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Mean Value Theorem
If f(x) is continuous on [a,b] and differentiable on (a,b), then there exists a value c, a<c<b, such that f’(c)= f(b)-f(a)/b-a
Basically saying that if a function is continuous and differentiable, then there has to be a point where the derivative (IROC) equals the AROC
Extreme Value Theorem
If f(x) is continuous on [a,b], then f(x) must obtain a maximum and minimum on value on [a,b].
Basically saying that if a function is continuous, then there has to be a maximum and minimum on that interval.
What does the first derivative tell us about f(x)?
f’(x)>0, f(x) is increasing
f’(x)<0, f(x) is decreasing
f’(x) inc, f(x) concave up
f’(x) dec, f(x) concave down
First Derivative Test
Allows us to find local/relative extrema
Find critical points
Make a sign chart w/ those critical points
Plug them into f’ to see where they are pos/neg
Positive to Negative: Relative MAX
Negative to Positive: Relative MIN
Candidates Test
Allows us to find absolute extrema
Find critical points
Make a table with critical points & end points
Plug into original function f(x)
What does the second derivative tell us about f(x)?
f’’(x)>0, f(x) is concave up
f’’(x)<0, f(x) is concave down
If f’’(x)=0/undefined and changes sign, there is a point of inflection
Second Derivative Test
Uses CONCAVITY to find local/relative extrema
Find critical points using f’
Find f’’ and plug in critical points
f’’(x)<0: relative max
f’’(x)>0: relative min
Critical Points
where f’(x)=0 or is undefined