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V2O5 reduces to V2O4 and is then regenerated, facilitating continuous conversion of SO2 to SO3
Reaction: 2I− + S2O8^2− → I2+ 2SO4^2− -This reaction is slow due to the repulsion between the negatively charged ions.
-Adding Fe2+ ions accelerates the reaction as follows:The mechanism involves:
Fe2+ ions are oxidised to Fe3+ by S2O82-:
S2O82-(aq) + 2Fe2+(aq) ➔ 2Fe3+(aq) + 2SO42-(aq)
The Fe3+ ions then oxidise I- to I2, regenerating Fe2+:
2Fe3+(aq) + 2I-(aq) ➔ I2(aq) + 2Fe2+(aq)
Fe2+ and Fe3+ facilitate electron transfer between I− and S2O8^2−, speeding up the reaction.
The reaction between permanganate ions (MnO4-) and oxalate ions (C2O42-) is an autocatalytic reaction. Autocatalysis occurs when a product of the reaction acts as a catalyst, speeding up the reaction as the product accumulates. In this case, Mn2+ is the autocatalytic product that accelerates the reaction.
The overall reaction is:
5C2O42-(aq) + 2MnO4-(aq) + 16H+(aq) ➔ 10CO2(g) + 2Mn2+(aq) + 8H2O(l)
The mechanism showing Mn2+ autocatalysis is:
Mn2+ catalyses the reaction by first reacting with MnO4- to form Mn3+ ions:
MnO4-(aq) + 4Mn2+(aq) + 8H+(aq) ➔ 5Mn3+(aq) + 4H2O(l)
The Mn3+ ions then react with C2O42- to regenerate Mn2+:
2Mn3+(aq) + C2O42-(aq) ➔ 2Mn2+(aq) + 2CO2(g)