Work done by Forces, Work & KE, Conservation of KE, Work-Energy Theorem, Linear Momentum, Constant angular acceleration

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48 Terms

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Work done by force when force is constant
W = F(r)cos0
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work unit
Joule (J)

1 J = 1 N\*m
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work can be
positive negative or zero
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if there is no displacement
there is no work no matter how large the force is
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if F and r are perpendicular (90)
then the force does no work
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positive work
theta less than 90 degrees
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zero work
theta is 90 degrees
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negative work
theta is greater than 90 and less than 270 degrees
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if multiple forces are acting on an object, the total work can be found by
adding up with individual works (Wtot=W1+W2+W3)

OR

using work equation using total force

Wtot = Ftot\*r\*cos0
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kinetic energy
the capacity of an object to do work based on its motion

KE=(1/2)mv^2
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work-energy theorem
Wtot = delta KE = (1/2mvf^2)-(1/2mvi^2)
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force not constant
Us or Ug
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finding work graphically
area under a force vs displacement graph
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Hookes law
Fsp = -kx

|Fsp| = k|x|
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units of spring constant
N/m
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work done by springs
Wsp = -(1/2kxf^2)-(1/2kxi^2)
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conservative force
work done depends on the initial and final positions and does not depend on the path taken
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conservative force examples
gravitational force

elastic force
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nonconservative force examples
friction

applied force

push & pull action

tension force
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the work done by gravity depends only on
the height of the starting and ending points (delta y)
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for conservative forces it is always
possible to define a potential energy
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the change in potential energy is equal
to the negative of the work done by a conservative force
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delta U
\-Wcons
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Ug
mgy
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Us
(1/2)kx^2
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if only conservative forces do work
the total mechanical energy remains constant

Emech before = Emech after

Emech = K + U = 0
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conservation of mechanical energy
if only conservative forces do work, then the total mechanical energy is constant (zero)
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work when friction is involved
Wtot= Wcons + Wnoncons
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if non-conservative forces do work on the system
Emech = K + U = Wnoncons
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power
the rate at which work is being done on a system
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power unit
1 J/s = 1 Watt (W)
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power formulas
P = dw/dt

Pavg = work/ time
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two types of momentum
linear momentum and angular momentum
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linear momentum
p =mv

units: kg\*m/s
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momentum
vector quantity

\-multiple nonzero can add up to zero
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kinetic energy
non-negative scalar quantity

K > 0
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momentum and KE
K = p^2/2m
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momentum and newtons second law
Fnet = dp/dt
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I net
delta p (change in momentum)
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impulse momentum theorem
F(delta t) = mvf - mvi
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law of conservation of momentum
the total momentum of an isolated system is constant
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impulse approximation
collisions and explosions are so brief they impart a comparatively insignificant impulse
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perfectly elastic
two objects bounce after the collision

move separately

momentum & KE conserved
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inelastic collision
two objects deform during collision so KE decreases

move separately after the collision

momentum conserved
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perfectly inelastic
two objects stick together after collision

finals velocities are the same

momentum conserved
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explosions
one big object becomes multiple smaller ones

KE not conserved

momentum conserved
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elastic collision equation
m1v1 + m2v2 = m1v1 + m2v2
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inelastic collision equation
m1v1 + m2v2 = (m1+m2)v3