Kinematics Review – Arjuna JEE (2026) KPP-09

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35 question-and-answer flashcards covering core kinematics formulae, graphical interpretations, conceptual statements and key numerical results from the Arjuna JEE (2026) KPP-09 lecture notes.

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31 Terms

1
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State the kinematic equation that gives displacement s in terms of initial velocity u, acceleration a and time t.

s = u t + ½ a t²

2
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Which equation relates final velocity v to initial velocity u, acceleration a and displacement s?

v² = u² + 2 a s

3
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Write the kinematic equation that gives final velocity v after time t under constant acceleration a.

v = u + a t

4
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In vertical motion (upward taken positive), what numerical value of g is commonly used in JEE problems?

g ≈ 10 m s⁻² downward (a = –10 m s⁻²)

5
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What is the velocity of a projectile at the highest point of its vertical motion?

Zero

6
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How long does a body thrown vertically upward with speed u take to reach its highest point?

t = u / g

7
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Give the expression for maximum height attained by a body projected vertically upward with speed u.

h_max = u² / (2 g)

8
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Resolve an initial speed u launched at angle θ into horizontal and vertical components.

ux = u cos θ, uy = u sin θ

9
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Write the time-of-flight formula for a projectile that lands back on the same horizontal level.

T = (2 u sin θ) / g

10
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Write the horizontal range formula for a projectile launched from ground level.

R = (u² sin 2θ) / g

11
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What are the SI units of acceleration?

Metre per second squared (m s⁻²)

12
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If a body starts from rest with constant acceleration a, what is its average velocity after time t?

v_avg = ½ a t

13
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When equal distances are covered at speeds v₁ and v₂, what is the average speed?

v_avg = 2 v₁ v₂ / (v₁ + v₂)

14
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When equal times are spent at speeds v₁ and v₂, what is the average speed?

v_avg = (v₁ + v₂) / 2

15
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How do you obtain displacement from a velocity-time graph?

By calculating the area under the v–t curve

16
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What physical quantity is represented by the slope of a velocity-time graph?

Acceleration

17
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What does a zero slope on a displacement-time graph indicate about the particle’s motion?

Its instantaneous velocity is zero (particle at rest at that instant)

18
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On a velocity-time graph, what indicates that the particle has reversed direction?

The velocity crosses zero and changes sign

19
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Define ‘reaction time’ for a driver.

Time interval between noticing the need to brake and actually applying the brakes

20
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If initial speed is doubled while the braking retardation is unchanged, by what factor does the stopping distance change?

It becomes four times larger (distance ∝ v₀²)

21
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What happens to the speed of a particle when its velocity and acceleration have opposite signs?

The particle slows down (speed decreases)

22
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If the speed of a particle is zero throughout a time interval, what must be true about its acceleration during that interval?

Acceleration must also be zero for the entire interval

23
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In the motorcycle problem, what is the maximum forward acceleration the engine can produce?

5 m s⁻²

24
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What is the maximum braking retardation available to the same motorcycle?

10 m s⁻²

25
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A rocket rises with net upward acceleration 10 m s⁻² for 60 s. What maximum height (in km) does it reach?

36 km

26
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After the rocket’s fuel finishes (at 60 s) how long does it continue to rise before momentarily coming to rest?

60 s

27
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A projectile is launched at 60 m s⁻¹, 60° above horizontal. When it is coming down and makes 30° with the horizontal, what is v²?

v² = 1.2 × 10³ m² s⁻² (1200 SI units)

28
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A balloon ascends with 10 m s⁻² for 2 s; then a particle is dropped. Two seconds later, what is the particle’s speed?

0 m s⁻¹ (it momentarily stops)

29
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For the same balloon problem, how high is the particle above the ground after those 4 s?

40 m

30
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State the condition under which the harmonic mean, rather than the arithmetic mean, gives average speed.

When equal distances are covered at two different speeds

31
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What kinematic fact explains why stopping distance quadruples when speed doubles, given constant deceleration?

Because stopping distance s = v₀² / (2 |a|); thus s ∝ v₀²