Gen Chem 1 Lab 7: Copper and Percent Yield

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18 Terms

1
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percent yield formula

(recovered mass/ initial mass) x 100%

2
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reaction 1 equation

Cu(s) + 4 HNO3 (aq) —> Cu(NO3)2 (aq) + 2NO2 (g) + 2 H2O (l)

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Cu(s) + 4 HNO3 (aq) —> Cu(NO3)2 (aq) + 2NO2 (g) + 2 H2O (l) visual

turned from orange to green, pungent brown gas’s formed, turned blue when water was added

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reaction 2 equation

Cu(NO3)2 (aq) + NaOH (aq) —> Cu(OH)2 (s) + NaNO3 (aq)

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Cu(NO3)2 (aq) + NaOH (aq) —> Cu(OH)2 (s) + NaNO3 (aq) visual

solution turned into a deep blue gel

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reaction 3 equation

Cu(OH)2 (s) -heated→ CuO (s) + H2 (g)

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Cu(OH)2 (s) -heated→ CuO (s) + H2 (g) visual

condensation on the beaker, mixture turned black

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after reaction 3 we decanted the resulting solution twice, what were we removing ?

OH ions

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reaction 4 equation

CuO (s) + H2SO4 (aq) → CuSO4 (s) + H2 (g)

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reaction 4 observations

condensation on beaker

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reaction 5 equation

CuSO4 (aq) + Zn (s) → Cu (s) ZnSO4 (aq)

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reaction 5 observations

gas evolved

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what are you removing from decanting after CuSO4 (aq) + Zn (s) → Cu (s) ZnSO4 (aq) ?

unreacted zinc

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if your percent yield was more than 100%, what are two plausible errors you may have made?

The product was not sufficiently dried, or the sample was contaminated within an impurity

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how do you find the limiting reagent of a reaction?

You take both reactants and how much of them there are and see how much you can make of a product

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when mixture of 14 g of acetylene in 14 g of oxygen is ignited. The resultant combustion reaction produces CO2 and H2O according to the following balanced equation. What is the limiting reactant?

2C2H2 (g) + 5O2 (g) → 4CO2 (g) + 2H2O (g)

O2

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how many milliliters of 5.5 M H2S04 are required to react with 0.71 g of CuO according to the equation

CuO (s) + H2SO4 (aq) → CuSO4 (aq) + H2O (l)

1.6 mL

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If 1.80 g of Zn is allowed to react with 1.73 g of CUSO4 according to the equation CuSO4 (aq) + Zn (s) → ZnSO4 (aq) + Cu (s) , how many grams of Zn will remain after the reaction is complete?

1.09 g