ec2104 lecture 2

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Last updated 7:51 AM on 8/22/26
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13 Terms

1
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a function is _____ when small changes in independent variable x leads to _____ changes in the ____________

a function is continuous is small changes in independent variable x leads to small changes in the function value y

2
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geometrically a function is continuous if it has no ______

geometrically a function is continuous if it has no breaks

3
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<p>in this definition, the 3 conditions are: </p><ol><li><p>the function f must be defined at _______</p></li><li><p>the _______________ must exist</p></li><li><p>the limit must = ___</p></li></ol><p></p>

in this definition, the 3 conditions are:

  1. the function f must be defined at _______

  2. the _______________ must exist

  3. the limit must = ___


  1. the function f must be defined at x = a

  2. the limit of f(x) which is x → a must exist

  3. the limit must = f(a)


4
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if f and g are continuous at a then (f + g) and (f - g) must both be continuous at a

5
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if f and g are continuous at a then fg and f/g must both be continuous at a

6
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[f(x)r] is continuous at a only if:

  1. _____ is defined

  2. r is a ___ _____


  1. [f(a)]r is defined

  2. r is a real number


7
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if f has an ______ on the interval l then its inverse f-1 is ________ on ______

if f has an inverse on the interval l then its inverse f-1 is continuous on f(l)

8
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INTERMEDIATE VALUE THEOREM: let f be a function which is continuous upon (a,b)

  • if f(a) and f(b) have ______ ____, then there is at least _ __ in (a, b) such that __ = 0


  • if f(a) and f(b) have different signs, then there is at least one c in (a, b) such that f(c)= 0 (meaning c is a root)


9
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INTERMEDIATE VALUE THEOREM: let f be a function which is continuous upon (a,b)

  • if f(a) __ f(b), then for every intermediate value y in the open interval between __ and __ there is at least one c in (a,b) such that f(c) = _


  • if f(a) =/= f(b), then for every intermediate value y in the open interval between f(a) and f(b) there is at least one c in (a,b) such that f(c) = y


10
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strengths of IVT

  1. tells you that at least 1 root exists

  2. the range of a continuous function over an interval is itself an interval


11
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limitations of

  1. doesn’t tell you how many roots

  2. doesn’t tell you how to get the roots


12
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5 steps to using the IVT:

  1. D_____ the function: Let f(x) be …

  2. E________ f(x) c_________: The polynomial f(x) is continuous for all x

  3. Choose an i_______: For x in [-2, 1]

  4. Check for s____ r_______: f(-2) = -4.2 and f(1) = -0.6

  5. Invoke IVT: So IVT implies that there exists at least 1 number c in [-2,1] such that f(c) = 0


5 steps to using the IVT:

  1. Define the function: Let f(x) be …

  2. Establish f(x) continuous: The polynomial f(x) is continuous for all x

  3. Choose an interval: For x in [-2, 1]

  4. Check for sign reversal: f(-2) = -4.2 and f(1) = -0.6

  5. Invoke IVT: So IVT implies that there exists at least 1 number c in [-2,1] such that f(c) = 0



13
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a function f(x) is differentiable at x=a as long as the limit in the definition of the derivative exists

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