Math

studied byStudied by 19 people
5.0(1)
get a hint
hint

Roots

1 / 28

encourage image

There's no tags or description

Looks like no one added any tags here yet for you.

29 Terms

1

Roots

  • The value/s which make/s the quadratic equation true.

New cards
2

Discriminant

  • This will guide us in determining the nature of the roots without solving.

  • b² - 4ac

New cards
3

Finding the roots by Quadratic Formula

  • if b² - 4ac > 0, the equation has two different real roots.

<ul><li><p>if <strong>b² - 4ac &gt; 0, </strong>the equation has two different real roots.</p></li></ul>
New cards
4

Finding the roots by Quadratic Formula

  • if b² - 4ac = 0, the equation has one real root.

<ul><li><p>if <strong>b² - 4ac = 0, </strong>the equation has one real root.</p></li></ul>
New cards
5

Finding the roots by Quadratic Formula

  • if b² - 4ac < 0, the equation has no real roots.

<ul><li><p>if <strong>b² - 4ac &lt; 0, </strong>the equation has no real roots.</p></li></ul>
New cards
6

Quadratic Term

  • The term with degree of 2 in a quadratic equation.

  • ± ax²

New cards
7

Linear Term

  • The term with the degree of 1 in a quadratic equation.

  • ± bx

New cards
8

Factoring

  • A method of solving quadratic equations which uses common monomial factor, difference of two squares, perfect square trinomials and general quadratic trinomials.

New cards
9

Solutions

  • The other term given to roots of quadratic equation.

New cards
10

Zero Product Property

  • The property which states that if a and b are real numbers such that ab = 0, then a = 0 and b = 0.

<ul><li><p>The property which states that if <strong><em>a </em></strong>and <strong><em>b</em></strong><em> </em>are real numbers such that <strong><em>ab</em></strong><em> </em>= 0, then <strong><em>a </em></strong>= 0 and <strong><em>b </em></strong>= 0.</p></li></ul>
New cards
11

Square Root Property

  • The property which states that, for any non-negative real number c, if = c, then x = ± √c.

<ul><li><p>The property which states that, for any non-negative real number <strong><em>c</em></strong>, if <strong><em>x² </em></strong>=<strong><em> c</em></strong>, then <strong><em>x </em></strong>= ± √<strong><em>c</em></strong>.</p></li></ul>
New cards
12

Extraneous

  • A value which was solved but is not a solution to the quadratic equation.

New cards
13

Imaginary

  • A root of a quadratic equation which is not real.

New cards
14

Constant Term

  • The term with a degree of zero in a quadratic equation.

  • ± c

New cards
15

Rational root

  • The nature of root of a quadratic equation wherein the discriminant is a perfect square.

New cards
16

Irrational root

  • The nature of root of a quadratic equation wherein the discriminant is not a perfect square.

New cards
17

Zero nature of roots

  • The value solved for the discriminant of a quadratic equation which has real and equal roots.

<ul><li><p>The value solved for the discriminant of a quadratic equation which has <strong>real </strong>and<strong> equal</strong> roots.</p></li></ul>
New cards
18

Positive nature of roots

  • The value solved for the discriminant of a quadratic equation which has real and unequal roots.

<ul><li><p>The value solved for the discriminant of a quadratic equation which has <strong>real </strong>and<strong> unequal</strong> roots.</p></li></ul>
New cards
19

Negative nature of roots

  • The value solved for the discriminant of a quadratic equation which has not real roots.

<ul><li><p>The value solved for the discriminant of a quadratic equation which has <strong>not</strong> <strong>real</strong> roots.</p></li></ul>
New cards
20

Standard/General Form

  • The form in which a quadratic equation is written as ax² + bx + c = 0.

New cards
21

Quadratic

  • Comes from the Latin word quadratus which means “to make a square”.

New cards
22

Steps in Solving Quadratic Equations by Factoring

1) Write the equation in standard form, with the right member zero.

2) Factor the left member of the equation.

3) Set each factor equal to zero.

4) Solve the resulting first-degree equations.

5) Check if the answers are correct by substituting them to the variable in the original equation.

<p>1) Write the equation in standard form, with the right member zero.</p><p>2) Factor the left member of the equation.</p><p>3) Set each factor equal to zero.</p><p>4) Solve the resulting first-degree equations.</p><p>5) Check if the answers are correct by substituting them to the variable in the original equation.</p>
New cards
23

Steps in Finding the Roots by Completing the Square.

1) If the value of a is 1, proceed to step 2. Otherwise, divide both sides of the equation by a.

2) Group all variable terms on one side of the equation and constant on the other side, x² + bx = c.

3) Complete the square of the resulting binomial by adding on both sides of the equation the square of half of b. x² + bx + (1/2 b)² = c + (1/2 b)².

4) Factor the resulting perfect square trinomial and write it as square of binomial. (x + b/2)².

5) Use the Square Root Property to solve for x. (x + b/2) = √c + (c + (b/2)².

<p>1) If the value of <strong>a </strong>is 1, proceed to step 2. Otherwise, divide both sides of the equation by <strong>a</strong>.</p><p>2) Group all variable terms on one side of the equation and constant on the other side, <strong>x² + bx = c.</strong></p><p>3) Complete the square of the resulting binomial by adding on both sides of the equation the square of half of b. <strong>x² + bx + (1/2 b)² = c + (1/2 b)².</strong></p><p>4) Factor the resulting perfect square trinomial and write it as square of binomial. (<strong>x + b/2)²</strong>.</p><p>5) Use the Square Root Property to solve for <strong>x</strong>. (<strong>x + b/2) = √c + (c + (b/2)²</strong>.</p>
New cards
24

Sum and Product of the Roots of a Quadratic Equation

If r and r are the roots of the quadratic equation ax² + bx + c = 0, then:

  • Sum of the root: r + r₂ = -b/a.

  • Products of the roots: rr₂ = c/a.

If we divide ax² + bx + c = 0 by a, we obtain x² + bx/a + c/a = 0.

The sum of the roots of ax² + bx + c = 0 is -b/a and the product of roots is c/a.

<p>If <strong><span style="font-family: Segoe UI Historic, Segoe UI, Helvetica, Arial, sans-serif">r</span><span style="font-family: -apple-system, BlinkMacSystemFont, Segoe UI, Roboto, Oxygen-Sans, Ubuntu, Cantarell, Helvetica Neue, sans-serif">₁</span></strong> and<strong> <span style="font-family: Segoe UI Historic, Segoe UI, Helvetica, Arial, sans-serif">r</span><span style="font-family: -apple-system, BlinkMacSystemFont, Segoe UI, Roboto, Oxygen-Sans, Ubuntu, Cantarell, Helvetica Neue, sans-serif">₂</span></strong> are the roots of the quadratic equation <strong>ax² + bx + c = 0</strong>, then:</p><ul><li><p><strong>Sum of the root: r<span style="font-family: -apple-system, BlinkMacSystemFont, Segoe UI, Roboto, Oxygen-Sans, Ubuntu, Cantarell, Helvetica Neue, sans-serif">₁</span> + <span style="font-family: Segoe UI Historic, Segoe UI, Helvetica, Arial, sans-serif">r</span><span style="font-family: -apple-system, BlinkMacSystemFont, Segoe UI, Roboto, Oxygen-Sans, Ubuntu, Cantarell, Helvetica Neue, sans-serif">₂ = -b/a.</span></strong></p></li><li><p><strong>Products of the roots: r<span style="font-family: -apple-system, BlinkMacSystemFont, Segoe UI, Roboto, Oxygen-Sans, Ubuntu, Cantarell, Helvetica Neue, sans-serif">₁</span> ⋅ <span style="font-family: Segoe UI Historic, Segoe UI, Helvetica, Arial, sans-serif">r</span><span style="font-family: -apple-system, BlinkMacSystemFont, Segoe UI, Roboto, Oxygen-Sans, Ubuntu, Cantarell, Helvetica Neue, sans-serif">₂ = c/a. </span></strong></p></li></ul><p>If we divide <strong>ax² + bx + c = 0 </strong>by <strong>a</strong>, we obtain <strong>x² + bx/a + c/a = 0.</strong></p><p>The sum of the roots of <strong>ax² + bx + c = 0</strong> is -b/a and the product of roots is c/a.</p><p></p>
New cards
25

Sum and Product of the Roots of a Quadratic Equation

A quadratic equation can be written in the form:

x² - (sum of the roots)x + (product of the roots) = 0.

<p>A quadratic equation can be written in the form:</p><p><strong>x² - (sum of the roots)x + (product of the roots) = 0.</strong></p><p></p>
New cards
26

Steps in finding the two consecutive positive even integers.

1) Identify the conditions stated.

2) Represent the unknown.

3) Form the equation satisfying the conditions mentioned in the problem.

4) Solve the resulting equation using the appropriate method.

5) Identify extraneous solutions if there are.

6) State the answer.

In finding two consecutive numbers with the given product, think of the factors of the product which have a difference of 1.

In finding the two consecutive even (or odd) numbers with the given product, think of the even (or odd) factors of the product which have a difference of 2.

<p>1) Identify the conditions stated.</p><p>2) Represent the unknown.</p><p>3) Form the equation satisfying the conditions mentioned in the problem.</p><p>4) Solve the resulting equation using the appropriate method.</p><p>5) Identify extraneous solutions if there are.</p><p>6) State the answer.</p><p>In finding two consecutive numbers with the given product, think of the factors of the product which have a difference of 1. </p><p>In finding the two consecutive even (or odd) numbers with the given product, think of the even (or odd) factors of the product which have a difference of 2. </p>
New cards
27

Finding the consecutive numbers.

How to find the sum of two consecutive numbers. (refer to the picture)

<p>How to find the sum of two consecutive numbers. (refer to the picture)</p>
New cards
28

Finding the consecutive numbers.

How to find the product of two consecutive numbers, (refer to the picture)

<p>How to find the product of two consecutive numbers, (refer to the picture)</p>
New cards
29

Finding the dimensions of a rectangle.

How to find the dimensions of a rectangle. (refer to the picture)

Area = length x width

<p>How to find the dimensions of a rectangle. (refer to the picture)</p><p>Area = length x width</p>
New cards

Explore top notes

note Note
studied byStudied by 13 people
Updated ... ago
5.0 Stars(1)
note Note
studied byStudied by 47 people
Updated ... ago
4.0 Stars(4)
note Note
studied byStudied by 20 people
Updated ... ago
5.0 Stars(2)
note Note
studied byStudied by 15 people
Updated ... ago
5.0 Stars(1)
note Note
studied byStudied by 26 people
Updated ... ago
5.0 Stars(1)
note Note
studied byStudied by 14 people
Updated ... ago
5.0 Stars(1)
note Note
studied byStudied by 7 people
Updated ... ago
5.0 Stars(1)
note Note
studied byStudied by 477 people
Updated ... ago
5.0 Stars(6)

Explore top flashcards

flashcards Flashcard80 terms
studied byStudied by 16 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard83 terms
studied byStudied by 15 people
Updated ... ago
5.0 Stars(2)
flashcards Flashcard39 terms
studied byStudied by 5 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard44 terms
studied byStudied by 14 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard21 terms
studied byStudied by 8 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard112 terms
studied byStudied by 2 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard246 terms
studied byStudied by 73 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard82 terms
studied byStudied by 67 people
Updated ... ago
4.5 Stars(2)