Orgo Exam 3 Reactions and Important Materials

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Last updated 12:52 AM on 7/8/26
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Grignard Reagents (Carbon Nucleophiles)

Reaction #1 - _________

  • Reduce ketone to OH and insert the carbons (located behind Mg) on the same carbon where the ketone was attached.

<p><strong><u>Reaction #1 - _________</u></strong></p><ul><li><p><strong>Reduce ketone to <mark data-color="red" style="background-color: red; color: inherit;">OH </mark>and </strong><span style="color: red;"><strong>insert the carbons</strong></span> (located behind Mg) <strong>on the same carbon where the ketone was attached. </strong></p></li></ul><p></p>
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C-Mg

Synthesis of Grignard Reagents

  • Grignard reagent is characterized by the presence of a ______ bond. Carbon is more electronegative than magnesium, so the carbon atoms withdraws electricity from magnesium via induction. This gives rise to a partial negative charge on the carbon atom.

    • The difference in electronegativity between C and Mg is so large that the bond can be treated as ionic


  • Mg and ether → synthesizes grignard by placing the Mg “behind” the halogen

<p><strong><u>Synthesis of Grignard Reagents </u></strong></p><ul><li><p>Grignard reagent is characterized by the presence of a ______ bond. <strong>Carbon </strong>is <strong><mark data-color="blue" style="background-color: blue; color: inherit;">more electronegative than magnesium</mark></strong>, so the <strong>carbon atoms withdraws electricity from magnesium via induction. This gives rise to a partial negative charge on the carbon atom. </strong></p><ul><li><p><mark data-color="yellow" style="background-color: yellow; color: inherit;">The difference in electronegativity between C and Mg is so large that the bond can be treated as ionic </mark></p></li></ul></li></ul><div data-type="horizontalRule"><hr></div><ul><li><p><span style="color: red;"><strong><mark data-color="red" style="background-color: red; color: inherit;">Mg and ether → synthesizes grignard by placing the Mg “behind” the halogen </mark></strong></span></p></li></ul><p></p>
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Cyanohydrin Formation (Carbon Nucleophiles)

Reaction #2 - ________

  • Reduce C=O to OH and insert CN on the same carbon. (May form a chrial center)

<p><strong>Reaction #2 - ________</strong></p><ul><li><p><span style="color: purple;"><strong>Reduce C=O to OH and insert CN on the same carbon</strong></span>. (May form a chrial center) </p></li></ul><p></p>
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Reduction to NH2

Reaction #2a) - _________

  • Replace CN with NH2

<p><strong><u>Reaction #2a) - _________</u></strong></p><ul><li><p><span style="color: red;"><strong>Replace CN with NH2</strong></span></p></li></ul><p></p>
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Reduction to Carboxylic Acid

Reaction #2b) - ______

  • Replace CN with carboxylic acid

<p><strong>Reaction #2b) - ______</strong></p><ul><li><p><span style="color: blue;"><strong>Replace CN with carboxylic acid </strong></span></p></li></ul><p></p>
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Wittig Reaction

Reaction #3) - ________

  • Extension of carbon chain

  • C=C bond formation

  • Preparation is in situ (prepared and used immediately)

  • Spontaneous reaction, driven by the formation of P=O bond

**Add carbons attached to PPh3 onto double bond (where C=O) → must determine if bond is E/Z

<p><strong><u>Reaction #3) - ________</u></strong></p><ul><li><p>Extension of carbon chain </p></li><li><p>C=C bond formation </p></li><li><p>Preparation is in situ (prepared and used immediately)</p></li><li><p>Spontaneous reaction,<strong> driven by the formation of P=O bond</strong> </p></li></ul><p><span style="color: blue;"><strong><mark data-color="blue" style="background-color: blue; color: inherit;">**Add carbons attached to PPh3 onto double bond (where C=O) → must determine if bond is E/Z </mark></strong></span></p>
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Preparation of Ylid Reagents

Reaction #3a) - ___________

Common Bases: NaH, PhLi, n-BuLi, NaNH2

  • R-X must be methyl, primary or secondary does not work with tertiary. (Steric hindrance)

<p><strong><u>Reaction #3a) - ___________</u></strong></p><p>Common Bases: NaH, PhLi, n-BuLi, NaNH2 </p><ul><li><p><strong>R-X must be methyl, primary or secondary</strong><span style="color: green;"><strong> does not work with tertiary. (Steric hindrance)</strong></span></p></li></ul><p></p>
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  • Z

  • E

Reaction #3 - Witting Reaction

  • Unstabilized ylids (no resonance) = ___ selective

  • Stabilized ylids (resonance) = ____ selective

<p><strong><u>Reaction #3 - Witting Reaction </u></strong></p><ul><li><p><span style="color: red;"><strong>Unstabilized ylids (no resonance)</strong></span> = ___ selective</p></li><li><p><span style="color: blue;"><strong>Stabilized ylids (resonance)</strong></span> = ____ selective </p></li></ul><p></p>
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Baeyer-Villiger Oxidation

Reaction #4) - __________

  • Formation of an ester, which is inserted on whichever side of the C=O bond is more likely to migrate

    • mCPBA

    • CF3CO3H

    • H2O2, AcOH

  • The group that migrates has the ability to stabilize positive charge during migration

<p><strong>Reaction #4) - __________</strong></p><ul><li><p>Formation of an <span style="color: green;"><strong>ester</strong></span>, <strong>which is inserted on whichever side of the C=O bond is more likely to </strong><span style="color: red;"><strong><mark data-color="red" style="background-color: red; color: inherit;">migrate </mark></strong></span></p><ul><li><p>mCPBA</p></li><li><p>CF3CO3H</p></li><li><p>H2O2, AcOH</p></li></ul></li><li><p><strong>The group that migrates has the ability to stabilize positive charge during migration </strong></p></li></ul><p></p>
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Migratory Aptitude

Reaction #4)

Baeyer-Villiger Oxidation - ____

<p><strong><u>Reaction #4)</u></strong></p><p>Baeyer-Villiger Oxidation - ____</p><p></p>
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Protons

Shielding and Deshielding Effect from Hb and Ha

  • Protons deshield neighboring _____due to their orientation in the applied magnetic field.

<p><strong><u>Shielding and Deshielding Effect from Hb and Ha </u></strong></p><ul><li><p>Protons deshield neighboring _____due to their orientation in the applied magnetic field. </p></li></ul><p></p>
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Ratios

Integration _____ of Individual Peaks

  • utilizes pascals triangle.

<p><strong>Integration _____ of Individual Peaks</strong></p><ul><li><p>utilizes<span style="color: blue;"><strong> pascals triangle. </strong></span></p></li></ul><p></p>
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<p>Review</p>

Review

Review

<p>Review</p>
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distance

Coupling Constant (J value, Hz)

Coupling constant is the _____ between peaks within a H-NMR signal.

  • Coupled protons have the same J value → next to each other

    • “a split b” = “b split a”

<p><strong><u>Coupling Constant (J value, Hz)</u></strong></p><p><span style="color: green;"><strong>Coupling constant</strong></span> is the _____ between peaks within a <strong>H-NMR signal</strong>. </p><ul><li><p>Coupled protons have the same J value → next to each other </p><ul><li><p>“a split b” = “b split a” </p></li></ul></li></ul><p></p>
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Splitting Tree

______ Diagram

  • Utilizes pascals triangle and J values, start by splitting with the largest J value.

<p><strong>______ Diagram </strong></p><ul><li><p>Utilizes <strong>pascals triangle and J values</strong>,<mark data-color="green" style="background-color: green; color: inherit;"> start by splitting with the largest J value. </mark></p></li></ul><p></p>
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Simple Spin Multiplicity

When all J values are equal, we observe a ___________.

<p>When <strong>all J values are <mark data-color="green" style="background-color: green; color: inherit;">equal</mark></strong>, we observe a ___________. </p>
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Complex Spin Multiplicity

When all J values are NOT equal, we observe a___________.

<p>When<strong> all J values are </strong><span style="color: red;"><strong><mark data-color="red" style="background-color: red; color: inherit;">NOT equal</mark></strong></span>, we observe a___________. </p>
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Tri-Substituted Alkene System

System 1: Comlex Spin Multiplicity in ___________

  • Geminal

  • Cis

  • Trans

<p><strong>System 1: Comlex Spin Multiplicity in ___________</strong></p><ul><li><p>Geminal </p></li><li><p>Cis</p></li><li><p>Trans</p></li></ul><p></p>
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0-3 Hz (small)

Complex Spin Multiplicity in Tri-Substituted Alkene System

  • 2J geminal = _____

<p><strong><u>Complex Spin Multiplicity in Tri-Substituted Alkene System </u></strong></p><ul><li><p>2J geminal = _____</p></li></ul><p></p>
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6-12 Hz (medium)

Complex Spin Multiplicity in Tri-Substituted Alkene System

  • 3J cis = _____

<p><strong><u>Complex Spin Multiplicity in Tri-Substituted Alkene System </u></strong></p><ul><li><p>3J cis  = _____</p></li></ul><p></p>
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12-18 Hz (large)

Complex Spin Multiplicity in Tri-Substituted Alkene System

  • 3J trans = _____

<p><strong><u>Complex Spin Multiplicity in Tri-Substituted Alkene System </u></strong></p><ul><li><p>3J trans = _____</p></li></ul><p></p>
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10-16 Hz

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~7 Hz

<p></p>
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4-10 Hz

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0.5-2 Hz

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0-1 Hz

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6-9 Hz

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1-3 Hz

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0-1 Hz

*Para protons don’t really couple

<p>*Para protons don’t really couple </p><p></p>
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Couple

  • Acidic protons do not ____ because it hops around

<ul><li><p><span style="color: red;"><strong>Acidic protons</strong></span> do not ____ because it <strong>hops around </strong></p></li></ul><p></p>
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<p>Pratice </p>

Pratice

Practice

<p>Practice </p>
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oic acid

Nomenclature of Carboxylic Acids

1) The suffix “______” indicates a carboxyl group.

**The parent chain must contain a carboxylic group as it has the highest priority among functional groups

<p><strong><u>Nomenclature of Carboxylic Acids </u></strong></p><p>1) The suffix “______” indicates a<span style="color: blue;"> carboxyl group. </span></p><p><span style="color: blue;">**The parent chain must contain a carboxylic group as it has the<strong> highest priority among functional groups </strong></span></p>
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Carboxylic Acid

Nomenclature of Carboxylic Acids

** A carboxyl group that is conntected to a ring is called “________”

<p><strong><u>Nomenclature of Carboxylic Acids </u></strong></p><p>** A<strong> carboxyl group</strong> that is conntected to a ring is called “________” </p>
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  • IUPAC: Methanoic Acid

  • Common: Formic Acid

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  • IUPAC: Ethanoic Acid

  • Common: Acetic Acid

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IUPAC: Propanoic Acid

Common: Propionic Acid

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IUPAC: Butanoic Acid

Common: Butyric Acid

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Benzoic Acid

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Pyruvic Acid

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dioic acid

Nomenclature of Diacids

1) The suffix “______” indicates two carboxyl groups

<p><strong><u>Nomenclature of Diacids </u></strong></p><p>1) The suffix “______” indicates two carboxyl groups </p>
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Oxalic Acid

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Malonic Acid

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Succinic Acid

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Glutaric Acid

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Adipic Acid

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Trigonal Planar

Physical Properties of Carboxylic Acids

(1) Molecular Geometry: ______

<p><strong><u>Physical Properties of Carboxylic Acids </u></strong></p><p>(1) <strong>Molecular Geometry:</strong> ______</p>
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Boiling Point

Physical Properties of Carboxylic Acids

(2) Higher ______ than alcohol due to a higher extent of hydrogen-bonding interactions.

<p><strong><u>Physical Properties of Carboxylic Acids </u></strong></p><p>(2) Higher ______ than alcohol due to a <strong>higher extent of </strong><span style="color: blue;"><strong>hydrogen-bonding</strong></span><strong> interactions. </strong></p>
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Water

Physical Properties of Carboxylic Acids

(3) Higher _____ in water compared to alcohols and aldehydes

  • Water solubuility decreases as the relative size of they hydrophobic protion of the molecule increases (Hydrophobic tail)

<p><strong><u>Physical Properties of Carboxylic Acids </u></strong></p><p>(3) Higher _____ in water compared to <strong>alcohols </strong>and <strong>aldehydes </strong></p><ul><li><p><strong>Water solubuility decreases </strong>as the <span style="color: blue;"><strong>relative size of they hydrophobic protion of the molecule increases <mark data-color="blue" style="background-color: blue; color: inherit;">(Hydrophobic tail) </mark></strong></span></p></li></ul><p></p>
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Acidic

Physical Properties of Carboxylic Acids

(4) It is the most _____ among functional groups

  • It is more acidic due to a resoance stabilized conjugate base.

<p><strong><u>Physical Properties of Carboxylic Acids </u></strong></p><p>(4) It is the most _____ among functional groups </p><ul><li><p><strong>It is more acidic due to a resoance stabilized conjugate base. </strong></p></li></ul><p></p>
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Acidity

Acidity of Carboxylic Acids

  • Inductive substitutents can increase _____, however the effect decreases with distance.

<p><strong><u>Acidity of Carboxylic Acids </u></strong></p><ul><li><p><strong>Inductive substitutents</strong> can increase _____, <mark data-color="red" style="background-color: red; color: inherit;">however the effect decreases with distance. </mark></p></li></ul><p></p>
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Electron-Withdrawing Groups (EWG’s)

Acidity of Carboxylic Acids

  • ______ enhance the acidity of benzoic acid due to that it stabilizes the conjugate base by introducing a positive charge to stabilize the negative charge.

<p><strong><u>Acidity of Carboxylic Acids </u></strong></p><ul><li><p>______ <strong>enhance the acidity of benzoic acid</strong> due to that it <mark data-color="blue" style="background-color: blue; color: inherit;">stabilizes the conjugate base by introducing a positive charge to stabilize the negative charge. </mark></p></li></ul><p></p>
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Conjugate Base and Acid (HH eq.)

Ratio of ____________

<p>Ratio of ____________ </p>
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Henderseon-Hasselbach Equation

Determination of Forms of Pyruvic Acid at Physiological pH

  • Utilize the ____ equation to determine which form is most formed at a specific pH.

    • Guesstimate by the number determined by pH-pka and 1:1000 (number of zeros)

<p><strong><u>Determination of Forms of Pyruvic Acid at Physiological pH </u></strong></p><ul><li><p>Utilize the ____ equation to determine which form is most formed at a specific pH.</p><ul><li><p>Guesstimate by the number determined by pH-pka and 1:1000 (number of zeros) </p></li></ul></li></ul><p></p>
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<p>Review Preparation of Carboxylic Acids </p>

Review Preparation of Carboxylic Acids

Review Preparation of Carboxylic Acids

<p>Review Preparation of Carboxylic Acids </p>
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Carboxylation of Grignard Reagents

Reaction #5) - ______________

  • Formation of a carboxylic acid using CO2 and a Grignard Reagent

  • “R” group of Grignard becomes “left” side of COOH

<p><strong><u>Reaction #5) -  ______________</u></strong></p><ul><li><p><strong>Formation of a </strong><span style="color: green;"><strong>carboxylic acid</strong></span><strong> using <mark data-color="green" style="background-color: green; color: inherit;">CO2 and a Grignard Reagent </mark></strong></p></li><li><p><mark data-color="yellow" style="background-color: yellow; color: inherit;">“R” group of Grignard becomes “left” side of COOH</mark></p></li></ul><p></p>
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Protic

Reaction #5) - Carboxylation of Grignard Reagents

  • Do not add a “_____” solvent together with Grignard

<p><strong><u>Reaction #5) - Carboxylation of Grignard Reagents </u></strong></p><ul><li><p>Do not add a “_____” solvent together with Grignard </p></li></ul><p></p>
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Hydrolysis of Nitriles

Reaction #6) - ___________

  • Formation of a carboxylic Acid from a nitrile

    • “Slice in” carboxylic acid at the carbon of the nitrile

<p><strong><u>Reaction #6) - ___________</u></strong></p><ul><li><p>Formation of a <span style="color: red;"><strong>carboxylic Acid</strong></span> from a <strong><mark data-color="red" style="background-color: red; color: inherit;">nitrile </mark></strong></p><ul><li><p><strong>“Slice in” carboxylic acid at the carbon of the nitrile</strong> </p></li></ul></li></ul><p></p>
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Carboxylic Acid Reduction

Reaction #7) - _________

  • Reduction process that reduces BOTH ketones and COOH down to an alcohol

<p><strong>Reaction #7) - _________</strong></p><ul><li><p>Reduction process that reduces <strong>BOTH <mark data-color="yellow" style="background-color: yellow; color: inherit;">ketones and COOH down to an alcohol </mark></strong></p></li></ul><p></p>
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Carboxylic Acid Reduction #2

Reaction #8) - ________

  • Reduction process that selectively reduces Carboxylic Acids (slices off C=O)

<p><strong><u>Reaction #8) - ________</u></strong></p><ul><li><p>Reduction process that <strong><mark data-color="red" style="background-color: red; color: inherit;">selectively reduces Carboxylic Acids (slices off C=O)</mark></strong></p></li></ul><p></p>
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Fischer Esterification

Reaction #9) - _________

  • Forms an Ester “on” the -OH of the carboxylic acid using the “R” of the alcohol utilized.

<p><strong><u>Reaction #9) - _________ </u></strong></p><ul><li><p>Forms an Ester <strong>“on” the -OH of the carboxylic acid using the “R” of the alcohol utilized. </strong></p></li></ul><p></p>
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Conversion to Acid Chloride

Reaction #10)- ____________

  • Replace OH with Cl, forming SO2 and HCl

<p><strong><u>Reaction #10)- ____________</u></strong></p><ul><li><p><span style="color: blue;"><strong>Replace OH with Cl</strong></span>, forming SO2 and HCl </p></li></ul><p></p>
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al

Nomenclature of Aldehydes

  • The suffix “___” indicates an aldehyde

    • The parent chain must include an aldehydic group (it will be number one in the chain)

<p><strong><u>Nomenclature of Aldehydes </u></strong></p><ul><li><p>The suffix “___” indicates an aldehyde </p><ul><li><p>The <strong>parent chain must include an aldehydic group</strong> (it will be number one in the chain) </p></li></ul></li></ul><p></p>
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Over

Nomenclature of Aldehydes

  • Aldehyde has a priority ____ alcohol, alkene, and alkyne.

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Carbaldehyde

Nomenclature of Aldehydes

  • An aldehydic group adjacent to a ring is called “______”

<p><strong><u>Nomenclature of Aldehydes</u></strong></p><ul><li><p>An <strong>aldehydic group adjacent to a ring</strong> is called “______” </p></li></ul><p></p>
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Benzaldehyde

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Formaldehyde

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Acetaldehyde

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One

Nomenclature of Ketones

  • Suffix “_____” indicates a ketone group

<p><strong><u>Nomenclature of Ketones</u></strong></p><ul><li><p>Suffix “_____” indicates a ketone group</p></li></ul><p></p>
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Over

Nomenclature of Ketones

  • The ketone group has priority ____ alcohol, alkene, and alkyne.

<p><strong><u>Nomenclature of Ketones</u></strong></p><ul><li><p>The ketone group has priority ____ alcohol, alkene, and alkyne. </p></li></ul><p></p>
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Derivatives

Carboxylic Acid _______

  • Acid Chloride

  • Acid anhydride

  • Ester

  • Amide

  • Cyanide

<p><strong><u>Carboxylic Acid _______ </u></strong></p><ul><li><p>Acid Chloride</p></li><li><p>Acid anhydride </p></li><li><p>Ester</p></li><li><p>Amide</p></li><li><p>Cyanide </p></li></ul><p></p>
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Acid Halides

Naming Carboxylic Acid Derivatives

(1) _______: replace “-ic acid” with “-yl halide”

<p><strong><u>Naming Carboxylic Acid Derivatives</u></strong></p><p>(1) _______: replace <strong>“-ic acid” with “-yl halide”</strong></p>
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Acid Anhydride

Naming Carboxylic Acid Derivatives

(2) _______: replace “-ic acid” with “-ic anhyride”

  • Split anhydride into two carboxylic acids

<p><strong><u>Naming Carboxylic Acid Derivatives</u></strong></p><p>(2) _______: replace <strong>“-ic acid” with “-ic anhyride”</strong></p><ul><li><p>Split anhydride into two carboxylic acids</p></li></ul><p></p>
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Ester

Naming Carboxylic Acid Derivatives

(3) _______: replace “-ic acid” with (alcohol + acid) “ate”

<p><strong><u>Naming Carboxylic Acid Derivatives </u></strong></p><p>(3)  _______: replace <strong>“-ic acid” with (alcohol + acid) “ate” </strong></p><p></p>
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Amide

Naming Carboxylic Acid Derivatives

(4) _______: replace “-oic acid” with “-amide”

<p><strong><u>Naming Carboxylic Acid Derivatives </u></strong></p><p>(4)  _______: replace <strong>“-oic acid” with “-amide”</strong></p>
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Nitriles

Naming Carboxylic Acid Derivatives

(5) _______: alkanenitrile

<p><strong><u>Naming Carboxylic Acid Derivatives</u></strong></p><p>(5) _______: alkanenitrile</p>
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Nucleophilic Acyl Substitution

Reaction #11) - _______

  • Leaving group on a carboxylic acid derivative is replaced by a nucleophile.

    • Tetrahedral Intermediate

    • Mechanism pattern depends on strength/reactivity of reagent and derivative. → Derivatives with more stable leaving groups are more reactive

<p><strong><u>Reaction #11) - _______</u></strong></p><ul><li><p>Leaving group on a carboxylic acid derivative is replaced by a<strong> nucleophile. </strong></p><ul><li><p>Tetrahedral Intermediate </p></li><li><p><strong><mark data-color="yellow" style="background-color: yellow; color: inherit;">Mechanism pattern depends on strength/reactivity of reagent and derivative</mark></strong><mark data-color="yellow" style="background-color: yellow; color: inherit;">. → Derivatives with more stable leaving groups are more reactive </mark></p></li></ul></li></ul><p></p>
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LESS

Reaction #11) - Nucelophilic Acyl Substitution

  • The relative reactivity of COOH derivatives is based on the stability of the leaving group and how resonance stabilized the deivative is → if it is resonance stabilized it is _____reactive

<p><strong><u>Reaction #11) - Nucelophilic Acyl Substitution </u></strong></p><ul><li><p>The relative reactivity of COOH derivatives is based on the stability of the leaving group and how resonance stabilized the deivative is →<span style="color: blue;"><strong><mark data-color="blue" style="background-color: blue; color: inherit;"> if it is resonance stabilized it is _____reactive </mark></strong></span></p></li></ul><p></p>
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<p>Review</p>

Review

Review

<p>Review</p>
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Reactive Starting Material + Strong Reagent

Reaction #11)

Pattern #1 - _________

  • Nucelophilic Attack → Loss of Leaving Group

    • Nucelophile is strong enough to attack right away

<p><strong><u>Reaction #11) </u></strong></p><p><strong>Pattern #1</strong> - _________</p><ul><li><p><mark data-color="yellow" style="background-color: yellow; color: inherit;">Nucelophilic Attack → Loss of Leaving Group</mark></p><ul><li><p>Nucelophile is strong enough to attack right away </p></li></ul></li></ul><p></p>
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Reactive Starting Material + Weak Reagent

Reaction #11)

Pattern #2 - _________

  • Nucelophilic Attack → Loss of Leaving Group → Proton Transfer

    • Deprotonation of Nucelophile is required

<p><strong><u>Reaction #11) </u></strong></p><p><strong>Pattern #2</strong> - _________</p><ul><li><p><mark data-color="yellow" style="background-color: yellow; color: inherit;">Nucelophilic Attack → Loss of Leaving Group → </mark><mark data-color="green" style="background-color: green; color: inherit;">Proton Transfer</mark></p><ul><li><p>Deprotonation of Nucelophile is required</p></li></ul></li></ul><p></p>
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Less Reactive Starting Material + Strong Reagent

Reaction #11)

Pattern #3 - _________

  • Nucelophilic Attack → Loss of Leaving Group

    • Nucelophile is strong enough to attack right away

<p><strong><u>Reaction #11) </u></strong></p><p><strong>Pattern #3 </strong>- _________</p><ul><li><p><mark data-color="yellow" style="background-color: yellow; color: inherit;">Nucelophilic Attack → Loss of Leaving Group </mark></p><ul><li><p>Nucelophile is strong enough to attack right away </p></li></ul></li></ul><p></p>
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Less Reactive Starting Material + Weak Reagent

Reaction #11)

Pattern #4 - _________

  • Proton Transfer → Nucelophilic Attack → Proton Transfer (x2) → Loss of Leaving Group → Proton Transfer

    • Reaction is too slow without protonation, reaction is must faster by adding a catalyst

      • Acid catalyst activates starting material so nucelophile can attack

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Sufficiently Reactive

Nucelophilic Acyl Substitution

  • The core pattern involves nucleophilic attack followed by loss of a leaving group

    • Proton Transfer occurs when

  1. The starting material is not ______

  2. The intermediate is a strong acid

  3. You must convert a poor leaving group to a better leaving group (for loss of leaving group)

<p><strong><u>Nucelophilic Acyl Substitution </u></strong></p><ul><li><p>The core pattern involves nucleophilic attack followed by loss of a leaving group </p><ul><li><p><span style="color: blue;"><strong><u><mark data-color="blue" style="background-color: blue; color: inherit;">Proton Transfer occurs when </mark></u></strong></span></p></li></ul></li></ul><ol><li><p><strong>The starting material is not ______</strong></p></li><li><p><strong>The intermediate is a <mark data-color="yellow" style="background-color: yellow; color: inherit;">strong acid </mark></strong></p></li><li><p><strong>You must convert a poor leaving group to a better leaving group (for loss of leaving group)</strong></p></li></ol><p></p>
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Preparation of Acid Chlorides

Reaction #12) - ___________

  • Replace OH with Cl

<p><strong><u>Reaction #12) - ___________</u></strong></p><ul><li><p>Replace <strong>OH </strong>with <strong>Cl </strong></p></li></ul><p></p>
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Hydrolysis of Acid Chlorides

Reactions of Acid Chlorides

Reaction #13) - ________ (Weak Nucelophile)

  • Replace Cl with OH

<p><strong><u>Reactions of Acid Chlorides </u></strong></p><p><strong>Reaction #13) - ________ (Weak Nucelophile) </strong></p><ul><li><p>Replace <strong>Cl </strong>with <strong>OH </strong></p></li></ul><p></p>
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Alcoholysis of Acid Chlorides

Reactions of Acid Chlorides

Reaction #14) - ________ (Weak Nucelophile)

  • Replace Cl with alcohol (ROH minus the H)

<p><strong><u>Reactions of Acid Chlorides </u></strong></p><p><strong>Reaction #14) - ________ (Weak Nucelophile) </strong></p><ul><li><p>Replace <strong>Cl with alcohol (ROH minus the H) </strong></p></li></ul><p></p>
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Aminolysis of Acid Chloride

Reactions of Acid Chlorides

Reaction #15) - ________ (Weak Nucelophile)

  • Replace Cl with Nitrogen group minus one hydrogen

<p><strong><u>Reactions of Acid Chlorides </u></strong></p><p><strong>Reaction #15) - ________ (Weak Nucelophile) </strong></p><ul><li><p>Replace<strong> Cl with Nitrogen group minus one hydrogen </strong></p></li></ul><p></p>
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Reduction of Acid Chloride

Reactions of Acid Chlorides

Reaction #16) - ________

  • xs LiAlH4 reduces all the way to alcohol

  • LiAl(O-t-Bu)3H is sterically hindered so it only reduces down to an aldehyde.

<p><strong><u>Reactions of Acid Chlorides </u></strong></p><p><strong>Reaction #16) - ________ </strong></p><ul><li><p><strong>xs LiAlH4</strong> reduces all the way to<span style="color: blue;"><strong><mark data-color="blue" style="background-color: blue; color: inherit;"> alcohol </mark></strong></span></p></li><li><p><strong>LiAl(O-t-Bu)3H</strong> is sterically hindered so it only reduces down to an <span style="color: green;"><strong><mark data-color="green" style="background-color: green; color: inherit;">aldehyde</mark></strong></span>. </p></li></ul><p></p>
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Reaction with Organometallic Reagents

Reactions of Acid Chlorides

Reaction #17) - ________

  • xs RMgBr = adds 2 “R’s” to carbon and reduces C=O to an alcohol

  • R2CuLi = adds 1 “R” to carbon (replaces Cl) does not reduce C=O to alcohol

<p><strong><u>Reactions of Acid Chlorides </u></strong></p><p><strong>Reaction #17) - ________ </strong></p><ul><li><p><strong>xs </strong><span style="color: blue;"><strong>R</strong></span><strong>MgBr</strong> = adds<strong><mark data-color="blue" style="background-color: blue; color: inherit;"> 2 “R’s”</mark></strong> to carbon and <strong>reduces C=O to an </strong><span style="color: red;"><strong>alcohol</strong></span></p></li><li><p><span style="color: blue;"><strong>R2</strong></span><strong>CuLi </strong>= adds <strong><mark data-color="blue" style="background-color: blue; color: inherit;">1 “R”</mark></strong> to carbon (replaces Cl)<strong><mark data-color="red" style="background-color: red; color: inherit;"> does not</mark> reduce C=O to alcohol </strong></p></li></ul><p></p>