate Mixed Strategy Nash Equilibrium (MSNE)

  1. Find the probability of each outcome to occur in equilibrium

  2. For each outcome, multiply the probability by a particular players payoff

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Example mixed strategy

  • Two players {A,B}

  • 4 actions: Up, Down, Left and Right

  • Are there any PSNE? No

  • Are there any MSNE?

    • If there is no PSNE there is for SURE a MSNE

<ul><li><p><span>Two players {A,B}</span></p></li><li><p><span>4 actions: Up, Down, Left and Right</span></p></li><li><p><span>Are there any PSNE? <strong>No</strong></span></p></li><li><p><span>Are there any MSNE?</span></p><ul><li><p>If there is no PSNE there is for <span style="color: red">SURE</span> a MSNE </p></li></ul></li></ul><p></p>
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Step 0: player A

  • Instead of playing U or D, Player A selects a probability distribution (πu, l- πu), meaning that with a probability (πu) player A will play Up and with a probability (I - πu) will play Down

    • π = p (probability)

  • Player A is mixing over the pure strategies Up and Down

  • The probability distribution (πu, I- πu) is a mixed strategy for player A

<ul><li><p><span>Instead of playing U or D, Player A selects a probability distribution (πu, l- πu), meaning that with a probability (πu) player A will play Up and with a probability (I - πu) will play Down</span></p><ul><li><p><span>π = p (probability)</span></p></li></ul></li><li><p><span>Player A is mixing over the pure strategies Up and Down</span></p></li><li><p><span>The probability distribution (πu, I- πu) is a mixed strategy for player A</span></p></li></ul><p></p>
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Step 0: player B

  • instead of playing L or R, Player B selects a probability distribution (πL, 1 - πL), meaning that with a probability (πL) Player B will play Left and with a probability (1 - πL) will play Right

  • Player B is mixing over the pure strategies Left and Right

  • The probability distribution (πL, 1 - πL) is a mixed strategy for Player B

<ul><li><p><span>instead of playing L or R, Player B selects a probability distribution (</span>πL<span>, 1 - </span>π<span>L), meaning that with a probability (</span>πL<span>) Player B will play Left and with a probability (1 - </span>πL<span>) will play Right</span></p></li><li><p><span>Player B is mixing over the pure strategies Left and Right</span></p></li><li><p><span>The probability distribution (</span>πL, 1 - πL<span>) is a mixed strategy for Player B</span></p></li></ul><p></p>
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Step 1: solving for B

  • What is the utility of Player B for just going to the Left?

    • Utility of Player B depends on the probability of Player A to go Up/Down → Getting 2 or 5 in utility

    • If B plays left, her expected payoff is: 2pU + 5(1 - pU)

      • Utility X probability

  • What is the utility of Player B for just going to the Right?

    • Utility of Player 2 depends on the probability of Player A to go Up/Down → Getting 4 or 2 in utility

      • If B plays right, her expected payoff is: 4pU + 2(1 - pU)

<ul><li><p><span>What is the utility of Player B for just going to the Left?</span></p><ul><li><p><span>Utility of Player B depends on the probability of Player A to go Up/Down → Getting 2 or 5 in utility</span></p></li><li><p><span style="color: red">If B plays left, her expected payoff is: 2pU + 5(1 - pU)</span></p><ul><li><p><span>Utility X probability</span></p></li></ul></li></ul></li><li><p><span>What is the utility of Player B for just going to the Right?</span></p><ul><li><p><span>Utility of Player 2 depends on the probability of Player A to go Up/Down → Getting 4 or 2 in utility</span></p><ul><li><p><span style="color: green">If B plays right, her expected payoff is: 4pU + 2(1 - pU)</span></p></li></ul></li></ul></li></ul><p></p>
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Step 2: solving for B indifferent

  • For a mixed strategy for a player, we need to see some probability distribution that makes the other player indifferent between his or her pure strategies:

    • If 2πu + 5(1- πu) > 4πu + 2(1- πu), player B would play Left

    • If 2mu + 5(1-πu) < 4πu + 2(1 - πu), player B would play Right

  • So, for there to be an equilibrium, B must be indifferent between playing Left or Right i.e., we need to determine the threshold

    • 2πu + 5(1-πu) = 4πu + 2(1 - πu)

  • Can you solve this?

    • 2πy +5 - 5πu = 4πu +2-2πu

    • 3πu+5=2πu+2

    • - 5πu= -3

    • πu = 3/5

      • Up

    • 1 - πu = 2/5

      • Down

<ul><li><p>For a mixed strategy for a player, we need to see some probability distribution that makes the other player indifferent between his or her pure strategies:</p><ul><li><p>If <span style="color: red">2πu + 5(1- πu)</span> &gt; <span style="color: green">4πu + 2(1- πu)</span>, player B would play Left</p></li><li><p>If <span style="color: red">2mu + 5(1-πu)</span> &lt; <span style="color: green">4πu + 2(1 - πu)</span>, player B would play Right</p></li></ul></li><li><p>So, for there to be an equilibrium, B must be <strong>indifferent</strong> between playing Left or Right i.e., we need to determine the threshold</p><ul><li><p><span style="color: red">2πu + 5(1-πu)</span> = <span style="color: green">4πu + 2(1 - πu)</span></p></li></ul></li><li><p>Can you solve this?</p><ul><li><p>2πy +5 - 5πu = 4πu +2-2πu</p></li><li><p>3πu+5=2πu+2</p></li><li><p>- 5πu= -3</p></li><li><p><strong>πu = 3/5</strong></p><ul><li><p>Up</p></li></ul></li><li><p><strong>1 - πu = 2/5</strong></p><ul><li><p>Down</p></li></ul></li></ul></li></ul><p></p>
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Step 3: solving for A

  • What is the utility of Player A for just playing Up?

    • Utility of Player A depends on the probability of Player B to go Left/Right

    • If A plays Up, his expected payoff is: 1πL+ 0(1-πl) = πL

  • What is the utility of Player A for just playing Down?

    • Utility of Player A depends on the probability of Player B to go Left/Right

    • If A plays Down, his expected payoff is : 0πL + 3(1-πL) = 3(1-πL)

<ul><li><p>What is the utility of Player A for just playing Up?</p><ul><li><p>Utility of Player A depends on the probability of Player B to go Left/Right</p></li><li><p><span style="color: red">If A plays Up, his expected payoff is: 1πL+ 0(1-πl) = πL</span></p></li></ul></li><li><p>What is the utility of Player A for just playing Down?</p><ul><li><p>Utility of Player A depends on the probability of Player B to go Left/Right</p></li><li><p><span style="color: green">If A plays Down, his expected payoff is : 0πL + 3(1-πL) =  3(1-πL)</span></p></li></ul></li></ul><p></p>
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Step 4: solving for A indifferent

  • So, for there to be an equilibrium, A must be indifferent between playing Up or Down i.e., we need to determine the threshold

    • πL = 3(1-πL)

  • Can you solve this?

    • πL = 3 - 3πL

    • 4πL = 3

    • πL =3,142 L 3/4

    • πL= 3/4

      • Left

    • 1 - πL = 1/4

      • Right

<ul><li><p>So, for there to be an equilibrium, A must be indifferent between playing Up or Down i.e., we need to determine the threshold</p><ul><li><p><span style="color: red">πL</span> = <span style="color: green">3(1-πL)</span></p></li></ul></li><li><p>Can you solve this?</p><ul><li><p>πL = 3 - 3πL</p></li><li><p>4πL = 3</p></li><li><p>πL =3,142 L 3/4</p></li><li><p><strong>πL= 3/4</strong></p><ul><li><p>Left</p></li></ul></li><li><p><strong>1 - πL = 1/4</strong></p><ul><li><p>Right</p></li></ul></li></ul></li></ul><p></p>
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Step 5: MSNE

MSNE = (3/5, 2/5) (3/4, 1/4)

Alternative writing

  • MSNE = (3/5U, 3/4L)

  • MSNE = (3/5, 3/4)

NOTE: always write in fractions

<p>MSNE = (3/5, 2/5) (3/4, 1/4)</p><p>Alternative writing </p><ul><li><p>MSNE = (3/5U, 3/4L)</p></li><li><p>MSNE = (3/5, 3/4)</p></li></ul><p>NOTE: always write in fractions </p><p></p>