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Degree of reduction
γ
Inorganic molecule degree of reduction
γ
Degree of reduction for carbon-containing molecules
γ = number of equivalents of electrons available for transfer to oxygen / gram-atom of carbon
Degree of reduction elements
Carbon = 4; Sulfur = 6; Hydrogen = 1; Oxygen = -2; Phosphorous = 5; Nitrogen = -3
Gram-atom of carbon
1 gram-atom of carbon-12 is 12 grams of carbon-12
General cell-growth mass balance
CHmOn + a O2 + b NH3 → c C HαOβNδ + d C HxOyNz + e H2O + f CO2
Calculating degree of reduction
Calculate γ for every compound in the cell balance
Small molecules in degree of reduction calculation
Start with the small molecules and use the number of valence electrons for inorganics
Degree of reduction of O2
γ = 2(-2) = -4
Degree of reduction of NH3
γ = -3 + (3×1) = 0
Degree of reduction of H2O
γ = 2(1) + (-2) = 0
Degree of reduction of CO2
γ = 4 + (2×-2) = 0
Degree of reduction of substrate
γs = 4 + m − 2n
Degree of reduction of biomass
γb = 4 + α − 2β − 3δ
Degree of reduction of product
γp = 4 + x − 2y − 3z
Degree of reduction of glucose
Glucose is C6H12O6
Glucose degree of reduction calculation
γ = (6×4 + 12×1 + 6×-2) / 6
Glucose degree of reduction
γ = 4
Meaning of glucose degree of reduction
γ = 4 moles of electrons available for transfer to oxygen per gram-atom of carbon
Decane degree of reduction
Decane is C10H22
Decane degree of reduction calculation
γ = (10×4 + 22×1) / 10
Decane degree of reduction
γ = 6.2
Decane clicker question answer
The reductance of decane (C10H22) is 6.2
Energy balance for aerobic growth
Q0 kγs − aQ0 4 = cQ0φγb + dQ0wγp
Heat generation during cell growth
Heat evolves during cell growth due to transfer of electrons to oxygen
Q0
Q0 is the heat of reaction per mole equivalent of electrons going to O2
Q0 approximate value
Q0 ≈ 27 kcal/mol e−
Energy per gram-atom carbon
γ = number of equivalents of electrons available for transfer to oxygen / number of carbon atoms
Energy balance use of degree of reduction
γi is a linear combination of elemental balances and may be convenient to use in place of an elemental balance
Water and reductance balance
Moles of water produced (e) are not easy to measure
Energy per gram-atom carbon in species i
γiQ0 is the energy (kcal) per gram-atom carbon in species i
Mass and energy balance equation 1
Carbon: 1(k) = cφ + dw + f
Mass and energy balance equation 2
Nitrogen: b = cδ + dz
Mass and energy balance equation 3
Reductance balance: kγs − a/4 = cφγb + dwγp
Mass and energy balance equation 4
Respiratory quotient: f/a
Prediction of heat evolution
Energy balance for aerobic growth: Q0kγs − aQ0/4 = cQ0φγb + dQ0wγp
Fraction of available electrons incorporated into product
ξP = dγp / kγs
Fraction of available electrons incorporated into biomass
ξb = cφγb / kγs
Fraction of available electrons transferred to O2
ε = a4 / kγs
Energy stored in biomass
Fraction of substrate’s energy stored in the biomass
Energy stored in product
Fraction of substrate’s energy stored in the product
Energy released as heat
Fraction of substrate’s energy released as heat
Energy fraction relationship
The fractions of substrate energy stored in biomass
Normalized energy balance
Divide every term in the energy balance by the term for the substrate’s energy
Metabolic heat
Metabolic heat sets cooling requirements for bioreactors that contain cells
YH
YH is metabolic heat evolved per cell mass produced
Heat of combustion of oxygen
Heat of combustion = 104 kcal/mol O2 = 435.24 kJ/mol O2
Relationship for heat of combustion
1/YH = ΔHC / YX/S − ΔHS
Growth heat rate
QGr = Hbiomass × rGr
Heat of combustion relationship
ΔHS is proportional to the sum of metabolic heat (1/YH) and heat of combustion of cell material (ΔHC)
Respiration yielding cells
Respiration yielding cells has an oxygen requirement of 1/YH in the combustion-based calculation
Substrate combustion
Substrate + oxygen → CO2 + H2O (+ N2)
Cell combustion
Cells + oxygen → CO2 + H2O + N2
Combustion of substrate
ΔHS is the heat of combustion of 1 mole of substrate
Combustion of cells
ΔHC is the heat of combustion of 1 mole of cells
Rate of heat evolution from growth
QGr = Hbiomass rGr
Heat generation calculation
YH can be calculated using the heat of combustion of substrate
Heat of combustion calculation using oxygen
Use 435.24 kJ per mole O2 and the number of moles of O2 needed to combust the substrate or cells
Substrate oxygen requirement for combustion
The number of moles of O2 needed to combust 1 mole of substrate can be calculated from the combustion equation
Cell oxygen requirement for combustion
The number of moles of O2 needed to combust 1 mole of cells can be calculated from the combustion equation
Heat-generation example
A yeast is grown on glucose with YX/S = 0.192 g cells/g S
Heat-generation example cell equation
C6H12O6 + a O2 + b NH3 → c C6H10NO3 + d C2H5OH + e H2O + f CO2
Molecular weight of yeast in example
144 g/mol
Molecular weight of ethanol in example
46 g/mol
Molecular weight of glucose in example
180 g/mol
Heat-generation example nitrogen balance
b = c
Heat-generation example carbon balance
6 = 6c + 2d + f
Heat-generation example oxygen balance
6 + 2a = 3c + d + e + 2f
Heat-generation example hydrogen balance
12 + 3b = 10c + 6d + 2e
Converting YX/S to mol X/mol S
YX/S = 0.192 g X/g S converts to 0.24 mol X/mol S
Stoichiometric coefficient c in heat-generation example
c = 0.24
Stoichiometric coefficient b in heat-generation example
b = c = 0.24
Relationship between growth/product rates and stoichiometric coefficients
The ratio of rates of cell growth to ethanol production is proportional to g cells/g ethanol
Converting cell and ethanol rates to molar rates
Convert g cells and g ethanol to moles to obtain the ratio of their stoichiometric coefficients
Stoichiometric coefficient d
d = 1
Heat-generation example carbon calculation
6 = 6(0.24) + 2(1) + f
Heat-generation example hydrogen calculation
12 + 3(0.24) = 10(0.24) + 6(1) + 2e
Heat-generation example oxygen calculation
6 + 2a = 3(0.24) + 1 + 2.16 + 2(2.56)
Final heat-generation stoichiometric equation
C6H12O6 + 1.5O2 + 0.24NH3 → 0.24C6H10NO3 + C2H5OH + 2.16H2O + 2.56CO2
Heat-generation example heat of combustion values
Heat of combustion of oxygen = 435.24 kJ/mol O2; glucose = 14.508 kJ/g glucose; cells = 21.1574 kJ/g cells
Cell yield in heat calculation
YX/S = 0.192 g cells/g S
Substrate heat of combustion
ΔHS = 14.508 kJ/g S
Cell heat of combustion
ΔHC = 21.1574 kJ/g cells
Metabolic heat yield calculation
HGr = 0.01838 kJ/g cells
Cell growth rate
rcell = 0.306 g cells/L·h
Rate of heat evolution
QGr = 16.65 kJ/L·h