CHM2046 Lecture 8/25

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Last updated 8:19 PM on 8/25/26
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23 Terms

1
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What is K?

The equilibrium constant; a number with no units that depends on the relative amounts of products and reactants at equilibrium

2
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How do we determine K?

From rate constants (k) → Kc = kfwd/krev

3
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Where does Kc = kfwd/krev come from?

{products] / [reactants] review this!!

4
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What does high K mean? Rationalize.

High K means the reaction is product-favored. Equilibrium lies right. This comes from a high [products] compared to [reactants].

5
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What does K ~ 1 mean?

At equilibrium, there is a mixture of products and reactants.

6
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Kc =

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7
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Rule #1 for writing equilibrium constant, K, expressions

Heterogeneous reactions: Pure solids and pure liquids WILL NOT appear in K, so do not include their concentrations in K. Why? Pure solids and liquids have standard-state quantity of 1.

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Heterogeneous reactions

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K is a defined value for ___ and ___.

A given temperature and specific balanced equation.

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Rule #2 for writing K expressions

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Rule #3

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Koverall =

K1 x K2 x K3…

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Rule #4

K refers to a balanced qeuation as written. K changes if multiplied by a common factor.

ex. A→B; 1/2A→1/2B. → Kc → K^1/2

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Kp =

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15
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Why can we use the same rules for Kc as Kp?

Every concentration can be rewritten as a pressure using a factor of RT. → P=(n/v)RT → M=P/RT

16
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How do we express K in terms of Kp?

delta n = change in moles of gas = moles gas products - moles gas reactants

<p>delta n = change in moles of gas = moles gas products - moles gas reactants</p>
17
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Always check that units given match ___!

units of K given

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Do the rules for K apply to Q?

Yes

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Q

The reaction quotient; Q is at any time in the reaction, any set of conditions; Q COULD be at equilibrium

20
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If Q is at equilibrium, ___.

Q = K

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K < Q

Reaction proceeds from right to left to reach equilibrium; goes to reactants. This is because we have “too much” product.

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K > Q

Reaction proceeds from left to right to reach equilibrium; goes to products. This is because we have “too much” reactant.

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K = Q

Reaction at equilibrium. No change in concentrations occurs.