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Polynomials will be continuous at
all intervals(-infinity,+infinity)
Intervals on which the function is continuous for 8-9x-x^2
(-infinity,+infinity)
"Find its average rate of change over the interval
[−7, 1]" formula
f(x)-f(y)/y-x
f(x) = −x2 − 14x − 6
Find its average rate of change over the interval
[−7, 1]
ΔyΔx=-8
Marginal Cost =
dP/dX
Marginal Cost for P = −0.7x^3 + 30x^2 − 162.85x − 4000
−2.1x^2 + 60x − 162.85
Get the derivative using the chain rule
y = (8x^2 − 3)^3
"Show that the function is increasing and decreasing on the given open intervals"
Derivative, 0,0,-power,power
Find the first partial derivatives.
g(x, y) = ln(x^4 + y^4)
g(x)=
4x^3/x^4+y^4
"Consider the following.
f(x) = −4x2 + 32x"
Increasing and Decreasing will be
Increasing: (-infinity, CN)
Decreasing: (CN,infinity)
Consider the following.
f(x) = −4x2 + 32x
Increasing and Decreasing
Increasing: (-infinity,4)
Decreasing: (4,infinity)
y = −x3 + 9x2 − 3
Concave upward:
Concave downward:
(-infinity,3)
(3,infinity)
Relative max and min for sq rt # -x^2
Relative Max: 0,sq rt
Relative Min(Smaller Value):-sq rt, 0
Relative Min(Smaller Value):sq rt, 0
Relative Min and Max for sq rt 49 -x^2
Relative Max: 0, 7
Relative Min(Smaller Value):-7, 0
Relative Min(Smaller Value):7, 0
Sketch a graph of a function f having the given characteristics.
f(0) = f(2) = 0f '(x) < 0 if x < 1f '(1) = 0f '(x) > 0 if x > 1f ''(x) > 0
Positive U graph
"A campground owner plans to enclose a rectangular field adjacent to a river. The owner wants the field to contain 125,000 square meters. No fencing is required along the river. What dimensions will use the least amount of fencing"
x=
y=
y = sq rt (125,000 x 2)
x = sq rt (125,000 x 2)/2
To Find the number of units x that produces a maximum revenue R
Get derivative then solve for X
Find the number of units x that produces a maximum revenue R.
R = 102x^2 − 0.04x^3
x = 1700 Units
"Find the number of units x that produces the minimum average cost per unit C
in the given equation.
C = 0.001x3 + 6x + 250"
Find C bar, then C bar prime, then solve for X
Find the number of units x that produces the minimum average cost per unit C
in the given equation.
C = 0.001x^3 + 8x + 250
x = 50
Derivative of any f(x)=ln(#x)
1/x
Derivative of f(x)=ln(5x)
1/x
Derivative of f(x)=ln(7x)
1/x
Find the derivative of the function.
y = ln xx4
1-4ln(x)/x^5
When doing cubed root indefinite integrals will be
3/4 and 4/3
When finding the integral of e^# with nothing in front
All you do in add the fraction
Integral of e^5x-7
1/5e^5x-7+C
When using Log rule for integral when numerator is in the denominator answer will be
C+Ln(|numerator|)