Exponential Distribution

0.0(0)
studied byStudied by 0 people
0.0(0)
full-widthCall with Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/19

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No study sessions yet.

20 Terms

1
New cards

Exponential Distribution

A continuous probability distribution that models the time between independent events occurring at a constant average rate λ

2
New cards

Probability Density Function (PDF)

  • f(x) = λe^-(λx) for x ≥ 0

  • It describes how the probability is distributed over time intervals

  • Used to model the time between successive arrivals at a service desk or failures of electronic components

3
New cards

Cumulative Distribution Function (CDF)

  • F(x) = 1 - e^(-λx)

  • Gives the probability that the waiting time is less than or equal to x

  • In reliability engineering, F(x) represents the probability that a component will fail before time x.

4
New cards

Expected Value (Mean)

  • μ_Χ = 1/λ

  • The average waiting time between events

  • If the average rate of incoming network packets is 5 per second, the mean waiting time between arrivals is 0.2 seconds

5
New cards

Variance

  • (σ_Χ)² = (1/λ²)

  • Measures the spread of waiting times

  • A higher λ (faster process) results in smaller variance, indicating more predictable waiting times

6
New cards

Standard Deviation

  • σ_X = 1/λ

  • Equals to the mean

  • Showing proportional speed

  • If average bulb lifetime is 1000 hours, its standard deviation is also 1000 hours.

7
New cards

Memoryless Property

  • P(X > s + t|X > s) = P(X > t)

  • The future waiting time does not depend on how much time has already elapsed

  • For radioactive decay, the chance an atom survives another 10 decay is independent of how long it has already existed

8
New cards

Exponential distribution’s relationship to the Poisson Process

  • The exponential distribution models the waiting time between events in a Poisson process with rate parameter λ

  • If call arrive at a call center following a Poisson process with λ = 3 per minute

  • The waiting time between calls follows Exp(3)

9
New cards

Derivation of the Mean

  • μ_X = ∫(from 0 to ∞) xλe^-(λx) dx = 1/λ

  • Evaluated by the integration by parts and L’Hôpital’s rule

  • to show the term -xe^-(λx) approaches zero as x → ∞

10
New cards

Derivation of the Variance

  • (σ_Χ)² = ∫(from 0 to ∞) x²λe^-(λx) dx - (μ_X)² = 1/(λ²)

  • Integration by parts confirms the result

  • with boundary terms vanishing as x → ∞

11
New cards

The Relationship Between Exponential and Poisson Distributions

  • If T is the waiting time until the next event in a Poisson process with rate λ

  • Then T ~ Exp(λ)

  • P(T > t) = P(X = 0) = e^-(λt) gives us:

  • F(t) = 1 - e^-(λt)

12
New cards

Probability of Waiting Longer than t

  • P(T > t) = e^-(λt)

  • If server crashes occur at λ = 0.2 per hour,

  • The probability of running more than 10 hours without a crash will be:

  • e^-2 = 0.135

13
New cards

Propagation of Uncertainty in λ ̂ (Estimated Rate)

  • σ_λ ̂ = | d/dX̄ 1/X̄ | σ_X̄ = 1/( X̄ n^1/2)

  • Used to quantify how precisely λ (event rate) is estimated from n observed intervals

14
New cards

Standard Error of the Mean for Exponential Distribution

  • σ_X̄ = σ/(n^1/2) = 1/(λ*n^1/2)

  • If mean lifetime of 10 devices is measured, this gives uncertainty in the average.

15
New cards

Estimation of Rate Parameter λ

  • λ ̂ = 1/X̄

  • The rate parameter is the reciprocal of the sample mean

  • In system reliability,

  • If average time between failure is 50 hours,

  • Estimated failure rate is 0.02 failures/hour

16
New cards

Uncertainty in Estimated Rate (σ_λ ̂)

  • σ_λ ̂ = 1/(X̄*(n^1/2))

  • For 25 observed events with average waiting time 2 minutes

  • σ_λ ̂ = 1/(2 × 5) = 0.1 min^-1

17
New cards

Component Lifetimes (Engineering Example)

  • The exponential distribution models how long a component operates before failure when the failure rate is constant.

  • For an electronic sensor with mean life 5000 hours

  • P(failure before 1000h) = 1 - e^(-1000/5000) = 0.181

18
New cards

Quality Testing (Industrial Example)

  • Used to predict the waiting time between defective products on an assembly line.

  • If defects occur on average every 200 items, λ = 1/200, so the chance no defect occurs in 300 items is e^-1.5 = 0.22

19
New cards

Communication Systems Example

  • Models the time between successive data packets or bit errors in a communication link.

  • If the average arrival packer rate is 1000 packets/sec

  • Then the waiting time between packets follows Exp(1000)

20
New cards

Time to Next Event (Medical Example)

  • Represents waiting time until the next biological event such as infection, decay, or heart beat irregularity.

  • If the rate of heartbeat irregularities is 0.05 per minute, the waiting time follows Exp(0.05)