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Base case (mathematical induction)
prove P(n0)
Induction (mathematical induction)
prove ∀k∈ℕ such that k≥n0, P(k)→P(k+1).
Assume induction hypothesis: P(k) for an arbitrary k∈ℕ such that k≥n0.
Show P(k+1).
Base case (strong induction)
prove P(n0) and possibly a few more base cases P(n0+1), P(n0+2),…,P(n0+a)
Induction step
prove ∀k∈ℕ such that k≥n0+a, (P(n0)∧P(n0 + 1)∧⋯∧P(k − 1)∧ P(k))→P(k + 1).
Assume induction hypothesis: P(j), for all j where n0≤j≤ k, for an arbitrary k∈ℕ such that k≥n0+a.
Show P(k+1).