modern test 2

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Last updated 3:24 AM on 9/22/26
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37 Terms

1
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speed of light is measured at c

BY EVERY OBSERVER

2
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basis of time dilation

velocity © has to stay constant so time hasw to change

3
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th moving clock runs slow =

an outside stationary observer sees time pass more slowly for a moving object

4
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guy on the train

proper time , views light going up and down

5
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observer on the tracfk views its as a longer path/diagonal

longer time

6
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proper length

observer on the trakcs

7
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guy on the spaceship time is proper

knowt flashcard image
8
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earth has proper time

knowt flashcard image
9
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farther away from earth, clock ticks faster

earth pre deterine time

10
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if photon had clock

no ticks

11
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Since a single clock in Clock A's frame cannot be at both event locations at once,

Clock A's frame must use multiple synchronized clocks spaced apart to measure the start and end of that interval.

12
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proper time

observers own refernece frame

one clock

no spatial dsitnacfe

13
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dialted time

same or other ref frame

multiple clocks

spatial distacne

14
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term image

given 1 time not the other5

<p>given 1 time not the other5</p>
15
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time dialtino

alpha and beta are 2 seperate places

16
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proper length

in whoevers ref frame where obj r at test

17
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contracted

observer who sees the onj moving

18
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<p></p>



19
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gamma

It tells you how much two observers will disagree on measurements of time and space based on their relative speed.NOT INVARIANT DEPENDS ON WHOS REFERENCE FRMAE UR USING, aka whos v ur using

20
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twin paradox

start w earth frame, v=x/t

21
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finding rockets time

time/gamma

22
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earth link clock accfording to rocket when it gets to planet P

t = t (our) gamma

x = x (our) gamma

23
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time on earth according to rocket coming back

time slipage plus earth time

24
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privilleged frame

absolute rest

absolt tiem

25
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gedmeotry of

SPACETIME

26
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time and spacfe

MEASURD!!! differnelty, clocks dcont acc change3 the way they tick

27
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so your saying since measuring megth is t4echnically measuring 1 length to another

that one length to another is not the same across all reference frames therefore its length is different dpe4ended on reference fram

28
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divide spacfe by c

distance in seconds

29
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multiplyby c

time units into length

30
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time in earths pov

mulyiply gamma to how much time spent on planet

31
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add outbotnd ( kinematics ) to inbound ( gamma )

32
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same ref frame

divide/multiply gamma

33
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turn arouhd n= change of simutlanelity

xhange in how ur seeing the clocks , earths clock appears to jump

34
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While you are coasting smoothly toward Canopus, the situation remains symmetric: you see Earth's clocks running slower than yours

This is because your two frames disagree on what events occur simultaneously across space.

35
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turn doesnt create agte differnenecfe

it simply aligns your reference frame with Earth's so both of you can stand side-by-side and agree on the final result.

36
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coordinatees, spacfetime invariant

s² = v² - t²

37
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<p>find invariant</p>

find invariant

pythag