Chapter 12 and 13 Organic Chemistry 2

0.0(0)
studied byStudied by 0 people
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/93

flashcard set

Earn XP

Description and Tags

Matt Way's Class Summer 2025

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

94 Terms

1
New cards
What does IR spectroscopy detect in molecules?
It detects how molecules absorb infrared light, revealing the types of bonds present.
2
New cards
How does UV–Vis spectroscopy differ from IR?
UV–Vis detects electronic transitions, while IR focuses on vibrational energy changes.
3
New cards
What is the formula for energy of electromagnetic radiation?
E = hc/λ
4
New cards
What is the formula for wavenumber?
ν̅ (cm⁻¹) = 1/λ (cm)
5
New cards
What is the IR wavelength and wavenumber range?
2.5–25 µm or 4000–400 cm⁻¹
6
New cards
Why is wavenumber useful in IR spectroscopy?
It is directly proportional to energy, which simplifies analysis of bond vibrations.
7
New cards
What analogy describes bond stretching in IR?
It’s like two balls connected by a spring (harmonic oscillator).
8
New cards
What factors increase vibrational frequency and wavenumber?
Stronger bonds and lighter atoms both increase frequency.
9
New cards
Why is recognizing functional groups important in IR spectroscopy?
Functional groups have characteristic absorption patterns that help identify molecular structures.
10
New cards
What are some functional groups to memorize for IR identification?
Alcohols, amines, ketones, aldehydes, carboxylic acids, nitriles, aromatics, alkyl halides, etc.
11
New cards
What should you be able to do with functional group IR patterns?
Recognize them visually and match them to specific wavenumber ranges in a spectrum.
12
New cards
What strategy helps when given an unknown molecular structure?
Look for key functional group IR absorptions and match them with known reference values.
13
New cards
What are common abbreviations used in IR spectra descriptions?
w = weak, m = medium, s = strong; n = narrow, b = broad, sh = sharp
14
New cards
Where can the IR absorption reference table be found?
In the course module titled “IR absorption reference table” under Chapter 12/13.
15
New cards
Where does the C–H stretch for alkanes appear?
Just below 3000 cm⁻¹
16
New cards
What are the key IR absorptions for alkynes?
≡C–H stretch near 3300 cm⁻¹ and C≡C stretch near 2100 cm⁻¹
17
New cards
What is the O–H stretch range for alcohols in IR?
Broad stretch between 3400–3650 cm⁻¹
18
New cards
What is the range for the C–O stretch in alcohols?
Strong stretch between 1000–1320 cm⁻¹
19
New cards
What is the N–H stretch range for amines?
Medium, 3250–3400 cm⁻¹
20
New cards
What other key stretches are seen in amines?
C–N stretch (1020–1250 cm⁻¹, medium) and N–H bend (1650–1580 cm⁻¹, medium)
21
New cards
What is the strong IR stretch characteristic of amides?
C=O stretch between 1760–1665 cm⁻¹
22
New cards
How do amide N–H stretches compare to amines?
Amides show medium N–H stretch from 3400–3250 cm⁻¹, typically narrower
23
New cards
What are the C–H stretch values for aromatic compounds?
Strong stretch from 3100–3000 cm⁻¹
24
New cards
What are the key C–C stretch ranges in aromatics?
Medium C–C stretches at 1600–1585 cm⁻¹ and 1500–1400 cm⁻¹
25
New cards
What is a unique IR signal for aldehydes not found in ketones?
Medium O=C–H stretch between 2830–2695 cm⁻¹
26
New cards
What is the C=O stretch range for aldehydes?
Strong peak from 1740–1720 cm⁻¹
27
New cards
What is the characteristic IR signal for ketones?
Strong C=O stretch around 1715 cm⁻¹
28
New cards
How do ketone IR spectra differ from aldehyde spectra?
Ketones lack the additional O=C–H stretch seen in aldehydes
29
New cards
What is the O–H stretch range in carboxylic acids?
Broad, medium intensity stretch between 3300–2500 cm⁻¹
30
New cards
What other major IR peaks do carboxylic acids show?
C=O stretch (1760–1690 cm⁻¹) and C–O stretch (1320–1000 cm⁻¹)
31
New cards
What IR signal is specific to C–Cl in alkyl halides?
Medium C–Cl stretch between 850–550 cm⁻¹
32
New cards
What C–H stretch may also appear in alkyl halides?
Medium C–H stretch between 1300–1150 cm⁻¹
33
New cards
What is the key IR absorption in nitriles?
Very strong C≡N stretch between 2260–2210 cm⁻¹
34
New cards
How does the nitrile peak appear in the IR spectrum?
As a sharp, strong signal in the 2200 cm⁻¹ region
35
New cards
What should you do when multiple functional groups are present in IR?
Identify each functional group individually and match all expected signals
36
New cards
What compound was used in this slide as an example of multiple functional groups?
Vanillin
37
New cards
How can you predict the compound from a given IR spectrum?
Match the absorption peaks to known functional group ranges and identify which functional groups are present
38
New cards
What is the first step in analyzing an unknown IR spectrum?
Look for strong, broad, or sharp peaks that match key functional group absorptions
39
New cards
How do nuclei behave without an external magnetic field?
Their spins are randomly oriented.
40
New cards
What happens when a magnetic field is applied in NMR?
Nuclei align parallel (low E) or anti-parallel (high E) to the field.
41
New cards
What is meant by “resonance” in NMR?
Absorption of radiofrequency radiation causes spin flips from low to high energy states.
42
New cards
What factors determine the resonance frequency in NMR?
Magnetic field strength, identity of the nucleus, electronic environment
43
New cards
What types of nuclei are detectable in NMR?
Nuclei with an odd number of protons and/or neutrons (e.g., ¹H, ¹³C)
44
New cards
What energy transition occurs during NMR measurement?
A proton absorbs radiofrequency and flips to a higher energy spin state.
45
New cards
What does the NMR signal ultimately represent?
It reflects the different magnetic environments of hydrogen atoms in a molecule.
46
New cards
How are signals displayed in NMR data?
As peaks on a spectrum measured in parts per million (ppm)
47
New cards
What causes multiple signals in ¹H NMR?
Chemically non-equivalent hydrogen atoms produce distinct signals.
48
New cards
What is chemical shift (δ)?
The position (in ppm) where a nucleus absorbs radiation, relative to TMS.
49
New cards
What is the formula for calculating chemical shift (δ)?
δ (ppm) = (Observed shift in Hz) / (Spectrometer frequency in MHz)
50
New cards
What is the reference compound for NMR chemical shifts?
Tetramethylsilane (TMS), assigned 0 ppm
51
New cards
Why is TMS used as the reference?
It has shielded protons (low electronegativity of Si), producing a consistent signal at 0 ppm
52
New cards
What does “downfield” mean in ¹H NMR?
A higher δ value; corresponds to less shielding and protons near electronegative atoms
53
New cards
What does “upfield” mean in ¹H NMR?
A lower δ value; corresponds to more shielding and protons near electron-rich environments
54
New cards
Which direction does the δ scale increase on an NMR spectrum?
From right (upfield) to left (downfield)
55
New cards
What causes protons to be deshielded in ¹H NMR?
Proximity to electronegative atoms or unsaturated systems (e.g., sp² carbons)
56
New cards
Where do sp³ C–H protons usually appear in ¹H NMR?
More upfield, typically around 0.9–1.5 ppm
57
New cards
Where do sp² C–H protons usually appear?
Downfield, typically 5–8 ppm
58
New cards
Where do aldehyde protons appear in ¹H NMR?
Around 9–10 ppm
59
New cards
Where do aromatic protons appear?
Around 6.5–8 ppm
60
New cards
Where do alcohol O–H protons typically appear?
Broad signals around 1–5 ppm, depending on hydrogen bonding
61
New cards
What symmetry does 1,4-dimethylbenzene (p-xylene) exhibit in ¹H NMR?
Symmetrical substitution gives only two types of proton environments
62
New cards
What are the expected δ values for p-xylene protons?
Aromatic protons ≈ 7.0 ppm; methyl protons ≈ 2.3 ppm
63
New cards
What does the area under an NMR peak represent?
The number of protons (hydrogens) contributing to that signal.
64
New cards
How does integration help interpret ¹H NMR spectra?
It allows you to calculate relative ratios of equivalent proton groups.
65
New cards
What does a taller or larger peak mean in NMR?
A larger number of equivalent hydrogens are contributing to that signal.
66
New cards
What causes spin–spin splitting in ¹H NMR?
Magnetic interactions between nonequivalent neighboring protons.
67
New cards
What is the “n + 1 rule” in NMR?
A proton with n neighboring hydrogens will split into n + 1 peaks.
68
New cards
What splitting pattern results from 1 neighboring proton?
Doublet (n + 1 = 2)
69
New cards
What splitting pattern results from 2 equivalent neighbors?
Triplet (n + 1 = 3)
70
New cards
What is a multiplet?
A complex splitting pattern from coupling with multiple nonequivalent proton groups.
71
New cards
What are the three types of protons in ethanol?
Methyl (CH₃), Methylene (CH₂), and Hydroxyl (OH)
72
New cards
Expected δ and splitting for CH₃ in ethanol?
δ ≈ 1.2 ppm; Triplet (split by CH₂)
73
New cards
Expected δ and splitting for CH₂ in ethanol?
δ ≈ 3.7 ppm; Quartet (split by CH₃)
74
New cards
Expected δ and splitting for OH in ethanol?
δ ≈ 2.6 ppm; Singlet (no coupling with other protons)
75
New cards
What were the actual δ values for ethanol’s protons in the spectrum?
Ha (CH₃) ≈ 1.2 ppm; Hb (OH) ≈ 2.6 ppm; Hc (CH₂) ≈ 3.7 ppm
76
New cards
Why does the OH signal often appear as a singlet?
Proton exchange with solvent prevents coupling with neighboring protons.
77
New cards
What happens to splitting when neighboring protons are equivalent?
Equivalent protons do not cause spin–spin splitting.
78
New cards
Why does 1,2-dichloroethane show only one signal?
Molecular symmetry makes all four hydrogens equivalent.
79
New cards
What does the NMR spectrum of 1,2-dichloroethane look like?
A single singlet at ~3.7 ppm, representing all symmetrical protons.
80
New cards
What structural feature leads to a singlet in this case?
The molecule has internal symmetry, so all H’s experience the same environment.
81
New cards
What is a key strategy to recognize equivalent protons?
Look for molecular symmetry that produces chemically identical environments.
82
New cards
Why might a compound with multiple protons still give few peaks?
Some sets of protons are equivalent due to symmetry and don’t split each other.
83
New cards
What does the NMR spectrum of 1,4-dioxane show?
One singlet around 3.6 ppm for all hydrogens
84
New cards
Why does 1,4-dioxane only show one signal?
Its cyclic symmetry makes all hydrogens equivalent.
85
New cards
How many distinct proton environments are present in 1,4-diethylbenzene?
Three: aromatic H’s, ethyl CH₂, and ethyl CH₃
86
New cards
How does symmetry affect the splitting in 1,4-diethylbenzene?
Symmetry simplifies the spectrum; equivalent protons result in fewer signals and predictable splitting.
87
New cards
What information should you gather for each proton environment in a compound?
Chemical shift (δ), Integration (number of H’s), Splitting pattern (singlet, doublet, etc.)
88
New cards
What’s the goal of matching spectrum peaks to proton sets?
To assign each NMR signal to a specific group of chemically equivalent protons in the molecule.
89
New cards
How can you check if your interpretation of an NMR spectrum is accurate?
The number of signals, their relative areas, and splitting should match the structure’s symmetry and hydrogen environments.
90
New cards
Why is integration critical in assigning peaks?
It tells you how many hydrogens are producing each signal, helping differentiate CH₃, CH₂, and CH types.
91
New cards
What is one major use of ¹H NMR in organic chemistry labs?
Verifying the identity and purity of synthesized compounds
92
New cards
How can NMR verify hydroboration–oxidation reactions?
The product's signal confirms formation of the less substituted alcohol, indicating anti-Markovnikov addition.
93
New cards
What does the ¹H NMR spectrum of hydroboration product show?
A signal for the alcohol proton, plus upfield CH₃ and CH₂ signals consistent with the product structure.
94
New cards
What supports the regioselectivity of the reaction in NMR?
The alcohol proton appears on the less substituted carbon, proving anti-Markovnikov orientation.