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When finding the current in branches of a multiloop circuit
Choose arbitrary directions for i. If at the very end, you get a negative value for i, that means the direction you chose was wrong - reverse it at the very end.
Junction rule
The sum of currents entering a junction must be equal to the sum of currents leaving that junction
Resistances in parallel
Resistors in parallel have the same potential difference V - par-v
Equivalent resistance in parallel
1/R equivalent = 1/R1 + 1/R2 + 1/R3 + …
Resistances in series
Resistors connected in series have the same current i across each - ser-i
Equivalent resistance in series
R equivalent = R1 + R2 + R3 + …
Finding potential difference between any two points in a circuit
Start at one point and traverse the circuit to the other point along any path, and add algebraically the changes in potential you encounter
Resistance rule
Change in potential across a resistor going the direction of the current = -iR
EMF rule
Change in potential across a battery going the direction of the current = (E)
Power of an EMF device
P = i(E)
Power
P = iV, P = i2 R, P = V2 /R, lightbulb gets brighter with more power through it
EMF (E)
(E) = dw (work) / dq (charge)
Units for a volt
Joule / coulomb
Current through a simple circuit
i = V/R
Resistance through a wire
R = (p) L/A, (p) is resistivity, L is length, A is area of cross-section
Units of an amp
Coulomb / second
Voltage potential difference between plates of a capacitor
Vc = q/c
Current when charging a capacitor
Current is zero when the plates have same potential difference as terminals of the battery
Equilibrium/final charge on a capacitor
q = C(E)
Charging equation for a capacitor
R * dq/dt + q/C = (E)
Charge on the plates of a capacitor being charged
q = C(E)(1 - e-t/RC )
Current while charging a capacitor
i = dq/dt = ((E)/R) * e-t/RC
How a capacitor behaves while being charged
Initially, capacitor acts like an ordinary connecting wire relative to the charging current. A long time later, it acts like a broken wire.
Voltage potential difference while charging a capacitor
Vc = q/C = (E)(1 - e-t/RC )
Capacitative time constant
Tau = RC
Discharging equation
R * dq/dt + q/C = 0
Charge when discharging a capacitor
q = q0 * e-t/RC
Current when discharging a capacitor
i = dq/dt = -(q0 / RC) * e-t/RC
Potential energy of capacitor
E = q2 / 2C = CV2 / 2