X-rays

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32 Terms

1
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Describe the basic principle of an X-ray tube (3 steps)

  • Electrons are emitted via. cathode

  • Accelerated by an electric field to an anode

  • Collides with a target

Notes:

  • when e- hits the anode, it decelerates and emits x-rays

  • change in velocity due to energies x10keV (low)

2
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What 3 things do the electron collisions in an x-ray tube give rise to?

1) Bremsstrahlung x-rays

2) Characteristic x-rays

3) Heat

max. energy gained by an electron = e delta v

3
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State and explain the 2 main processes after an electron interacts with a target

1) Bremsstralung x-rays: ENERGY LOST in the form of this x-ray

  • German: “Breaking radiation“

  • consider particle charge e, scattered by a nucleus of charge Ze

  • a Coulomb force: F directly proportional to Ze²

  • Resulting acceleration direc. prop. to Ze²/m

  • Deceleration causes emission of EM radiation, where:

  • power of radiation direc. prop. to a²

  • power direc. prop. to z²e4/m²

  • produces a continuous x-ray spectrum

From an x-ray tube, higher power is required:

  • decrease mass m

  • increase Z of target

  • max. energy of emitted photon:

    • occurs when electron loses all its kinetic energy

    • hv_max = e delta v

    • v_max = max. frequency of x-rays

2) Characteristic x-rays: specific to different energies

  • caused by collisions with atomic electrons

  • incident electron excites or ionizes an atom

  • electronic energy level is filled by downward transitions

  • causes emissions of x-rays of identical frequencies

    • characteristic wavelengths shown

  • compute energy of characteristic x-rays using the Bohr model of the atom:

    • Energy levels in an atom according to the Bohr model:

      • En = (1/n²)*(-m_e*q_e^4 (Z-1)² / (8*h²*eps_0²))

      • n = principle quantum number

      • can derive an approximate formula for energy difference when electrons transition between shells:

        • see image

<p>1) Bremsstralung x-rays: ENERGY LOST in the form of this x-ray</p><ul><li><p>German: “Breaking radiation“</p></li><li><p>consider particle charge e, scattered by a nucleus of charge Ze</p></li><li><p>a Coulomb force: F directly proportional to Ze² </p></li><li><p>Resulting acceleration direc. prop. to Ze²/m</p></li><li><p>Deceleration causes emission of EM radiation, where:</p></li><li><p>power of radiation direc. prop. to a² </p></li><li><p>power direc. prop. to z²e<sup>4</sup>/m² </p></li><li><p>produces a continuous x-ray spectrum</p></li></ul><p>From an x-ray tube, higher power is required:</p><ul><li><p>decrease mass m</p></li><li><p>increase Z of target</p></li><li><p>max. energy of emitted photon:</p><ul><li><p>occurs when electron loses all its kinetic energy</p></li><li><p>hv_max = e delta v</p></li><li><p>v_max = max. frequency of x-rays</p></li></ul></li></ul><p></p><p>2) Characteristic x-rays: specific to different energies </p><ul><li><p>caused by collisions with atomic electrons</p></li><li><p>incident electron excites or ionizes an atom</p></li><li><p>electronic energy level is filled by downward transitions</p></li><li><p>causes emissions of x-rays of identical frequencies</p><ul><li><p>characteristic wavelengths shown</p></li></ul></li><li><p>compute energy of characteristic x-rays using the Bohr model of the atom:</p><ul><li><p>Energy levels in an atom according to the Bohr model:</p><ul><li><p>En = (1/n²)*(-m_e*q_e^4 (Z-1)² / (8*h²*eps_0²))</p></li><li><p>n = principle quantum number</p></li><li><p>can derive an approximate formula for energy difference when electrons transition between shells:</p><ul><li><p>see image</p></li></ul></li></ul></li></ul></li></ul><p></p><p></p>
4
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Draw the x-ray spectrum for an x-ray tube. Label the axes, along with the Bremsstrahlung and characteristic x-rays. Note anything else that may be important.

  • can change the energy spectrum by changing the target material to shift k_alpha and k_beta lines

  • e.g. molybdenum:

    • k_alpha = 17.9 keV

    • k_beta = 21 keV

  • lower energies give better soft tissue contrast

<ul><li><p>can change the energy spectrum by changing the target material to shift k_alpha and k_beta lines</p></li><li><p>e.g. molybdenum:</p><ul><li><p>k_alpha = 17.9 keV</p></li><li><p>k_beta = 21 keV</p></li></ul></li><li><p>lower energies give better soft tissue contrast</p></li></ul><p></p>
5
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State the ranges for hard and soft x-ray energies- explain their uses.

Hard: E> 10keV

  • penetrate liquids, some solids

  • used for diagnostic imaging

Soft x-rays: E< 10keV

  • hardly penetrate matter

6
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Explain the basic idea of a planar x-ray.

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7
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Assuming an isoenergetic beam, derive an equation for the beam intensity with distance.

mu is the attenuation coefficient.

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<p>mu is the attenuation coefficient.</p><img src="https://knowt-user-attachments.s3.amazonaws.com/81d80d1d-21f0-4558-9060-61597e79d8bb.png" data-width="100%" data-align="center" alt="knowt flashcard image"><p></p>
8
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State and explain the 3 mechanisms of interaction of x-rays with matter.

1) Photoelectric effect

  • photon interacts with an electron

    • electron is emitted from the atom and photon absorbed

    • contribution of photoelectric effect to mu:

    • mu_PE ~ ezÂł/EÂł

    • most important at low energy & for tissues with high z values

2) Compton scattering

  • photon scatters by a weakly bound electron

    • electron is ejected from the atom

    • photon energy is released by an amount, depending on the scattering angle

    • contribution of scattering to mu:

    • mu_CS direc. prop. to p (approx.)

3) Pair production

  • photon interacts with a nucleus, forming electron/position pair

  • only happens for photon energy > 1.02 MeV

    • (rest mass of electron and position)

  • less relevant for diagnostic x-rays

9
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Draw a graph of mu against the energy of a photon for each mechanism of interaction, labelling the diagram. Explain which is most important.

knowt flashcard image

<img src="https://knowt-user-attachments.s3.amazonaws.com/445006d0-b80c-4c48-b585-dc6aa8d475a6.png" data-width="100%" data-align="center" alt="knowt flashcard image"><p></p>
10
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What are Fourier Transforms useful for?

  • a way to assess frequency content of a signal or optical frequencies in an image

  • they consider phase

11
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What do the low and high frequencies in a spatial domain correspond to?

Low:

  • represent overall spatial structure

High:

  • represent smaller, rapidly-changing features

12
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State the 1D FT and 1D FT equations for functions F(k) and f(x)

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<img src="https://knowt-user-attachments.s3.amazonaws.com/8439c84f-278e-4ca6-a999-4f283335c0a4.png" data-width="100%" data-align="center" alt="knowt flashcard image"><p></p>
13
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State the 2D FT and 2D IFT equations for F(k_x, k_y) and f(x, y)

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14
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Describe the principles of Translate-rotate x-ray CT + draw a plot of x-ray intensity vs. distance from the beam in the y direction.

1) A series of pencil- narrow beam x-rays- beam shines through the subject (defined by lead collimators)

2) Source + detector: translated across the body

3) Attenuation of the beams allows definition of a projection from a given direction

<p>1) A series of pencil- narrow beam x-rays- beam shines through the subject (defined by lead collimators)</p><p>2) Source + detector: translated across the body</p><p>3) Attenuation of the beams allows definition of a projection from a given direction</p>
15
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What is the intensity (as a function of distance r) given by, hence the projection? Draw a diagram of the rays going through a subject, with labels to help.

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16
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Draw two plots: intensity and projection against r as rays pass through a subject.

State what they are dependent on.

  • projections are spread across object

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17
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What is the general equation for projection?

  • everything is - apart from path xcos phi + ysin phi

  • this picks out a path

  • want the attenuation- image of the slice

    knowt flashcard image

18
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What type of process is used to invert the equation and reconstruct mu(x, y) from P(phi, r)?

Back projection construction

19
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What does Central Section Theorem state? What does it prove?

States: “1D FT of a projection through an object is the same as a section through the 2D FT of the object itself along the Fourier conjugate of the projection.”

1DFT (P(phi, r) —> 2DFT (mu(x, y))

Proves there is enough information in the projections to define M(k_x, k_y) and so mu(x, y)

20
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Starting from an axial slice and defining the 1DFT of the projection of that slice, prove the Central Section Theorem.

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21
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What is the disadvantage to the Central Section Theorem?

  • it’s non-uniform sampling of k-space

  • need different method of reconstruction

22
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What is the basic principle of Crude Back Projection reconstruction?

  • generated by spreading each projection back across image space and adding them together

23
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<p>Crude back projection…<br>Use the expression to relate reconstructed image mu* to real image mu(x,y)</p>

Crude back projection…
Use the expression to relate reconstructed image mu* to real image mu(x,y)

M*(k_x, k_y) = M(k_x,k_y)/k_r
M = 2DFT of the object
M* = 2DFT of the image

- spatial frequencies down weighted in proportion to their magnitude

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24
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What are the basic principles of Filtered Back Projection? (3 things)

  • corrects blurring

  • projects P’, a filtered version of each projection

  • amplifies components in projection in proportion to their spatial frequency

25
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Give a disadvantage for Filtered Back Projection

  • can also amplify high-frequency noise which is unwanted!

26
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Give the basic principles of Iterative Back Projection.

  • an alternative to FBPR

  • numerical technique

  • results in better images

Based on algorithm:

1) Make a guess at the object by making PxQ grid of numbers

2) Use guess to make simulated projection

3) Compare simulated projections to the real projections and update the guess

Note:

  • also becoming more popular

27
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Path length: simulated projections…
How to find the real object from the iterative BPR?

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28
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<p>Using various projections calculate the possible real projection from the grid. Assume the path length through each voxel = 1.</p>

Using various projections calculate the possible real projection from the grid. Assume the path length through each voxel = 1.

knowt flashcard image

<img src="https://knowt-user-attachments.s3.amazonaws.com/37b298b4-ee05-4813-95ac-a7515a679eeb.png" data-width="100%" data-align="center" alt="knowt flashcard image"><p></p>
29
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What is the main source of noise in x-ray CT?

  • photon noise

30
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How is the signal-to-noise ratio (SNR) calculated from the number of photons?

SNR = sqrt(N)
high photons = good SNR
but wanna avoid it!!

31
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What can generate higher SNR? What are the disadvantages to this?

  • increasing voxel size

  • leads to partial voluming

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32
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What is beam hardening and what can it lead to?

  • X-ray has multiple energies, so the average beam energy is higher as the beam travels through the tissue

  • this can lead to artefacts (unreal images)