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rates of change are increasing
"up like a cup"
slope of secant line
change in y/change in x = f(b) - f(a)/b-a
Y-Y₁ = m (X-X₁)
point: (X₁, Y₁)
y = a (x-h)² + k
V: (h, k)
AOS: x=h
y = a (x-p)(x-q)
x-int: (p, 0) (q, 0)
y = ax² + bx + c
V: (-b/2a, )
x = -b ± √(b² - 4ac)/2a
* finds both real and imaginary zeros
lim f(x) =
x → ∞/-∞
compare the degree of the top and bottom
y = #
lim f(x) = #
x → ∞
lim f(x) = #
x → -∞
finding vertical asymptotes of a rational function
factor the denominator and find what values make each factor = to zero
X = #
use synthetic or long division to find a linear equation that represents the end behavior
* the degree of the numerator must be one bigger than the degree of the denominator
aₙ = a₁ + d(n-1)
a₁ is first term
d is common difference
aₙ = a₀ + d(n)
aₙ = aₖ + d(n-k)
k is any term
aₙ = a₁ (r)ⁿ⁻¹
r is common ratio
aₙ = a₀ (r)ⁿ
aₙ = aₖ (r)ⁿ⁻^K
f(x) = a(b)^x
a is y-int
b is constant proportion/multiplier
f(x) = y₁ (b)^x-x₁
(x₁, y₁) can be any input output pair
A = Pₑ^rt
P is initial amount
r is rate as a decimal
t is times
A = P₀ (1+r/n)^(n)(t)
P₀ is initial amount
r is rate as a decimal
n is number of times compounded in a year
y = y₀ (1/2)^t/n
y₀ is the initial amount
n is the time of half-life