Laplace Transform

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Last updated 12:52 PM on 6/30/26
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47 Terms

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Laplace Transform Definition

ℒ{f(t)} = F(s) = ∫₀^∞ e^(-st)f(t)dt

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Laplace Transform of 1

ℒ{1} = 1/s, s > 0

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Laplace Transform of e^(at)

ℒ{e^(at)} = 1/(s-a), s > a

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Laplace Transform of tⁿ

ℒ{tⁿ} = n!/s^(n+1), s > 0

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Laplace Transform of sin(kt)

ℒ{sin(kt)} = k/(s²+k²), s > 0

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Laplace Transform of cos(kt)

ℒ{cos(kt)} = s/(s²+k²), s > 0

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Linearity Property

ℒ{af(t)+bg(t)} = aℒ{f(t)} + bℒ{g(t)}

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Notation for Laplace Transform

If ℒ{f(t)} = F(s), then F(s) is called the Laplace transform of f(t)

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First Derivative Property

ℒ{f'(t)} = sF(s) - f(0)

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Second Derivative Property

ℒ{f''(t)} = s²F(s) - sf(0) - f'(0)

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Third Derivative Property

ℒ{f'''(t)} = s³F(s) - s²f(0) - sf'(0) - f''(0)

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nth Derivative Property

ℒ{f⁽ⁿ⁾(t)} = sⁿF(s) - sⁿ⁻¹f(0) - sⁿ⁻²f'(0) - ··· - f⁽ⁿ⁻¹⁾(0)

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Pattern for Derivative Transforms

Start with sⁿF(s), then subtract descending powers of s multiplied by successive initial conditions

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Exponential Shifting Theorem

ℒ{e^(at)f(t)} = F(s-a)

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How to Apply the Exponential Shifting Theorem

Replace every s in F(s) with (s-a)

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Region of Convergence for Exponential Shift

If F(s) exists for s > c, then ℒ{e^(at)f(t)} exists for s > a+c

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Laplace Transform of e^(at)sin(kt)

k/((s-a)²+k²)

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Laplace Transform of e^(at)cos(kt)

(s-a)/((s-a)²+k²)

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Most Common Laplace Pairs to Memorize

1 ↔ 1/s, e^(at) ↔ 1/(s-a), tⁿ ↔ n!/s^(n+1), sin(kt) ↔ k/(s²+k²), cos(kt) ↔ s/(s²+k²)

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Why Laplace Transforms Are Useful

They convert differential equations into algebraic equations in the variable s

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What Happens to Initial Conditions in Laplace Transforms

They appear automatically through the derivative formulas

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Common Mistake with Derivative Rule

F(s) is the Laplace transform of f(t), not an antiderivative of f(t)

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Variable in the Time Domain

t

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Variable in the Laplace Domain

s