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chain rule
d/dx[f(x)gx)] = f’[g(x)]*g’(x)
![<p>d/dx[f(x)gx)] = f’[g(x)]*g’(x)</p>](https://knowt-user-attachments.s3.amazonaws.com/9225a5ed-c264-4607-bad7-353cf4a10609.png)
implicit differentiation
Take the derivative like normal except for anything except any variable that is not based on x, then take derivative in context of the variable. For example, d/dx(5y²) → 10y*dy/dx

Inverse derivatives
Function must be invertible and differentiable.
If f(x)=0, then the inverse function is differentiable, and the inverse of the derivative of the original function is equal to the derivative of the inverse function.
d/dx[arcsin(u)]
u’/sqrt(1-u²)

d/dx[arccos(u)]
-u’/sqrt(1-u²)

d/dx[arctan(u)]
u’/1-u²

d/dx[arccot(u)]
-u’/1-u²

d/dx[arcsec(u)]
u’/[|u|sqrt(1-u²)]
![<p>u’/[|u|sqrt(1-u²)]</p>](https://knowt-user-attachments.s3.amazonaws.com/bddb7477-2f6a-4bf3-b148-c624fb4cf899.png)
d/dx[arccsc(u)]
u’/[|u|sqrt(1-u²)]-
![<p>u’/[|u|sqrt(1-u²)]-</p>](https://knowt-user-attachments.s3.amazonaws.com/ab189768-270b-4e70-a8df-d9593e41c244.png)
y’’
d²y/d²x
