Wind Energy 8-11

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67 Terms

1
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what are the years when the type 1 WECS was dominate?

1980-1995

2
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what are some advantages of the type 1?

simple power conversion configuration; low initial maintenance cost; reliable operation (no power converter)

3
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whare are some disadvantages of the type 1?

no adequate control of the reactive power; lower Cp efficiency because of “fixed” speed; changes in wind cause frequency stabilization issues; grid faults cause severe stress on mechanical components

4
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what is the typical power range of the type 1?

< 1 MW

5
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what are the main components of the type 1?

blades, gearbox, SCIG (squirrel-cage induction generator), soft-starter, capacitor bank, transformer, grid

6
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what is stall control (type I0)?

a passive method used to limit aerodynamic power; this power shows an undesirable overshoot behavior

7
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what is active stall control (type I1)?

passive control with adjustable rotor blades; blades rotate out of wind (negative angles) causing turbulence; no overshoot but higher price arising

8
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what is involved in the drive train of the type 1?

rotor shaft, the gearbox, an elastic coupling and the generator

9
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what are the loads of a type 1?

high loads due to stall control in blades; stiff coupling to grid with high loads and high variability in the active power

10
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what are the power electronics of a type 1?

soft-starter using thyristors

11
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what is the reactive power of the type 1?

no capability to control reactive power; capacitors are used to improve power factor

12
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what are the control strategies of type 1?

ensuring safe turbine operation; in dual speed systems, maximizing energy production at low wind speeds; compensating power factor; responding to a higher level control to start/stop

13
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what are the controllable processes in type 1?

development of aerodynamic torque; development of generator torque; conversion of electrical power from one form into another, using power electronics

14
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when was the type 2 dominate?

1995-2000

15
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what are the components of type 2?

blades, gearbox, WRIG (wound rotor induction generator), external variable rotor resistance, soft- starter, capacitators, transformer, grid

16
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what are the advantages of the type 2?

reduces mechanical loads; smooths active power generation; some improvement in aerodynamic efficiency

17
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what are the disadvantages of the type 2?

limited improvement in aerodynamic efficiency; losses in the variable resistance; no adequate control of reactive power; does not fulfill modern grid codes requirements

18
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what is the typical power range for type 2?

600 kW- 2 MW

19
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what is pitch control (type I2)?

blade is rotated actively into the wind (positive angles); avoids overshoot in power curve

20
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what rotor control does type 2 use?

pitch control to limit and optimize the generated output power

21
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what is the characteristic speed of type 2?

“limited” variable speed by modifying rotor resistance

22
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what are the components of the type 2 drive train?

rotor shaft, gearbox, elastic coupling, generator

23
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what are the loads of type 2?

reduced aerodynamic loads due to pitch control in blades; softer coupling to grid with high loads and medium variability in the active power

24
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what is the generator of the type 2?

wounded rotor asynchronous generator

25
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what are the power electronics in type 2?

external variable rotor resistance; soft-starter using thyristors

26
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what is the reactive power of type 2?

no capability to control reactive power; capacitors used to improve power factor

27
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what is the variable speed of the type 3?

30%

28
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what are the advantages to the type 3?

improvement in aerodynamic efficiency; reduces mechanical loads; smoothes active power generation; control of active and reactive power; supports voltage dips; fulfills modern grid code requirements

29
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what are the disadvantages of type 3?

stator generation is directly connected to the grid and feels any of its disturbance; speed range is smaller than type 4; maintenance cost with slip rings

30
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what is the power range of type 3?

2-5 MW

31
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what rotor control system does type 3 use?

pitch control

32
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what are the speed characteristics of type 3?

variable speed (30%); Cp is aimed for low and medium wind speeds

33
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what does are the components for drive train for type 3?

rotor shaft, gearbox, elastic coupling, generator

34
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what are the loads of type 3?

reduced aerodynamic loads due to pitch control in blades; coupling to the grid is “soft”, reducing loads

35
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what generator does type 3 use?

doubly fed induction generator (DFIG)

36
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what is the reactive power of the type 3?

capability to control reactive power ± 0.9- 0.95 power factor

37
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what are the control strategies of type 3?

ensuring safe turbine operation; speed control to maximize energy production w/in load constraints; pitch control; responding to a higher level control set-point

38
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what is the purpose of the frequency converter in type 3 and 4?

enables control of both the active and reactive power delivered by the generator of the grid

39
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which WECS does not need a gearbox?

type 4

40
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what rotor control is used in type 4?

pitch control

41
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what is the speed characteristics of type 4?

variable speed 50%; Cp is aimed for low and medium wind speeds

42
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what components are a part of the drive train of type 4?

rotor shaft, elastic coupling, generator

43
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what are the loads of the type 4?

loads are reduced by using pitch control; coupling to the grid is “soft”, reducing loads

44
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what are the generators of type 4?

WRSG (wound rotor synchronous generator), PMSG (permanent magnet synchronous generator), IG (induction generator)

45
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what are the power electronic of a type 4?

full rated power converter connected to the rotor (100% nominal power); a rectifier with a dc/ac boost converter

46
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what is the reactive power of type 4?

capability to control reactive power (± 0.9-0.95 power factor)

47
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equation for apparant power

S = P/ p.f. = 3 x V1 x I1*

48
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equation for reactive power

Q = sqr(S² - P²)

49
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operating speed equation

ns = (60 * f) / Pp

50
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equation slip

s = ns - n/ ns

51
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equation airgap power

Pd = Pmi/(1-s)

52
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equation aerodynamic torque

Taero = Paero/ Otur = [½ x rho x A x U³x Cp(TSR, B)] / Otur

53
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equation energy

E = P (power) x T (time)

54
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equation tangent velocity

tangent velocity = w x R (w = rotational speed m/s, radius)

55
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equation relative wind speed

Urel = sqr[(real-induced)² + Utan²]

56
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equation tip speed ratio

TSR = O*R/ U = tangent velocity/free flow wind speed

57
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equation area (not given radius)

A = mass flow rate/ (air density x wind speed)

58
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equation equivalent impedance

Zeq = (jXm x R’2/s + jX’2)/ (jXm + R’2/s + jX’2)

59
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equation stator current

I1 = V1 / Zt = V1 / (R1 + jX1 + Zeq)

60
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equation rotor losses

Pcu2 = Pmi - Pd = 3 x R2 x I’2²

61
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equation stator losses

Pcu1 = Pd - P1 = 3 x R1 x I1²

62
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equation total efficiency

N = ne x nm x Cp

63
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equation Vm

Vm = V1 - I1(R1 + jX1)

64
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equation Im

Im = Vm / jXm

65
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equation rotor current

I2’ = I1 - Im

66
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equation internal mechanical power

Pmi = 3 x R2’ (1/s - 1) x I’2²

67
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equation internal mechanical torque

Tmi = Pmi / Om