Newton's First Law of Motion and Forces

Set of flashcards covering key concepts from Newton's First Law of Motion and forces within the context of physics, particularly focusing on equilibrium and friction.

The first condition of equilibrium states that the sum of the forces acting on a body must equal __.

Zero.

In classical mechanics, __ is the measure of the gravitational force acting on an object.

Weight.

Two types of friction are and friction.

Static; Kinetic.

Applied Force is denoted as __.

F or FA.

The normal force is represented by the symbol __.

N or FN.

The equation for translational equilibrium is given by __ = 0.

∑Fx and ∑Fy.

The force of gravity is also known as __.

Weight.

A body is in equilibrium when the resultant of the force system acting on it is __.

Zero.

The maximum static frictional force is defined by __.

fs,max = μsN.

The coefficient of friction is denoted by the symbol __.

μ.

In static equilibrium, the external forces acting on the body __.

Are balanced.

Kinetic friction force is given by the equation __.

fk = μkN.

Static friction is always __ than kinetic friction.

Greater.

The angle of incline mentioned for the block problem is __ degrees.

35°.

Friction force is proportional to the __ between two bodies.

Normal force.

If T is the tension in the cable, for constant speed up the slope, __ = W1 sin 15°.

T.

The problem of moving a granite block considers a slope of __ degrees.

15°.

When a force of weight W2 acts downward, the tension T must equal __ for equilibrium.

W2.

If the angle is 30° and it’s a static system, we need to find the maximum weight of block __.

A.

A horizontal force applied against a wall is denoted as __.

F.

The relationship between static and kinetic friction states that __ < μs < 1.

0.

In the free-body diagram, tension can be resolved into and components.

Vertical; Horizontal.

The weight of the crate in the sample problem is __ lb.

400.

The forces in ropes BA and BC can be found by solving equations for __.

Equilibrium.

For the system to move with constant speed, the relationship w1 = __ must be satisfied.

0.26w2.

The maximum static friction is reached when __ is exceeded.

fs,max.

The block weighing __ N has a coefficient of static friction of 0.25.

711.

If μk > 1, it means __ .

It is easier to lift than slide.

Once an object is in motion, use __ instead of μs.

μk.

To budge a resting object, you must exceed the __ of static friction.

Maximum force.

The total tensile force T in the sample problem equals __ in equilibrium.

W2.

The components T1 and T2 in the free-body diagram correspond to angles of __ degrees.

10° and 35°.

The principles of static friction apply as long as the object is __ .

At rest.

The tension in rope BA was found to be approximately __ lb.

398.372.

The first condition of equilibrium requires the sum of forces in the and directions.

X; Y.

For block C weighing 40 kg, the corresponding mass of block A has been calculated to be __ kg.

20.

The vertical weight component for block B is influenced by the __ angle.

Incline.

The relationship between the weights of w1 and w2 is essential for maintaining __ speed.

Constant.

Frictional forces depend on both the __ in contact and their materials.

Surfaces.

The coefficient of static friction ranges between and .

0; 1.

In a free-body diagram, angle θ is crucial in determining the __ components.

Vector.

If the static force is applied, the system will remain in __ .

Static equilibrium.

Understanding forces and equilibrium is fundamental in __ mechanics.

Classical.

For maximal function in static conditions, the applied force needs to consider both and .

Friction; Weight.

The vector sum of all forces should always yield __ upon equilibrium.

Zero.