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Individual Z problem
z = x − μ / σ
Individual Z interpretation
Positive z = above μ, negative z = below μ, z > 2 = generally unusual
Sample mean Z problem
z = x̄ − μ / (σ / √n)
Sampling distribution problem
ux̄ = μ and SE = σ / √n
CLT problem
If n ≥ 30 treat the sampling distribution of x̄ as approximately normal
Confidence interval problem P.Z.CV.CI.
Identify the parameter, then choose Z T or proportion, then find critical value and E, then build the interval
Known σ mean problem
use Z
Unknown σ mean problem
use T and df = n − 1
Proportion problem —> P, Z
successes x and n → calculate p̂ = x / n —> then use a proportion Z interval
Plus 4 problem
Given x and n → p̃ = x + 2 / n + 4
Find interval from estimate and E Estimate 50 and E 3 → interval
47 to 53
Find E from interval Interval 40 to 50 → E
5
Find estimate from interval Interval 40 to 50 → estimate =
45
Find width from E, E = 5 → width =
10
Confidence comparison: 99 percent confidence is X than 95 percent confidence with the same data
99 percent confidence is wider than 95 percent confidence with the same data
Sample size comparison: Larger n → ? E → ? interval
Larger n → smaller E → narrower interval
Standard deviation comparison: Larger σ or s → ? E → ? interval
Larger σ or s → larger E → wider interval
Asked how many observations are needed for a mean → use ? formula
mean sample size
Asked how many people or successes are needed → use ? formula
proportion sample size
No prior proportion problem: No prior p̂ → use ?
0.50
Sample size calculation
Calculate n then always round UP
Degrees of freedom problem: n = 20 → df =
19
Confidence level problem: 95 percent → α = 0.05 → α/2 =
0.025
Confidence level problem: 99 percent → α = 0.01 → α divided by 2 =
0.005
Confidence level problem: 90 percent → α = 0.10 → α divided by 2 =
0.05
Method recognition: σ known → ?; σ unknown or s given → ?; proportion → ?
σ known → Z; σ unknown or s given → T; proportion → Z
Formula recognition
Identify what the problem asks for before choosing the formula