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Strategies for indefinite u-sub
make u equal to expression that’s more complicated
set u to denominator (especially for trig functions)
make u equal to expression with higher exponent
make it equal to whatever will cancel the other expression in the integral with X
Can you choose to not make an expression u even if u equals that expression?
Yes (do this when you need to cancel x and u doesn’t help)
What to do when x is still in the integral after u subbing
manipulate u equation to equal x in terms of u and plug into it into integral
Trig u-sub strategies
use identities to isolate a single trig function with a power of 1, and create u so it will cancel (usually u is the function you have more of so the single expression will cancel)
use identities to convert between sines and cosines
make u the trig function that you have a higher power of usually
sin⁴x = (sin²x)² works for cosine too
Is the domain of a function that same as its integral?
Yes
When would you add absolute value bars when solving the integral?
When the antiderivative has a log function where negatives can’t be inputted, and the domain of the original function is all real numbers
When would you NOT add absolute value bars inside a log function of an antiderivative?
when the function inside the log always evaluates to positive no matter x (i.e. e^x)
How to solve definite integrals using u-sub
solve exact same way using u sub, except use 1st Fund Theorem at the end to solve the antiderivative at the bounds
How to change the bounds of a definite integral
Find u
Plug in original top and bottom bounds for x in the u equation and set new values for top and bottom respectively
If new top value turns out to be less than the new bottom value, flip the integral
in antiderivative don’t plug x back, keep u and sub in for 1st FTC
If you change the bounds of a definite integral, do you have to plug x back in for u?
No (just plug in new top and bottom bounds for u using 1st FTC)
Differential equation
equation that involves a derivative
What does a slope field show?
the slope of the antiderivative at each point on a graph
Strategy for drawing slope fields for differential equations with x and y variables
Pick one x coordinate and plug it in with all other y coordinates in the graph to find the slopes at every y for that x
How to draw the graph of the antiderivative on a slope field from a given point
plot the point and then follow the curves on each slope line from there
Strategies for matching a slope field to a differential equation
Look for horizontal tangents at corners
test x = 0
pick points to test
If a trig integral already has sine and cosine, and one of them has a power of 1 while the other has a higher power, make u….
equal to the function in the higher power
(if integral is sin(x)cos³(x), make u = cos(x)
If an initial condition is given, use it find…
C
What is the integral of dx?
x
How to complete the square
Move c in quadratic out of the expression, to make room for a new c
(b/2)² = new c value in quadratic
Condense the quadratic into perfect square
Subtract the new c from the old c
If there’s a negative outside of the quadratic when completing the square, then ____ the new c value to the old c
add
If there’s a negative in front of x² and you need to complete the square, then…
factor out the negative only for a and b in the quadratic
For synthetic division, the divisor has to be in the form of…
x - c
(if x + c, make c negative in the division)
If you don’t have 1 for the constant in the denominator when completing the square, then…
multiply the numerator and denominator by the reciprocal of the constant
Incorporate this value into the parentheses of the perfect square by taking it’s square root and placing it in the denominator of the expression
For undefined slopes in a slope field, draw…
no lines
If you get a plus or minus when integrating by separation of variables, how do you determine which one to use?
Use initial condition and plug into the positive and negative equation
See which one actually yields a true answer
What to do if you integrate by separating variables and you get an equation that doesn’t make the initial condition true
If you use an absolute value sign when integrating, get rid of it and make the equation on the other side of the equal sign plus or minus
Take the sign that makes the initial condition true