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How do you balance chemical equations?
By adjusting the coefficients to ensure the same number of atoms on both sides.
What does the mole in an equation represent?
It represents the ratio of amounts of substances involved in the reaction.
How is the mole related to a balanced equation?
The coefficients in the equation represent the mole ratio of reactants to products.
If 2 moles of hydrogen react with 1 mole of oxygen, what is the mole ratio?
The ratio is 2:1 (Hâ‚‚ : Oâ‚‚).
How can you calculate the moles of a product from a chemical equation?
Use the mole ratio from the balanced equation and the number of moles of the reactants.
What is the mole ratio of COâ‚‚ to Hâ‚‚O in the combustion of methane?
The ratio is 1:2 (CH₄ + 2O₂ → CO₂ + 2H₂O).
How do you use a chemical equation to determine the limiting reactant?
By calculating which reactant runs out first based on the mole ratio and amounts given.
What do you do if the number of moles of a reactant is not given in a reaction?
You can use molar masses to calculate the number of moles from the mass of reactants.
How does the mole ratio help in stoichiometry?
It allows the calculation of the amounts of products formed from given amounts of reactants.
What is the mole of oxygen required to react with 4 moles of hydrogen in the formation of water?
2 moles of oxygen are required for 4 moles of hydrogen (2:1 ratio).
How can you use the mole ratio to determine excess reactants?
By comparing the available amount of reactants with the ratios in the balanced equation.
How do you calculate the moles of carbon dioxide produced in a reaction?
Use the mole ratio from the equation and the amount of reactant involved.
How can you use molar volume to calculate moles of a gas at STP?
Divide the volume of gas by 22.4 dmÂł (molar volume) to calculate moles.
How would you use a balanced equation to calculate theoretical yield?
Use the mole ratios to determine how much product should be formed, given the amount of reactants.
What happens when the mole ratio in an equation is not balanced correctly?
The equation no longer represents the correct proportions of reactants and products.