momentum + Newtons laws

- 2 light gates

-gate measures the time taken for the trolley to pass

-speed = distance travelled/time

force is directly proportional to the rate of change in momentum

-sphere A exerts force on sphere B

According to newtons 3rd law sphere b will apply an equal and opposite reaction

-this force opposes the motion of sphere A

-sphere A decelerates according to N2

-resultant force on sphere B accelerates B

-the forces on spheres are equal so change in momentum are same for each sphere

-increases time to come to rest

-decreases rate of change in momentum

-decreases force

whats meant by centre of gravity

where weight seems to be acting from

newtons laws

an object will remain at rest or continue moving at a constant speed and direction unless acted upon by an external force

F=MA

every action has an equal and opposite reaction

f=ma a=Δv/Δt v²=u²+2as

√2 ×9.81 × 1.6

5.6/0.90

45 x 6.2 = 280

p=mv

66+52=118

118 × 5.6=660.8

660.8=(52 × 7.5) x 66v

660-330/66=v

v=4.1

p=mv

1500+1200=2700

-

f=Δmv/t

0.06 × 25 / 0.09=37.5

glider1 exerts force on glider 2 according to N3

glider 2 exerts an equal and opposite force on 1

there is now a resultant force on 1

1 accelerates according to N1

-collision on ice so minimal frictional force

-momentum is conserved in collision

-momentum of A before = momentum of B after

-stone A must be at rest after the collision

-all of the kinetic energy of stone A must have transferred to B

-Kinetic energy is conserved in an elastic collision

-according to N3 pair of forces must act on different bodies

-gravity is not a good description of force

-the lift of the plane should be paired with the push of the plane on the air

-if vertical resultant force is zero plane will not accelerate

-so plane would be at rest or moving at a uniform velocity vertically

-there must be some horizontal motion so plane cant be in same place

-magnet increases balls ke

-momentum is conserved in collision

-ke is conserved so so the last ball moves away with the same velocity

-rope is under tension

-team A exerts a force on rope and exerts a force on team A due to N3

-However force of rope on team is greater than frictional force for team A

-Team A now has a resultant force t the right

-Team A accelerates to the right due to N1 and N2

-because the frictional force between the ground and team B is larger

ek=e

e=mgh

ek=1/2xmxv²

31×9.81×0.13=39.53

39.53=½ x31x v²

√39.53×2/31=1.59

p=mv

1.59 × 31=49.5

v²=u²+2as

√v²-2as

√2×9.81×2.5