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Exponential Distribution
A continuous probability distribution that models the time between independent events occurring at a constant average rate λ
Probability Density Function (PDF)
f(x) = λe^-(λx) for x ≥ 0
It describes how the probability is distributed over time intervals
Used to model the time between successive arrivals at a service desk or failures of electronic components
Cumulative Distribution Function (CDF)
F(x) = 1 - e^(-λx)
Gives the probability that the waiting time is less than or equal to x
In reliability engineering, F(x) represents the probability that a component will fail before time x.
Expected Value (Mean)
μ_Χ = 1/λ
The average waiting time between events
If the average rate of incoming network packets is 5 per second, the mean waiting time between arrivals is 0.2 seconds
Variance
(σ_Χ)² = (1/λ²)
Measures the spread of waiting times
A higher λ (faster process) results in smaller variance, indicating more predictable waiting times
Standard Deviation
σ_X = 1/λ
Equals to the mean
Showing proportional speed
If average bulb lifetime is 1000 hours, its standard deviation is also 1000 hours.
Memoryless Property
P(X > s + t|X > s) = P(X > t)
The future waiting time does not depend on how much time has already elapsed
For radioactive decay, the chance an atom survives another 10 decay is independent of how long it has already existed
Exponential distribution’s relationship to the Poisson Process
The exponential distribution models the waiting time between events in a Poisson process with rate parameter λ
If call arrive at a call center following a Poisson process with λ = 3 per minute
The waiting time between calls follows Exp(3)
Derivation of the Mean
μ_X = ∫(from 0 to ∞) xλe^-(λx) dx = 1/λ
Evaluated by the integration by parts and L’Hôpital’s rule
to show the term -xe^-(λx) approaches zero as x → ∞
Derivation of the Variance
(σ_Χ)² = ∫(from 0 to ∞) x²λe^-(λx) dx - (μ_X)² = 1/(λ²)
Integration by parts confirms the result
with boundary terms vanishing as x → ∞
The Relationship Between Exponential and Poisson Distributions
If T is the waiting time until the next event in a Poisson process with rate λ
Then T ~ Exp(λ)
P(T > t) = P(X = 0) = e^-(λt) gives us:
F(t) = 1 - e^-(λt)
Probability of Waiting Longer than t
P(T > t) = e^-(λt)
If server crashes occur at λ = 0.2 per hour,
The probability of running more than 10 hours without a crash will be:
e^-2 = 0.135
Propagation of Uncertainty in λ ̂ (Estimated Rate)
σ_λ ̂ = | d/dX̄ 1/X̄ | σ_X̄ = 1/( X̄ n^1/2)
Used to quantify how precisely λ (event rate) is estimated from n observed intervals
Standard Error of the Mean for Exponential Distribution
σ_X̄ = σ/(n^1/2) = 1/(λ*n^1/2)
If mean lifetime of 10 devices is measured, this gives uncertainty in the average.
Estimation of Rate Parameter λ
λ ̂ = 1/X̄
The rate parameter is the reciprocal of the sample mean
In system reliability,
If average time between failure is 50 hours,
Estimated failure rate is 0.02 failures/hour
Uncertainty in Estimated Rate (σ_λ ̂)
σ_λ ̂ = 1/(X̄*(n^1/2))
For 25 observed events with average waiting time 2 minutes
σ_λ ̂ = 1/(2 × 5) = 0.1 min^-1
Component Lifetimes (Engineering Example)
The exponential distribution models how long a component operates before failure when the failure rate is constant.
For an electronic sensor with mean life 5000 hours
P(failure before 1000h) = 1 - e^(-1000/5000) = 0.181
Quality Testing (Industrial Example)
Used to predict the waiting time between defective products on an assembly line.
If defects occur on average every 200 items, λ = 1/200, so the chance no defect occurs in 300 items is e^-1.5 = 0.22
Communication Systems Example
Models the time between successive data packets or bit errors in a communication link.
If the average arrival packer rate is 1000 packets/sec
Then the waiting time between packets follows Exp(1000)
Time to Next Event (Medical Example)
Represents waiting time until the next biological event such as infection, decay, or heart beat irregularity.
If the rate of heartbeat irregularities is 0.05 per minute, the waiting time follows Exp(0.05)