BIOCHEM Exam 2

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Includes lectures 5-11

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146 Terms

1
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What is the correct order of steps for protein purification?

  1. Break open the cell 2. Centrifugation 3. Column chromatography 4. Gel electrophoresis 5. Analyze

2
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What is ATCase regulation?

High amount of CTP product inhibits ATCase at

3
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To study enzyme activity, structure, or sequence, a protein must be:

Completely isolated and purified

4
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Purity of the isolated protein is analyzed by:

SDS-PAGE

5
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Low-speed centrifugation removes:

Large debris, nuclei, cell walls

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After centrifugation, the supernatant is:

The liquid containing soluble proteins

7
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High-speed centrifugation separates:

Organelles (mitochondria, lysosomes)

8
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Very high-speed centrifugation removes:

Ribosomes, membranes, small vesicles

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The stationary phase is:

A solid material proteins stick to

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The mobile phase is:

A liquid that carries proteins through the column

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Chromatography separates molecules based on their:

Different interactions with the stationary phase

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Column chromatography steps include:

Load column → add sample → elute → collect fractions

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Size-exclusion chromatography separates proteins based on:

Size (molecular weight)

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In gel filtration:

Large proteins elute first

15
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Ion-exchange chromatography separates proteins based on:

Charge

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The two main types of ion exchangers are:

Cation-exchange & anion-exchange

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Proteins are eluted using:

Increasing amounts of competing ions (salt gradient)

18
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SDS gives proteins a:

Negative uniform charge

19
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SDS-PAGE gels are made from:

Polyacrylamide

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In SDS-PAGE, proteins are separated based on:

Size

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Negatively charged proteins in SDS-PAGE move toward:

Anode (+)

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In SDS-PAGE:

Small proteins move fastest

23
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Trypsin cleaves on the C-terminal side of:

Lys & Arg

24
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Chymotrypsin cleaves on the C-terminal side of:

Trp, Tyr, Phe

25
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Cyanogen Bromide cleaves proteins:

At methionine residues

26
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Edman degradation determines:

N-terminal amino acid sequence

27
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Edman degradation uses:

Phenylisothiocyanate (PITC)

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Each Edman Degradation cycle removes:

The N-terminal amino acid

29
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A catalyst increases reaction ________ without being ________.

speed; used up

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Catalysis refers to the:

acceleration of a reaction

31
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Without enzymes, most biochemical reactions would:

Occur too slowly to sustain life

32
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ΔG° describes:

Free energy change from reactants → products

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ΔG°‡ is the:

Activation energy barrier

34
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The transition state represents:

The highest-energy intermediate

35
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Enzymes work by:

Lowering ΔG‡

36
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Enzymes:

Do NOT affect ΔG°

37
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Glucose oxidation has ΔG° = –689 kcal/mol, meaning:

Reaction is spontaneous

38
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A substrate is:

A reactant that binds the enzyme to form a complex

39
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Active sites:

Contain unique amino acids specific for binding

40
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Enzyme–substrate interactions are primarily:

Weak noncovalent interactions

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The two major binding models are:

Induced-fit & lock-and-key

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Lock-and-key model fails to explain:

Enzyme conformational change

43
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Induced-fit is favored because:

It allows enzyme conformational change upon substrate binding

44
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A perfect lock-and-key fit would:

Make the ES complex too stable

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Once the substrate binds, the enzyme:

Converts ES → EP → E + P

46
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To measure enzyme kinetics, you vary:

[substrate]

47
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Km is:

[S] at ½ Vmax

48
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Low Km means:

High enzyme affinity

49
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Vmax is:

Maximum velocity when the enzyme is saturated

50
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Lineweaver-Burk plots are useful because they:

Convert hyperbolic Michaelic-Menten curves into a straight line

51
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On an Lineweaver-Burk plot:

y-intercept = 1/Vmax

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Km is obtained from:

–1/x-intercept

53
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A competitive inhibitor binds to:

Active site

54
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Competitive inhibitors:

Increase Km, unchanged Vmax

55
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Competitive inhibition can be overcome by:

adding more substrate

56
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Noncompetitive inhibitors bind:

At a site other than active site

57
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Noncompetitive inhibitors:

Lower Vmax, Km unchanged

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In noncompetitive inhibition:

Substrate can still bind, but enzyme is inactive

59
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Given that lines intersect at x-axis but have different y-intercepts, urea is:

Noncompetitive

60
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Enzymes in pathways are regulated mainly to:

Save energy and avoid wasteful reactions

61
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High-energy pathways must be regulated because they:

Are expensive in ATP

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Stopping unnecessary steps in a pathway:

Reduces wasted intermediates

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Which of the following is controlled by regulation?

Both

64
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A zymogen is a(n):

Inactive enzyme precursor

65
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Zymogens become active when they are:

Cleaved to change conformation

66
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Cofactors are small molecules that:

Are required for enzyme activity

67
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Which is a cofactor?

Both metal ions and coenzymes

68
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Phosphorylation is the covalent addition of:

a phosphate group (PO₄³⁻)

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Phosphorylation typically:

Causes conformational change and alters activity

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Which residues can be phosphorylated?

Ser, Thr, Tyr

71
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Kinases:

Add phosphates from ATP to proteins

72
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Feedback inhibition occurs when:

Products of a pathway inhibit an earlier enzyme

73
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Feedback inhibition:

Prevents waste and saves energy

74
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A high concentration of final product means:

No need for more product → pathway should shut down

75
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ATCase catalyzes a step in synthesis of:

CTP

76
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CTP is primarily used for:

RNA and DNA synthesis

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High CTP:

Inhibits ATCase

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If CTP inhibits ATCase, the whole pathway:

Turns off to conserve energy

79
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ATCase activity curve is:

Hyperbolic

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The sigmoidal curve indicates:

Cooperative substrate binding

81
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CTP causes ATCase activity to:

Decrease

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ATP causes ATCase activity to:

Increase

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ATCase is made of:

3 catalytic dimers + 2 regulatory trimers

84
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CTP binds to the:

regulatory subunits

85
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Binding of CTP causes:

Conformational change → decreased activity

86
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ATP binding to ATCase:

Activates the enzyme by shifting to active conformation

87
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ATP stimulates ATCase because:

Both ATP and CTP are required for nucleic acids; ATP signals energy availability

88
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Phosphorylation typically changes:

Conformation and function of the protein

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Phosphorylation can:

All of the above

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Kinases transfer phosphate from:

ATP → protein

91
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Dephosphorylation typically:

Removes PO₄ and causes a new conformation

92
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Na⁺/K⁺ pump transports:

3 Na⁺ out, 2 K⁺ in

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Phosphorylation causes the Na⁺/K⁺ pump to:

Dump Na⁺ to the outside of the cell

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Dephosphorylation causes:

Conformational change returning pump to Na⁺-binding state

95
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Biological membranes are primarily made of:

Lipids, proteins, carbohydrates

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Membranes:

Serve as defining boundaries of cells and organelles

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Membranes:

Also regulate molecular transport

98
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Lipids are broadly defined as molecules that are:

Insoluble or poorly soluble in water but soluble in nonpolar solvents

99
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Amphipathic lipids have:

Polar head + nonpolar hydrophobic tails

100
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Sterols contain:

A four-ring structure