1/21
Looks like no tags are added yet.
Name | Mastery | Learn | Test | Matching | Spaced | Call with Kai | Chat |
|---|
No analytics yet
Send a link to your students to track their progress
E field in conductors is =
ALWAYS 0
ΔV in conductors is =
ALWAYS 0
Equipotential surface inside conductors
Where are induced charges in conductors =
Induced charge resides ONLY on the surface; there is NO induced charge in the volume (Gauss's Law).
What is E field at surface of conductor =
ONLY perpendicular
E_tang = 0
Can positive and/or negatives charges move in conductors =
Positive charges are fixed
Negative charges can freely move, will settle on surface at equilibrium
A point charge +q is suspended in a hole inside a neutral conductor, what charges appear on the two surfaces?
−q on the inner (cavity) surface (induced from outside surface)
+q on the outer surface
E-field now exists outside conductor
Conductor boundary condition purpose and formula =
shows how E-field and induced charges change at the boundary of two mediums
E_n = ρ_s / ε₀
E_n = E normal on surface
ρ_s = surface charge density
Charge density vs. curvature on a conductor =
Smaller radius of curvature = larger surface charge density (ρ₁/ρ₂ = R₂/R₁ for connected spheres).
Why do lightning rods end in sharp points? =
Sharp = small radius of curvature → highest surface charge density there
When is surface charge density positive/negative
E_n into = ρ_s negative
out of conductor = ρ_s positive
A point charge sits above a grounded infinite conducting plane, how to find e field
Method of images: a fictitious −Q mirrored below the plane gives the same E-field ABOVE the plane
Potential on a conducting sphere due to an EXTERNAL point charge Q at distance d =
V(r = R) = V(r = 0) = kQ / d
(equidistant trick: integral of dQ over the surface = 0)
if sphere has initial charge q_net
V = [kQ] / [d] + [kq_net] / [R]
Capacitance =
C = Q / V;
Farad [F]
assumed to be isolated (only object)
amount of charge needed for a conducting body to increase potential by 1V
Capacitance of a two-conductor capacitor =
C = Q / ΔV_(2→1)
(depends ONLY on geometry and dielectric permittivity, not on Q or V)
Parallel plate capacitor =
C = εA / d = ε₀ε_r A / d
(area A, separation d, dielectric ε)
Energy stored in a capacitor =
U_e = [Q²] / [2C] = (1/2)CV²
Capacitance per unit length of a coaxial cable (inner a, outer b) =
C / L = [2πε] / [ln(b/a)]
Dielectrics in parallel (side by side) =
C = [ε₁A₁] / [d] + [ε₂A₂] / [d] = C₁ + C₂
(capacitors in parallel add)
Dielectrics in series (stacked layers d₁, d₂) =
1/C = [d₁] / [ε₁A] + [d₂] / [ε₂A] = 1/C₁ + 1/C₂
(capacitors reciprocal add in series)
Energy density of the electric field =
u_e = (1/2)D→ · E→
= (1/2)εE→ · E→
= (1/2)εE²
Moving plates with battery CONNECTED vs. DISCONNECTED =
battery connected → V fixed, use U = (1/2)CV²
battery removed → Q fixed, use U = Q²/(2C)
Capacitance of a spherical capacitor (concentric shells, inner a, outer b) =
C = 4πε₀ [ab] / [b − a]