25 Centres of mass and stability

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21 Terms

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moment =

force x distance

where distance is the perpendicular distance from the line of action of the force from the point that moments are being taken from

<p>force x distance</p><p>where distance is the perpendicular distance from the line of action of the force from the point that moments are being taken from</p>
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torque

another word for moment/turing force

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what can be said about moments if a system of forces is in equilibrium

the resultaint moment taken about any point is 0

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lamina

a flat thin objecct with a negliable thinckness - model as a 2d shape (kinda like a shop sign)

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if the line of action of a force passes through point a what do you do when you are calculation the moment around A

ignore that force

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units for moments

Nm

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rotational equilibrium

anitclockwise moments = clockwise moments

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a pivot

a fixed point that an object can rotate about

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a couple consists of

two parallel forces that are equal in magnitude, opposite in direction and do not share a line of action

<p><strong><em>two parallel forces that are equal in magnitude</em></strong><span>, opposite in direction and do not share a line of action</span></p>
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what is the moment of a couple about any point always equal to

F x d

where d is the perpendicular distance between the line of action of the two forces

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forces that cause rotation without translation are known as

couples

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Cantilever force diagram

Y is vertical reaction force

X is horizontal reaction force

M is the moment due to the couple at the cantilever

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Center of mass

The single point at which we can treat the entire mass of the object as acting on

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Centre of mass for a system of particles

X = (∑(mₙ x xₙ))/∑mₙ

Y = (∑(mₙ x yₙ))/∑mₙ

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Center of mass for a right angled triangle

X = 1/3 x base

Y = 1/3 x height

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Centre of mass for a isocolies

X = 0.5 x base

Y = 1/3 x height

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A uniform lamina has

Area and mass but no thickness

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Center of mass of a composite body with an area removed

as normal but the area removed should be considered as negative

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Centre of mass for a uniform albina with an area bounded by the curve y = f(x)

X = ∫xy dx / ∫y dx

Y = ∫ ½y² dx / ∫y dx

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Centre of mass for a uniform solid formed by rotating the area between the curve and the x axis by 360

X = ∫xy² dx / ∫y² dx

Y = 0

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Note about using integration to find the CoM

The density p should be included in a proof but will cancel out

π should be included if it is a volume of revolution proof but will also cancel