DE Chemistry II Lecture for Science Majors Test 2

studied byStudied by 0 people
0.0(0)
learn
LearnA personalized and smart learning plan
exam
Practice TestTake a test on your terms and definitions
spaced repetition
Spaced RepetitionScientifically backed study method
heart puzzle
Matching GameHow quick can you match all your cards?
flashcards
FlashcardsStudy terms and definitions

1 / 53

encourage image

There's no tags or description

Looks like no one added any tags here yet for you.

54 Terms

1

Which has the smallest entropy?

C (diamond)

New cards
2

Which statement is correct?

when Q = K then triangleG = 0

New cards
3

The most probable state is the one with the ________.

largest number of possible arrangements

New cards
4

Which substances are included in the equilibrium constant expression, Kc?

only gases and dissolved substances

New cards
5

Which, if any, of the following processes is spontaneous under the specified conditions?

CO2(s) → CO2(g) at 0*C, 1 atm pressure

New cards
6

HI decomposes into its elements according to second-order kinetics. How long will it take for the concentration to decrease to 1.25 M from an initial concentration of 2.25 M? The rate constant, k, equals 1.6 × 10−3 M−1hr−1.

 

2 HI(g)  H2(g) + I2(g)

2.2 × 10² hours

New cards
7

A substance, A, decomposes according to zero-order kinetics from an initial concentration of 1.90 M to 0.420 M in 85.2 seconds. What is the value of the rate constant, k?

1.74 × 10−2 M∙s−1

New cards
8

HI decomposes into its elements according to second-order kinetics. What concentration of HI remains from an initial concentration of 2.30 M after 4.5 hours? The rate constant, k, equals 1.6 × 10−3 M−1s−1.

 

2 HI(g)  H2(g) + I2(g

2.26 M

New cards
9

Which expression best defines the rate of the reaction with respect to CO2, given the following reaction?

 

C3H8(g) + 5 O2(g)  3 CO2(g) + 4 H2O(g

knowt flashcard image
New cards
10

What is the rate of change of H2O if the rate of change of CO2 is 0.600 M/s?

 

C3H8(g) + 5 O2(g)  3 CO2(g) + 4 H2O(g)

0.800 M/s

New cards
11

What are the units for the rate constant, k, for a first-order reaction?

s−1

New cards
12

Radioactive decay follows first-order kinetics. If sodium-24 has a half-life of 14.96 hours, what is its rate constant, k?

4.63 × 10−2 hr−1

New cards
13

Which equation shows the integrated rate law for a substance that reacts according to second-order kinetics?

knowt flashcard image
New cards
14

The reaction of NO and O3 reacts with second-order kinetics. If it takes 94 seconds for the concentration of NO to go from 3.00 M to 1.25 M, what is the rate constant, k?

 

NO(g) + O3(g)  NO2(g) + O2(g)

4.96 × 10-3 M−1∙s−1

New cards
15

A substance, Z, with an initial concentration of 1.75 M follows second-order kinetics and decays with a half-life of 6.8 minutes. What is the value of the rate constant, k?

8.4 × 10−2 M−1∙min−1

New cards
16

The rate law expresses the relationship between the concentrations of reactants and the rate of reaction.

 

Given the rate law, rate = k[A]2[B]2, the rate will increase by a factor of ____ when the concentration of A and B are both doubled.

Given the rate law, rate = k[A]2[B]2, the rate will increase by a factor of ____ when the concentration of A and B are both doubled.

16

New cards
17

A reaction has the general rate law: rate = k[A]2[B]2. What is the order with respect to A and what is the overall order of the reaction?

Second order with respect to A; fourth order overall

New cards
18

At equilibrium, both the forward reaction and the reverse reaction occur simultaneously and at the same rate. Since the rates are the same, the concentrations of the reactants and products do not change.

 

An equilibrium constant expression can be developed, which is a mathematical expression indicating the relationship between the reactants and the products.

 

The equilibrium concentrations can be substituted into the equilibrium expression to determine the equilibrium constant, K. The equilibrium constant can also be denoted as “K,” “Kc,” or “Keq.

 

 

What is the equilibrium constant, K, for the following reaction if the concentration of CO was measured to be 3.1 × 10-2 M, the concentration of O2 was measured to be 1.7 × 10-2 M, and CO2 was measured to be 1.452 × 10-1 M?

 

2 CO(g) + O2(g)  2 CO2(g)

K = 1.3 × 103

New cards
19

At equilibrium, both the forward reaction and the reverse reaction occur simultaneously and at the same rate. Since the rates are the same, the concentrations of the reactants and products do not change.

 

An equilibrium constant expression can be developed, which is a mathematical expression indicating the relationship between the reactants and the products.

 

The equilibrium concentrations can be substituted into the equilibrium expression to determine the equilibrium constant, K. The equilibrium constant can also be denoted as “K,” “Kc,” or “Keq.”

What is the concentration of CO if the concentration of Cl2 was measured to be 0.75 M, COCl2 was measured to be 2.21 M, and the equilibrium constant, K, is 5.3?

 

CO(g) + Cl2(g) ⇌ COCl2(g)

[CO] = 0.56 M

New cards
20

New cards
21
New cards
22
New cards
23
New cards
24
New cards
25
New cards
26
New cards
27
New cards
28
New cards
29
New cards
30
New cards
31
New cards
32
New cards
33
New cards
34
New cards
35
New cards
36
New cards
37
New cards
38
New cards
39
New cards
40
New cards
41
New cards
42
New cards
43
New cards
44
New cards
45
New cards
46
New cards
47
New cards
48
New cards
49
New cards
50
New cards
51
New cards
52
New cards
53
New cards
54
New cards
robot