GENETICS MODULE ONE/TWO

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Last updated 12:39 PM on 9/8/26
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module one!

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revision: 

  • DNA(template strand/anti sense  is used) to make mrna is read as codons where anticodon on tuna makes proteins by combining amino acids

  • 5’->3’ or also called N-terminus to c-terminus

  • Eukaryotic has methymini UAC 

  • Protein-E-P-A, initiation, elongation, termination

  • The catalytic activity of the ribosomes is done by the rRNA not the protein

• ⁃ Trna: aminoacyl-tRNA-synthetase

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Transfer RNAs (tRNAS) and the adaptor hypothesis and its structural shape and ISOACCEPTORS:

  • The adaptor molecule is the tuna, it is the adaptor between mrna codons and amino acids

  • Trna anticodon base-pairs antiparallel with the mrna codon

  • It has a ‘cloverleaf’ secondary structure

  • Amino acids covalently attached (esterified) to the 3’terminal adenosine (CCA end), so think of it like the 3’ end of every tuna ends in cca and the amino acid attaches to the last A. This is OF THE TRNA so what make it.

  • Esterified means when tRNA (empty) uses an atp to attach an amino acid onto it

• ⁃ Each amino acid has one or more tRNA genes that encodes tRNAS used specifically for the amino acid (isoacceptors). So many codons make one amino acid


ISOACCEPTORS:

  • A different tRNA that carries the same amino acid


<ul><li><p>The adaptor molecule is the tuna, it is the adaptor between mrna codons and amino acids</p></li><li><p>Trna anticodon base-pairs antiparallel with the mrna codon</p></li><li><p>It has a ‘cloverleaf’ secondary structure</p></li><li><p>Amino acids covalently attached (esterified) to the 3’terminal adenosine (CCA end), so think of it like the 3’ end of every tuna ends in cca and the amino acid attaches to the last A. This is OF THE TRNA so what make it.</p></li><li><p>Esterified means when tRNA (empty) uses an atp to attach an amino acid onto it</p></li></ul><p class="p1">• ⁃ Each amino acid has one or more tRNA genes that encodes tRNAS used specifically for the amino acid (isoacceptors). So many codons make one amino acid</p><p class="p1"></p><p class="p1">ISOACCEPTORS:</p><ul><li><p>A different tRNA that carries the same amino acid</p></li></ul><p></p>
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tRNA specificity there are two levels:



1. Aminoacylation = putting the correct amino acid onto the correct tRNA

Before tRNA can go to the ribosome, it needs to be loaded (charged) with an amino acid.

An enzyme called aminoacyl-tRNA synthetase does this.

There are generally 20 types of aminoacyl-tRNA synthetases, one corresponding to each standard amino acid.

For example:

Alanine → alanyl-tRNA synthetase → alanine tRNA

The synthetase has to recognise TWO things:

Correct amino acid
       ↓
aminoacyl-tRNA synthetase
       ↓
Correct tRNA
       ↓
tRNA—AMINO ACID

How does it know which tRNA is correct?

It recognises specific identity elements in the tRNA's structure. These can include:

  • the anticodon

  • bases in/near the acceptor stem

  • other characteristic bases/structural features
    Then, using ATP, it attaches the amino acid to the 3′ CCA end of the tRNA.

So:

Aminoacyl-tRNA synthetase makes sure the correct amino acid is attached to the correct tRNA.


2. Decoding = putting that tRNA at the correct mRNA codon

Now imagine the tRNA has already been loaded:


       ALANINE
          |
       3′ CCA
          |
        tRNA
          |
      ANTICODON

The tRNA enters the ribosome.

Its anticodon base-pairs with the complementary mRNA codon.

For example:

mRNA: 5′- G C U -3′
| | |
tRNA anticodon: 3′- C G A -5′
|
ALANINE

GCU codes for alanine.

Therefore, when this tRNA's anticodon matches GCU, the ribosome accepts the tRNA and alanine gets added to the growing protein.

So there are TWO different types of specificity:
Aminoacylation:

"Does this tRNA have the correct amino acid attached?"

Controlled by → aminoacyl-tRNA synthetase

Decoding:

"Is this tRNA matching the correct mRNA codon?"

Controlled by → codon–anticodon base pairing in the ribosome

So the full process is:

amino acid → loaded onto correct tRNA → tRNA anticodon finds matching mRNA codon → ribosome incorporates that amino acid into the protein








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anticodon loop, draw a diagram

  • Remember 5’ to 3’

  • Interact through Hydrogen bonds

3rd base in codon is recognised by 1st base in anticodon 




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ABNORMAL BASES IN TRNAS:

  • Trnas have many abnormal bases/nucleotides that are created via post-transcriptional modification

  • Modified bases allows TRNA to be more flexible of function then only being able to use g,c,a,u

  • There are 80 known ones

  • And the best known one is INOSINE (I)

    • This is created by deamination of adenine into hypoxanthine

    • Forms hydrogen bonds with C,A, and U but not G (H, idk y h but its just to say not g…), this is important when in position 34 of a TRNA explain later…


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Terriary TRNA STRUCTURE:


  • A common l shaped structure enables TRNAS to fit into ribosomes

• ⁃ Modified bases assist tertiary structure formation


<ul><li><p></p></li></ul><ul><li><p>A common l shaped structure enables TRNAS to fit into ribosomes</p></li></ul><p class="p1">• ⁃ Modified bases assist tertiary structure formation</p><p class="p1"></p>
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HOW DID THEY GET EVIDENCE OF TRIPLET CODE??? as in that three account of one amino acid, In vitro transition studies

first s cientists know that dna→mrna→ protein

and then mrna told ribosome which amino acids to add.

But they didn't yet know: which 3-base codon = which amino acid?


  • The first evidence was trinucleotide binding of aminoacly-trnas to ribosomes

  • they did the bottom experiment when a short rna of only three cnucleotides ro one codon, so they kno whwat codon codes for what. they just put a lot of trna’s in it to see which will go to it.


  • The second was the cell-free (in vitro) protein synthesis experiment by nierenberg and matthael; khorana et al):

    • They wanted to make proteins outside a living cell, so they could control every ingredient and test their ideas. 

    • They know protein-making needs: amino acids, tuna, ribosomes, energy (ATP/GTP), and an mRNA “instructions” template.

    • They did this:

      • Smashed open e-coli bacteria using an abrasive powder to release everything inside

      • Spin it in a centrifuge to remove solid junk like broken cell walls

      • Keep the leftover liquid (cell lysate), which sill has trns, ribosomes, and enzymes floating in it

      • They added an enzyme (DNase) to destroy any DNA so that the cell can’t make its own new RNA this was only the mRNA the scientists add will be used. Stops de novo RNA synthesis (which is when an rna ploymerase builds a new rna strand directly from indivisual nucleotide building blocks without a preesisiting primer

      • And any leftover natural RNA breaks down on its own cause RNA doesn’t last long

      • Now they added their own synthetic MRNA sequence, plus amino acids which one of is radioactively labeled (14C) so they can track it. so they did this experiment many times adding phenylalanine then alanine ttcetc and which ever one showed up uuu is what codes for it

• ⁃ For the first experiment they used this for was poly(U) RNA template (UUUU) where it had all 20 amino acids plus one 14C radioactively labeled. 20 seperate experiments conducted in parallel



so that helped find codon+trna used.









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results

 have one that worked and one that didnt

  • so basically the mrna only takes the right amino acid which are the ones we added in. hense if not radioactive then it wasnt used


  • Left side

  • The 14C is attached to alanine

  • Poly-u MRNA gets fed into the ribosome

  • The ribosome builds a protein but it turns out to be PHE, PHE, PHE all phenylalanine

  • Since no alanine was used at all, the radioactive tag never shows up in the final protein

  • So the purified protein is not radioactive which means poly-u does not code for alanine




  • Right side

• ⁃ Proteins made the the the and since phenylalanine is the labelled one every one made has a radioactive tag so this does code for it 



<p>&nbsp;have one that worked and one that didnt</p><ul><li><p>so basically the mrna only takes the right amino acid which are the ones we added in. hense if not radioactive then it wasnt used</p></li></ul><ul><li><p></p></li></ul><ul><li><p>Left side</p></li><li><p>The 14C is attached to alanine</p></li><li><p>Poly-u MRNA gets fed into the ribosome</p></li><li><p>The ribosome builds a protein but it turns out to be PHE, PHE, PHE all phenylalanine</p></li><li><p>Since no alanine was used at all, the radioactive tag never shows up in the final protein</p></li><li><p>So the purified protein is not radioactive which means poly-u does not code for alanine</p></li></ul><p class="p2"></p><ul><li><p></p></li></ul><ul><li><p></p></li></ul><ul><li><p>Right side</p></li></ul><p class="p1">• ⁃ Proteins made the the the and since phenylalanine is the labelled one every one made has a radioactive tag so this does code for it&nbsp;</p><p class="p1"></p><p class="p1"></p>
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lecture two recap

nitiator tRNA = "I'm bringing Met to START the protein."

Elongator tRNA = "I'm bringing Met to ADD to an already-growing protein."

<p><strong>nitiator tRNA = "I'm bringing Met to START the protein."</strong></p><p><strong>Elongator tRNA = "I'm bringing Met to ADD to an already-growing protein."</strong></p>
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ADDING ONTO TO EXPERIMENT BUT THEN WHAT ABOUT THOSE WHICH ARE GUGUGUGU ETCETCETC


  • ac question


  • You dont know where it starts, at the g? Or the u?

  • So firstly you narrow it down to two options, so either valine (GUG OR UGU) or cysteine (GUG or UGU), do the three reading frames way

  • Then you try different repeating sequences with there codons instead gugguggug or ugguggugg or ggugguggu etc. valine showed up (GUG,UGG,GGU) AND TRYPTOPHAN (GUG,UGG,GGU) AND GLYCINE (GUG, UGG, GGU), you can just choose one gugguggug etc cause when u do the three reading frames it takes them all into account

  • Then if you combine the two.

  • Experiment one: GUG (valine r systeine)

  • Experiment two: valine, try, glycine

• ⁃ Only similar is valine so it has to be that

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prac quesiton



• ⁃ It is using RNA and not DNA because the experiments during this time only knew it came from RNA


nswer should look liek this:


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Initiation and termination codon:

  • Initiation start codon: for eukarAUG which codes for met but for prokay its fmet for other species

  • Termination stop codon: UAA, UAG, UGA


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DEGENERACY:

  • Most amino acids are specified by 2-4 codons, and most degeneracy is in the 3rd base of the codon


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Deviations from the standard genetic code:

  • In human mitochondria, AUG, AUA and AUU can all act as start codons. UGA encodes tryptophan instead of stop. AUA encodes methionine instead of isoleucine and AGA and AGG encode stop instead of arginine THIS ISNT MARKED!!!! THE OTHER TWO ARE

  • Prokaryotes use GUG or UUG too as an alternative for AUG doe fmet, but only at start

  • CUG encodes serine instead of leucine in candida cylindracea and some other candida species (Candida albicans)


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WOBBLE:

  • Each amino acid has its only TRNA GENE

  • Standard genetic code has 64 codons

• ⁃ 61 of these specify the 20 amino acids (the other r stop/start). Does this mean that there must be 61 TRNA genes, no. Some TRNA can do many different codons 





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hypothesis:


THE WOBBLE HYPOTHESIS:

  • By Francis crick in 1966 to explain how one TRNA molecule could recognise one degenerate codon

  • The hypothesis: the base at the 5’ end of the anticodon (position 34) can wobble’ meaning can be different codons (explained better below)

• ⁃ Extra base-pair options compared to standard A—U AND G—C




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consequences




WOBBLE CONSQEUNCES:

  • Theoretical minimum of 32 tuna species to read 61 CODONS (31 unique anticodons + 1 initiator TRNA)

  • E.COLI: 41 anticodons and around 45 TRNA species

  • mitochondria: 22 TRNA species; super wobble lets U34 sometimes pair with A,G,C,U

  • This is limited by the fact that TRNAS must only recognise codons for a single amino acid, otherwise translational fidelity would be compromised EXPLAINED BELOW


EXAMPLE OF BAD PART OF WOBBLE: REMEMBER TO LOOK AT THE WHOEL BOX!!! 



The bottom ones can’t happen as it represents another amino acid!!!!


in exma:








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EXAMPLE OF WOBBLE:


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things u need to know:


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DNA STRANDS NAMING:

  • TOP STRAND OF DNA IS USUALLY SHOWN (CODING/non-template/crick/sense/forward STRAND) 5’ TO 3’

  • The other strand is called noncoding/reverse/antisense/watson/template, BOTTOM IS USED TO MAKE MRNA CAUSE IT TECHNICALLY IS A CODING STRAND


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recap of lecture 3


<img src="https://assets.knowt.com/user-attachments/c106d493-288e-40ab-adf8-a8677a0534c7.png" data-width="50%" data-align="center" style="display: block; width: 50%; margin-left: auto; margin-right: auto;"><p></p>
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READING FRAME:

  • Refers to the position at which you start reading nucleic acid in 3 nucleotide codons

  • If you start at the first nucleotide, that is reading frame +1, reading frame +2 starts at nucleotide 2 and reading frame +3 at nucleotidee 3, etcetcecet

• ⁃ As mrna is single stranded it has three reading frames which dan has 6

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OPEN READING FRAME (ORF):

 - traditional definition: a region in any reading frame that begins with a start codon (ATG) and ends with a stop codon

DNA start codon = ATG

  • If transcribed an ORF might be translate to produce a protein


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IN EXAM!!!!!:

  • N-terminal amino acid means (fmet or met), which one? The one WITHOUT STOP!! If it said the ENITRE open reading frame then the one w start and stop

• ⁃ Base substitution (nonsense mutation), shorted 




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words to know:


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MUTATION:

  • It is a change in the genetic material and the process producing it

  • Heritable at cell division; only offspring-founding lineages transmit to next gen

  • Ultimate source of new varitation for evolution

  • Recombination rearranges genetic variability into new combination

  • Natural selection raises the frequency of fitter variants in the current environment


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MUTANT:

  • An organism with a non-wild-type genotype (and often phenotype)

  • Wild type (WT) = the standard/reference form normally used for comparison.

  • Mutant = has a genetic change compared with WT.

  • The mutation may or may not change the observable phenotype.


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MUTATION IS INEVITABLE: two different ways DNA can get damaged spontaneously

  • Spontaneous cytosine deamination (C loses a amino group turning it into a U)-> uracil (U:G mismatch, cause u doesn’t normally belong under DNA)

  • so U SINT IN DNA BUT SOEMTIMES A C CAN TURN INTO U WHICH THEN WHEN TURNED INTO MRNA IS AN A→T

    • Errors occur during replication (unexcused uracil pairs with A) and repair. So c-g turns into u-g which replicates into a mutation of t-a (BASE SUBSTITUTION MUTATION)


  • Spontaneous hydrolysis of bond linking purines (G and A) to deoxyribose

    • Purines are a and g and normally these are attached to the deoxyribose sugar

    • A/G-SUGAR-PHOSPHATE

    • Sometimes the bond connecting the purine base to the sugar breaks spontaneously so the a or g is literally lost form the dan so now you have

    • Sugar-no base- sugar this is called an apurinic site

    • It is estimated 10,000 purines lost/day/human, and substitutions can occur when these uninformative apurinic sites are replicated

    • Since it is blank it may insert a incorrect nucleotide (substitution mutation)


  • REMEMBER DNA IS NOT TOALLY CHEMICALLY STABLE, PROOFREADING AND REPAIR MACHANISMS WILL REPAIRS MOST MISTAKES BUT NOT ALL. ALSO FIDELITY OF REPLICAITON IS NOT 100%

• ⁃ mutations are inevitable, mutagens just increase the frequency 

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FOUR TYPES OF MUTATIONS:


  1. Spontaneous

  2. Induced

  3. Germinal

  4. Somatic 


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  • Spontaneous:


  • Spontaneous: arise endogenously through replication errors, the intrinsic chemical instability of dan, OXIDATIVE DAMGE ETC 

  • WE TALKED ABT TI ABOVE, it is internal/natural DNA damage


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  • INDUCED:


  • ARISE WHEN LESIONS FROM MUTAGENS ESCAPE CORRECT REPAIR

  • Caused by something external

  • Uv radiation chemical etcetce

  • lesion= dna damage

  • Usually is repaired but sometimes isn’t

  • Mutagen->dna dmage-> dna repair-> fixed

  • Mutagen-> dan besoin-> Dailed to repair-> mutation 


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• ⁃ GERMINALL

OCCUR IN GERM-CELL PRECURSORS AND WILL BE TRANSMITTED THROUGH DERIVED GAMETES; ALL OFFSPRING WILL THEN CARRY THEM

  • This is where the mutation occurs

  • Occurs in germ-cell precursor, the cells which will produce sperm or eggs

  • Parents gremlin mutation-> gamete-> child-> mutation int he child’s cells


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  • SOMATIC: 



  • SOMATIC: occur in somatic cells; confined to the clone descended from that cell, not transmitted to offspring, but can drive cancer. 

  • Normal body cells

  • Normal skin cell-> mutation-> ,utaed skin cell-> cell division-> Manu descendant cells

  • Can cause cancer

  • Call -> mutation0> uncontrolled divsiion-> cancer/tumour


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PRE-EXISITING MUTANTS: THE EXPERIMENT

  • Replica plating was used to identify the appearance f resistance in proveiously anti-biotic-sensitive Esherichia coli prior to treatment with the drug

  • Stress does not direct which mutation occurs, it selects among variants already present



  1. Start with culture: a bacteria culture (no streptomycin (antibiotic) exposure yet) is grown from a liquid tube

  2. Master plate: the bacteria are spread onto plate with no streptomycin, so colonies grow in fixed, identifiable positions. A valvet-covered taped is pressed onto this ‘master plate’ the fine hairs of the velvet pick up cells from each colony like a rubber stamp

  3. Cells stick to the velvet: because the velvet touched every colony in the exact same spatial layout, it now carries a ‘fingerprint’ copy of the last plates colony pattern

  4. Replica stamping: the velvet is pressed onto new plates: one containing streptomycin, one without. Since the velvet preserves the spatial arrangement, each new plate ends up with colonies in the same positions as the original master plate.

  5.  Selection reveals pre-existing resistance: On the streptomycin plate, almost all colonies die, except one or two that happen to carry a resistance mutation. Critically, when researchers go back to the master plate (which was never exposed to streptomycin) and pick cells from that exact same spot, those cells are also resistant.


So what does that prove? The resistance wasn't caused by the antibiotic — it was already there, sitting in the population by random chance (mutation), before the antibiotic ever showed up. The antibiotic didn't create resistant bacteria; it just killed off everything that wasn't already resistant, revealing the ones that were.




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STARCVATION, SLECTION, AND MUTAITON IN MIRCOBOES: DRAW A GRAPH AND LABEL

This is in a flask or plate with minted nutrients:

Lag phase: Bacteria are just settling in, adjusting to their environment. Population size is flat — barely any division happening yet.

Log phase: Explosive growth. Cells are dividing rapidly, doubling again and again, food is abundant. This is the steep upward curve.

Stationary phase: Growth stalls out and flattens. Nutrients are running low, waste products are building up, and the environment is getting stressful. New cell division roughly equals cell death, so the population size plateaus


  • Here's the twist: in that stressful, nutrient-starved stationary phase, bacteria (and fungi) actually start mutating faster than normal. This is sometimes called "stress-induced mutagenesis."

  • Why is this interesting/important? It might sound like it contradicts the Lederberg experiment (where mutations were shown to happen randomly, independent of the stress/selection agent). But look closely at the second bullet — it clarifies that this isn't a contradiction:

  •  "Mutations stay random with respect to benefit, but could create a mutant with a selective advantage in a certain environment."

  • This is the key distinction:

  • The rate of mutation can go up under stress (more mutations happening overall when times are tough).

• • But which mutations occur is still random — the stress doesn't "aim" the mutations toward a useful outcome. It's not that stress directs bacteria to evolve resistance specifically. It just cranks up the overall mutation dial, and by chance, some of those random mutations might happen to be useful in that environment


STRESS EFFECTS HOW MUCH NOT WHAT!!

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REVERTING A MUTANT PHENOTYPE:

  • Forward mutation: wilf-type to mutant allele

  • Reverse mutation (reversion): a secondary mutation which restores wild-type phenotypes

    • Back mutation: restores the wild-type sequence

    • Suppressor mutation: compensating change elsewhere; first mutation persists


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vocab





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MULTIGENIC CONTROL OF PHENOTYPES: how to stop phenotypes from happening bad and good





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CONDITIONAL LETEHAL MUTATIONS: permissive vs restrictive AND NEXT THREE SLIDES ARE TYPE OF CONDITION MUTANTS



  • Conditional lethal mutations: a normal mutation might make a cell unable to survive all the time/A conditional lethal mutation is a mutation that is only lethal under certain conditions.


  • Two conditions: permissive and restrictive. Permissive is the mutation is okay and cell survives//grows

  • restrictive condition is mutation causes a problem and cell dies/cannot grow

    • no growth or death in restrictive conditions

    • Viable in permissive conditions

    • Grown under the permissive condition, then shifted to stricture conditions to reveal the phenotype


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• ⁃ Auxotophes: vs proto


  • Auxotophes:cannot make an essential metabolite that prototrophs synthesise ; they grow only if it is supplied, so minimal medium is restrictive

    • An auxotroph has a mutation that means it cannot make an essential substance itself.

    • For example, imagine a mutant bacterium cannot make amino acid X.

  • So for an auxotroph:

  • X supplied = permissive

  • X not supplied = restrictive


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• ⁃ Temperature- 



  • Temperature- sensitive mutants: grow only at permissive temperatures

  • 25°C → 🟢 grows

  • 37°C → 🔴 doesn't grow

• ⁃ The lower temperature might be the permissive condition, while the higher temperature is the restrictive condition.

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  • Suppressor



  • Suppressor- sensitive mutants are viable only when a second genetic factor (a suppressor) is present

  • Mutation A → causes lethal problem

  • But:

  • Mutation A + suppressor mutation → problem is compensated → 🟢 survives

Therefore:

  • Suppressor present → permissive → survives

  • Suppressor absent → restrictive → dies


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4 main types of mutations





  • wildtpye: IS THE original one

  • Substation : one is changed

  • Inversion-; flipped aourd 180

  • Insertion: put in

• ⁃ Deletion: taken out


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mutation types again




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HOW TO EXPLAINC ONSERVATIVE VS NONE CONCERVATION:amino acids






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review lectyre 4


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TAUTOMERIC SHIFTS AFFACT: TYPE OF MUTATION

  • SPONETEOUS BASICALLY HYDROGEN ATOM BECOES WEIRD FORM AND BECOMES A DIFFERENT TAUTOMER, LIKE THE G BECOMES WEIRD SO IT CAN NOW PAIR W A now it is a t-a pair etc. THIS IS ISOMERISATION

  • This shift is when a hydrogen atom temporarily moves to a different position within a dan base

  • Cause the doubles bonds/electrons to change

  • So it become a different tautomer (different form of same molecule)

  • Means c can also pair w a etcetc which when replicated could turn into a mutaition of t-a

  • Isomerisation (which it changes to a similar one) caused by a reversible change in the location of hydrogen atom in a base

• ⁃ By modifying the pairing of nucleotides, tautomeric shift can cause substitution mutation





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TYPES OF SUBSTITUTION: base substation where ne dan base is replaced by another, two types

transitions:

Pyrimidine-> pyrimidine

Purine-> purine


TRANSVERSIONS:

Pyrimindine->purine

Purine->pyrimidine



Although there are 8 possible transversions and only 4 possible transitions, transitions are more common!!

Transitions

There are only two possible same-group swaps:

A G
C T

That's 4 possible directional substitutions if you count each direction:

  • A → G

  • G → A

  • C → T

  • T → C

= 4 transitions

Transversions

Each purine can change into either of the two pyrimidines:

A → C
A → T
G → C
G → T

And each pyrimidine can change into either purine:

C → A
C → G
T → A
T → G

= 8 transversions

So:

4 transitions
8 transversions



<p>transitions:</p><p class="p1">Pyrimidine-&gt; pyrimidine</p><p class="p1">Purine-&gt; purine</p><p class="p1"></p><p class="p1">TRANSVERSIONS:</p><p class="p1">Pyrimindine-&gt;purine</p><p class="p1">Purine-&gt;pyrimidine</p><p class="p1"></p><p class="p1"></p><p class="p1">Although there are 8 possible transversions and only 4 possible transitions, transitions are more common!!</p><p class="p2"><strong>Transitions</strong></p><p class="p1">There are only two possible same-group swaps:</p><p class="p1"><strong>A </strong><span data-name="left_right_arrow" data-type="emoji">↔</span><strong> G</strong><br><strong>C </strong><span data-name="left_right_arrow" data-type="emoji">↔</span><strong> T</strong></p><p class="p1">That's <strong>4 possible directional substitutions</strong> if you count each direction:</p><ul><li><p>A → G</p></li><li><p>G → A</p></li><li><p>C → T</p></li><li><p>T → C</p></li></ul><p class="p1">= <strong>4 transitions</strong></p><p class="p2"><strong>Transversions</strong></p><p class="p1">Each purine can change into either of the two pyrimidines:</p><p class="p1">A → C<br>A → T<br>G → C<br>G → T</p><p class="p1">And each pyrimidine can change into either purine:</p><p class="p1">C → A<br>C → G<br>T → A<br>T → G</p><p class="p1">= <strong>8 transversions</strong></p><p class="p1">So:</p><p class="p1"><strong>4 transitions</strong><br><strong>8 transversions</strong></p><p class="p1"></p><p class="p1"></p>
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core concepts




<p></p><p></p><p></p>
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mutagens 5-BROMOURACIL

MUTAGENS: a base ANALOUGE (structure if like a normal dan base so it is mistaken as one) called 5-BROMOURACIL (chemical mutagen)

  • Turns in keto and enrol form

  • Keto form likes to pair with A (acts as t)

  • ENOL with G (acts as c)

• ⁃ When replicated it can switch into the other form meaning c-g turns into a-t which isn’t good



<p>MUTAGENS: a base ANALOUGE (structure if like a normal dan base so it is mistaken as one) called 5-BROMOURACIL (chemical mutagen)</p><ul><li><p>Turns in keto and enrol form</p></li><li><p>Keto form likes to pair with A (acts as t)</p></li><li><p>ENOL with G (acts as c)</p></li></ul><p class="p1">• ⁃ When replicated it can switch into the other form meaning c-g turns into a-t which isn’t good</p><p class="p1"></p><p class="p1"></p>
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NIRTROUS ACID

  • CAUSES OXIDATIVE DEAMINATION OF BASES:

  • Deamination is removing an amine group (-NH2) from a base

  • This acid does this, converting on base into a different one


Left side:

  • Cytosine turns into uracil 

  • Uracil acts like thymine, meaning it pairs with a not guanine so in the next replication the c:G will turns into t:a

Right:

  • Adenine turns to hypoxanthine

  • Adenine also has an amine group that nitrous acid can remove turns into hypo.

• ⁃ So you get h:C but not he next replication Hypo acts like G directs a c to be inserted so the A:T pair becomes a G:C





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Mutagenesis by ultraviolet radiation

  1. Uv light can react with cytosine to form a photo hydrate, becomes chemically unstable and prone to deamination

  • Converts to uracil (like nitrous acid)

  • C:g-> t:a

  • Cytosine photo hydrate can deanimate to uracil, giving C->T transition 

  1. UV light hits two adjacent pyrimidines on the same DNA strand, that means nay of the TT,TC,CT,CC in sequence can cause a abnormal covalent bonds to form between each other making a cyclobutane pyrimidine dimer (CPD).This is the big one.

Pyrimidines are C and T.

So if two pyrimidines are next to each other on the SAME DNA strand, such as:

TT
TC
CT
CC

UV can cause abnormal covalent bonds to form between them.

If the damage isn't repaired, the cell may use special translesion synthesis (TLS) polymerases.

These polymerases can:

replicate ACROSS the damaged site

which lets replication continue.

But some TLS polymerases are less accurate than normal replicative DNA polymerases, so there's a greater chance of inserting the wrong nucleotide opposite the damaged bases → mutation.





Two neighbouring bases get chemically welded together sideways forming a little four-sided ring. 

  • Normal dna polymerase can’t read through the leision, to get past it translation synthesis polymerase are used these are sloppier and error prone polymerase. They often in sort wrong bases which is a big issue

• ⁃ Adjacent pyridines (TT,TC,CT,CC) form cyclobutane dimers that stall replicative polymerases and force translesion synthesis




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INTERCALATION OF AN ACRIDINE DYE CAUSE FRAMESHIFT MUTATIONS:





PROFLAVIN IS AN EXAMPLE:


The key is: proflavin itself doesn't become a DNA base. Instead, by sitting between bases, it can cause DNA polymerase to insert an extra nucleotide or skip/delete a nucleotide during replication.

So:

Proflavin → intercalates between bases → distorts DNA → replication error → insertion or deletion

Why does that cause a frameshift?

Remember that mRNA is read 3 bases at a time:

ATG | AAA | CCG | TTT

If you insert ONE base:

ATG | TAA | ACC | GTT | T...

Everything after the insertion is now grouped differently.

That's a frameshift.




  • Sightly positively charged size, which can slip in the middle of the bases as shown in photo. Influxes the helices, it leads to the addition and deletion of the bases-> changes reading frame. This happens when unwinding, it gets int he way and gets rid or adds bases 

• ⁃ Insertion/deletion of a number of base pairs not divisible by three alters the reading frame of he gene distal to the site of mutation

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HOW INSERTIONS AND DELETIONS (INDELS) AFFECT PHENOTYPE:

  • • ⁃ They cause frameshift mutations

  • Consider a single insertion in an ORF:


  • CALLED FRAMESHIFT MUTATIONS

    • Occur only in ORF’S

    • Usually give nonsense mutation (premature stop)

    • Usually encode nonsense proteins




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EFFECT OF IONISING RADIATION, HYDROXYLAMINE AND ALKYLATING AGENTS


1. Ionising radiation

Ionising radiation has enough energy to remove electrons from molecules, which can severely damage DNA.

One major consequence is double-strand breaks:

DNA ========   ========
              ↑
        both strands broken



The cell tries to repair the break, but if the pieces are rejoined incorrectly, you can get:



Deletion → DNA piece is lost

Inversion → DNA piece is put back flipped

Translocation → DNA piece attaches somewhere else, often another chromosome



So:



Ionising radiation → DNA breaks → imperfect repair → large chromosome changes





2. Hydroxylamine

Hydroxylamine is a chemical mutagen that modifies cytosine.



Normally:



C pairs with G



After hydroxylamine modifies C → N4-hydroxycytosine, the modified C can mispair with A.



After replication, this can become:



G:C → A:T



That's a transition because C→T and G→A stay within their respective base classes.



So memorize:



Hydroxylamine → modifies C → G:C → A:T transition





3. Alkylating agents

These chemicals add alkyl groups onto DNA bases.



That can change how bases pair or damage DNA more extensively, so they can cause:



transitions, transversions, and chromosome aberrations.



So they're less specific than hydroxylamine.







  • Ionising radiation causes double stranded breaks, repair can cause deletions, inversions and translocations.

  • It has enough energy to knock electrons out of molecules, comes broken.  Can try to repair it but it isn’t always perfect


  • Hydroxyl amine converts cytosine to N4-hydroxycytosine, pairing with A, results in G:C-> A:T transitions

  • Chemical mutagen that specifically modifies cytosine (C) so again G:C->A:T


  • Alkylating agents are chemicals that donate alkyl groups to other molecules, inducing transitions, transversions, and gross chromosome aberrations

  • Are chemicals that add an alkyl group to DNA bases

• ⁃ Transitions/transversions or Chromosome aberrations (changes in number of physical structure of chromosomes

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SUPPRESSOR MUTATIONS: definitions and how it was discovered?

Definition:

When a second mutation event masks the deleterious effects of a first mutation

Discovery: from studies in bacterial genetics

  • means it can make leucine by itself

  1. Start with wild-type bacteria that are Leu+

    • Leu+ means they can make leucine themselves.

  2. Mutate the Leu+ bacteria and select a mutant that is Leu-

    • Leu- means it cannot make leucine itself.

    • This is an auxotroph.

  3. Grow the Leu- mutant on medium containing leucine

    • It needs leucine supplied because it cannot produce its own.

  4. Mutate the Leu- cells again

  5. Plate the cells on medium without leucine

  6. Most Leu- cells cannot grow

    • But if a second mutation restores the ability to grow, that cell now has a Leu+ phenotype

  7. Select the Leu+ colonies that appear

    • These are called revertants because their phenotype has returned to Leu+.

  8. Sequence/compare the relevant genes in:

    • wild-type Leu+

    • first mutant Leu-

    • second mutant/revertant Leu+

  9. Compare the sequences:

    • If the original mutation has been corrected/gonereversion/back mutation

    • If the original mutation is still there, but there is a second mutation that compensates for itsuppressor mutation

So the key sequence is:

Leu+ → first mutation → Leu- → second mutation → Leu+ phenotype again

And the definition:

Suppressor mutation = a second mutation that masks or compensates for the harmful effect of the first mutation, while the original mutation remains.


What can happen:



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Intragenic: 

Intragenic: means instead of fixing the one basic codon aadd another acidic somewhere else to cancel it



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INTRAGENIC SUPESSORE: T4 rIIB

  • When a second mutagen happens at a different site in the same gene

Classical genetic evidence fro the triplet code:

  • Proflavin used to induce frameshift in phage TA rIIB

  • RiiB function function scored by plaque assay- if inavtictaed, cant grow on esceriachia coli K12(game)

  • After successive mutational events, it was found that gain or loss of 1 or 2 bases inactive rIIB but 3 couldd store funcition

  • Genetic code must be a triplet (or a multiple of 3), non-overlapping, read from a fixed starting point


One taken out and reading frame restored: works well if the codes still code for some similar

Classical genetic evidence for the triplet code: Proflavin, an intercalating mutagen, was used to induce frameshift mutations in the rIIB gene of bacteriophage T4, whose function could be assessed using plaque assays. RiiB function function scored by plaque assay- if inavtictaed, cant grow on esceriachia coli K12(game). Researchers found that the insertion or deletion of 1 or 2 bases usually inactivated the rIIB gene because it shifted the reading frame, changing all downstream codons. However, the insertion or deletion of 3 bases could restore the reading frame and therefore restore gene function. Similarly, a +1 insertion could be suppressed by a nearby −1 deletion (or vice versa), because the second mutation restored the original reading frame; although the sequence between the two mutations was altered, the protein could still function if those amino-acid changes were tolerated. These experiments provided strong evidence that the genetic code is read in non-overlapping groups of three nucleotides (triplet codons) from a fixed reading frame.




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Intergenic supressor mutations:


Second mutation in a different gene: an extragenic supressor mutation

• ⁃ Example of 2 genes encoding a multimeric protein








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TRNA INTERGENIC SUPRESSOR MUTATIONS: A DIFF TYP amber

TRNA INTERGENIC SUPRESSOR MUTATIONS: A DIFF TYPE

so basically turned into stop (amber mutation is the example) but then the trna mutates and instead of puttign a stop codon it bputs an amino acid so it turns back to normal!

  • First mutation in an ORF is deleterious to bacterium

  • Second (supressor) mutation nia anticodon region of a TRNA gene restores full ORF fuction

  • histroical: studies of nonsense mutants in E.coli:

    • Cause shown to be point mutation in ORF producing premature STOP

• ⁃ “Amber” mutation: tyr codon converted to stop codon





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THE AMES TEST:

Ames test: The Ames test is a simple, inexpensive and highly sensitive bacterial screen for chemical mutagens, developed by Bruce Ames and coworkers, using histidine auxotrophic (His⁻) mutants of Salmonella Typhimurium. His⁻ bacteria cannot synthesise histidine and therefore normally cannot grow on medium lacking histidine. If a mutation restores a His⁺ prototrophic phenotype, the bacterium can synthesise histidine again and form a colony. Therefore, a chemical is considered mutagenic if it increases the number of His⁺ revertant colonies above the spontaneous/background reversion rate. Different strains are used to detect different types of mutations: TA1535 contains a base-substitution missense mutation (associated with a Leu→Pro loss-of-function change) and is used to detect base-substitution mutagens, whereas TA1537 contains a frameshift mutation and is used to detect frameshift mutagens. The tester strains are also made more sensitive to mutagens by having defective nucleotide-excision repair, so DNA damage is less efficiently repaired, and a defective lipopolysaccharide barrier, which increases the uptake of bulky mutagens. The test can also be performed with and without rat-liver S9 fraction. S9 contains liver metabolic enzymes because some chemicals are not directly mutagenic but are converted by mammalian metabolism into mutagenic metabolites. Therefore, an increase in His⁺ revertants only when S9 is present indicates that the chemical requires metabolic activation to become mutagenic.

In the example results, the red chemical caused no increase in His⁺ colonies on either strain, so it does not appear to be a mutagen. The blue chemical increased His⁺ colonies on the substitution-mutant plate without S9, but not on the frameshift plate, so it is a direct-acting mutagen that causes substitution mutations. The green chemical caused no increase without S9, but when rat-liver S9 was added it increased His⁺ colonies on the frameshift-mutant plate, showing that it is a promutagen (indirect-acting mutagen) that must first be metabolically activated and then causes frameshift mutations. Thus, which strain shows increased His⁺ colonies tells us the mutation type, while whether S9 is required tells us whether the mutagen is direct- or indirect-acting.


indirect: it is mutagenic with liver

direct: is it mutagenic



  • A bacterial screen for chemical mutagens

  • Bruce Ames and coworkers developed a simple, inexpensive and extremely sensitive test for the mutagenicity of chemicals using histidine auxotrophic mutants of Salmonella Typhimurium

  • Mutagens raise reversion to His⁺ prototrophy above background

    • Strain TA1535 has a missense mutation (Leu→Pro, a loss of function substitution) (case substitution)

    • Strain TA1537 has a frameshift mutation

    • Nucleotide excision-repair mutant (⇧ mutagen sensitivity)

    • Defective lipopolysaccharide barrier (⇧uptake of bulky mutagens)

THIS IS HWY TWO DIFFERNET ONES ARE USED:

ADD S9: FROM RATS INTO IT







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recap 5

knowt flashcard image
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DNA REPAIR MECHANISMS IN ECOLI AS OUR EXAMPLES: photo reactivation

  1. Photo reactivation

  • cyclobutane dimmers (LIKE Thymine dimers) are caused by the excitation energy of UV radiation

  • Fixed using light dependant repair

  • Photolayse absorbs blue light for energy

  • Cleaves thymine dimers, restoring original state

• ⁃ Doesn’t work in the dark. 



To fix it, cells that have this pathway use an enzyme called photolyase. Photolyase:

1. Recognises and binds the pyrimidine dimer

2. Absorbs blue/visible light for energy

3. Uses that energy to break the abnormal covalent bonds joining the two bases

4. Restores the bases to their normal structure

The important thing is that photolyase doesn't cut the bases out and replace them. It directly reverses the UV-induced bond.

<ol><li><p>Photo reactivation</p></li></ol><ul><li><p>cyclobutane dimmers (LIKE Thymine dimers) are caused by the excitation energy of UV radiation</p></li><li><p>Fixed using light dependant repair</p></li><li><p>Photolayse absorbs blue light for energy</p></li><li><p>Cleaves thymine dimers, restoring original state</p></li></ul><p class="p1">• ⁃ Doesn’t work in the dark.&nbsp;</p><p class="p1"></p><p class="p1"></p><p class="p1">To fix it, cells that have this pathway use an enzyme called <strong>photolyase</strong>. Photolyase:</p><p><strong>1. Recognises and binds the pyrimidine dimer</strong><br>↓<br><strong>2. Absorbs blue/visible light for energy</strong> <span data-name="sun" data-type="emoji">☀</span><br>↓<br><strong>3. Uses that energy to break the abnormal covalent bonds joining the two bases</strong><br>↓<br><strong>4. Restores the bases to their normal structure</strong> <span data-name="check_mark_button" data-type="emoji">✅</span></p><p>The important thing is that photolyase <strong>doesn't cut the bases out and replace them</strong>. It <strong>directly reverses the UV-induced bond</strong>.</p>
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  1. Base excision repair:

BER VS NER


Excision repair: DNA repair systems recognise damaged or abnormal DNA and excise (remove) the damaged region. In base excision repair (BER), an abnormal or chemically modified individual base is recognised and removed, followed by processing of the resulting site. In nucleotide excision repair (NER), a larger stretch of nucleotides surrounding a bulky, helix-distorting lesion, such as a UV-induced thymine/pyrimidine dimer, is removed by an endonuclease-containing repair complex. After the damaged DNA has been removed, DNA polymerase fills the resulting gap using the undamaged complementary DNA strand as the template, ensuring the correct sequence is restored. Finally, DNA ligase seals the remaining nick in the sugar-phosphate backbone, completing the repair.


  • A dna repair endonuclease binds to an excises the damaged base or bases

    • This recognises the error

    •  Base excision repair pathways remove abnormal or chemically modified bases with a single enzyme

    • Nucleotide excision repair pathways remove larger defects, such as thymine dimers and uses an endonuclease-containing complex (two two next slide)

  • A DNA polymerase fills in the gap, suing undamaged complementary strand of DNA as a template. This fixes it

• ⁃ Dna ligase seals the break left by dan polymerase. This glues it back




<p class="p1"></p><p class="p1"><strong>Excision repair:</strong> DNA repair systems recognise damaged or abnormal DNA and <strong>excise (remove) the damaged region</strong>. In <strong>base excision repair (BER)</strong>, an abnormal or chemically modified <strong>individual base</strong> is recognised and removed, followed by processing of the resulting site. In <strong>nucleotide excision repair (NER)</strong>, a larger stretch of nucleotides surrounding a bulky, helix-distorting lesion, such as a <strong>UV-induced thymine/pyrimidine dimer</strong>, is removed by an <strong>endonuclease-containing repair complex</strong>. After the damaged DNA has been removed, <strong>DNA polymerase fills the resulting gap</strong> using the undamaged complementary DNA strand as the template, ensuring the correct sequence is restored. Finally, <strong>DNA ligase seals the remaining nick in the sugar-phosphate backbone</strong>, completing the repair.</p><p class="p1"></p><ul><li><p>A dna repair endonuclease binds to an excises the damaged base or bases</p><ul><li><p>This recognises the error</p></li><li><p>&nbsp;Base excision repair pathways remove abnormal or chemically modified bases with a single enzyme</p></li><li><p>Nucleotide excision repair pathways remove larger defects, such as thymine dimers and uses an endonuclease-containing complex (two two next slide)</p></li></ul></li><li><p>A DNA polymerase fills in the gap, suing undamaged complementary strand of DNA as a template. This fixes it</p></li></ul><p class="p2">• ⁃ Dna ligase seals the break left by dan polymerase. This glues it back</p><p class="p2"></p><p class="p2"></p><p class="p2"></p>
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• 3. NUCLEOTIDE EXCISION REPAIR:


  1. NUCLEOTIDE EXCISION REPAIR:

  • UVRB AND UVRA , recognises the big error, then it bends it

  • UVRC cuts it, four bases in one direction, 8 in other direction

  • Then with uvrD it will unwind it and throw it away with the big error

  • Can cell can use it to make other stuff

  • Then DNA polymerase fills it in up 

• ⁃ And liagse glues it back


AAAA | BBBBBBBB-XX-BBBB | CCCCC

<p class="p1"></p><ol><li><p>NUCLEOTIDE EXCISION REPAIR:</p></li></ol><ul><li><p>UVRB AND UVRA , recognises the big error, then it bends it</p></li><li><p>UVRC cuts it, four bases in one direction, 8 in other direction</p></li><li><p>Then with uvrD it will unwind it and throw it away with the big error</p></li><li><p>Can cell can use it to make other stuff</p></li><li><p>Then DNA polymerase fills it in up&nbsp;</p></li></ul><p class="p2">• ⁃ And liagse glues it back</p><p class="p2"></p><p class="p2">AAAA | BBBBBBBB-XX-BBBB | CCCCC</p>
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  1. Mismatch repair in E.coli: BAE IS WRONG A IS A C BUT SHOUDLNT ETC


  1. Mismatch repair in E.coli: BAE IS WRONG A IS A C BUT SHOUDLNT ETC

  • This is for if a is in the spot of a c, they know which one it is, there is GATC thing on the base so it knows that the original strand. basically the orginal is methalated which the mutation base isnt so it reconigess that its not methalyted

  • MUTS recognises mismatches and binds to them to initiate the repair process

  • MUTL joins and activates MUTH

  • MUTH (an endonuclease) cuts the unmethylated strand at nearest hemimethylated (half methylated) GATC sequence; on either side of the mismatch

  • Excision requires MUTS, MUTL, UVRD (DNA helices 2, also known as MUTU, and an exonuclease

• ⁃ Dna polymwerase 3 fills in the gap and DNA ligase seals the nick

<ol><li><p>Mismatch repair in E.coli: BAE IS WRONG A IS A C BUT SHOUDLNT ETC</p></li></ol><ul><li><p>This is for if a is in the spot of a c, they know which one it is, there is GATC thing on the base so it knows that the original strand. basically the orginal is methalated which the mutation base isnt so it reconigess that its not methalyted</p></li><li><p>MUTS recognises mismatches and binds to them to initiate the repair process</p></li><li><p>MUTL joins and activates MUTH</p></li><li><p>MUTH (an endonuclease) cuts the unmethylated strand at nearest hemimethylated (half methylated) GATC sequence; on either side of the mismatch</p></li><li><p>Excision requires MUTS, MUTL, UVRD (DNA helices 2, also known as MUTU, and an exonuclease</p></li></ul><p class="p1">• ⁃ Dna polymwerase 3 fills in the gap and DNA ligase seals the nick</p>
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  1. DEALING WITH THYMINE DIMERS USING POSTREPLICATION REPAIR



  • A thymine dimer in the template strand blocks replication

  • DNA polymerase 3 restarts DNA synthesis past the dimer, leaving a gap in the nascent strand

  • RecA binds to the single strand (this is bad btw that’s y we NEED the other options to work) of DNA at the gap and meditates base pairing with the homologous segment of the sister double helix to fill the gap

• ⁃ Dna polymerase fills the gap in the problematic strand using information from the sister double helix, and dan ligase seals the nick 

so it goes back to normal one to see what it was meant to be


<ol><li><p></p></li></ol><ul><li><p>A thymine dimer in the template strand blocks replication</p></li><li><p>DNA polymerase 3 restarts DNA synthesis past the dimer, leaving a gap in the nascent strand</p></li><li><p>RecA binds to the single strand (this is bad btw that’s y we NEED the other options to work) of DNA at the gap and meditates base pairing with the homologous segment of the sister double helix to fill the gap</p></li></ul><p class="p2">• ⁃ Dna polymerase fills the gap in the problematic strand using information from the sister double helix, and dan ligase seals the nick&nbsp;</p><p class="p2">so it goes back to normal one to see what it was meant to be</p><p class="p2"></p>
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• 7. THE SOS RESPONCE IN E.COLI

7. SOS response in E. coli

  • Replication-blocking DNA damage causes DNA polymerase III to stall at a lesion.

  • Stalling leaves/exposes single-stranded DNA (ssDNA).

  • RecA binds/coats the ssDNA, forming an activated RecA* filament.

  • RecA* stimulates the self-cleavage/inactivation of LexA.

  • Normally, LexA dimers bind SOS boxes in the promoters of SOS genes and repress their transcription.

  • When LexA is inactivated, repression is removed → SOS genes are expressed.

  • The SOS response includes translesion DNA polymerases, such as DNA polymerase V, which can replicate across lesions that normally block DNA polymerase III.

  • DNA Pol V is low-fidelity and lacks proofreading, and damaged bases may provide poor/no reliable coding information. Therefore, it can insert incorrect nucleotides.

  • Translesion synthesis (TLS) allows replication to continue despite the lesion, increasing cell survival, but it can also introduce mutations.


  • Replication-blocking DNA damage (a lesion) activates the SOS respond

    • Dna polymerase V bypasses lesions that stall DNA polymerase 3; Pol V lacks proofreading and lesions are non-intructive

    • Translation synthesis fills these gaps but tolerates lesions, leaving mutations

  • lexA dimers normallin bind SOS boxes in SOS gene promoters, repression transcription

  • Stalled replication exposes single-stranded DNA which recalls coats to form a filament (ReA*)

  • This activates RECA which stimulates LEXA to inactivate itself, turning on SOS


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RECOMBINATION: HOMOLOGOUS

  • Recombination between homologous DNA molecules involves numerous enzymes, that clease, unwind. Stimulate single-strand invasions of double helices, repair and join strands of DNA

  • In most eukaryotes crossovers mature within the synaptonemal complex during prophase of meiosis I

  • Crossing over involves the breakage of parental chromosomes, rejoining the parts in new combinations through the formation and resolution of a Holliday junction

  • The Holliday model is one of the most widely supported explanations of the molecular basis of recombination

• ⁃ LOOK VIDEO LECTURE 6: 00:29:00


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holiday model/

CHI STRUCTURE: OR HOLLIDAY INTERMEDIATE:

Order of the Holliday model: Homologous chromosomes first pair and align with one another. An endonuclease makes single-strand breaks (nicks) at corresponding positions in the two homologous DNA molecules. Helicase unwinds the DNA, exposing the cut single strands, and a RecA-type protein promotes strand invasion, where each exposed strand pairs with the complementary sequence on the other homologous DNA molecule. This causes strand exchange, and DNA ligase joins the exchanged strands, producing a crossed DNA structure called a Holliday junction. The Holliday junction can then be resolved by an endonuclease cutting the crossed strands, followed by DNA polymerase filling any gaps and DNA ligase sealing the nicks. The DNA molecules separate, producing recombinant chromosomes containing new combinations of parental DNA.













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EVOLUTION OF GENE CONCEPT: 


A mutation in a particular gene can cause a defect in a particular enzyme, blocking a specific step in a metabolic pathway and causing characteristic metabolites to accumulate or become deficient.

  1. GARROD: ONE GENE- ONE METABOLIC BLOCK:

  • In born errors of metabolism is  the first book made

  • This is common is inbreding: the mutations below

  • Mutations in homogentisic acid oxidase leads to the production of black urine, kidney stones, cartilage damage and heart disease

  • Discovery of the first recessive allele in humans

  • Mutations in phenylalanine hydroxylase cause mental impairment, light hair color, and the presence of metabolites in blood and urine


<p></p><p class="p2">A mutation in a particular gene can cause a defect in a particular enzyme, blocking a specific step in a metabolic pathway and causing characteristic metabolites to accumulate or become deficient.</p><ol><li><p>GARROD: ONE GENE- ONE METABOLIC BLOCK:</p></li></ol><ul><li><p>In born errors of metabolism is&nbsp; the first book made</p></li><li><p>This is common is inbreding: the mutations below</p></li><li><p>Mutations in homogentisic acid oxidase leads to the production of black urine, kidney stones, cartilage damage and heart disease</p></li><li><p>Discovery of the first recessive allele in humans</p></li><li><p>Mutations in phenylalanine hydroxylase cause mental impairment, light hair color, and the presence of metabolites in blood and urine</p></li></ul><p></p>
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  1. BEADLE AND TATUM: ONE GATE- ONE ENZYME



  • Proposed that biosynthesis of essential metabolites is under genetic control

  • Mutations in genes involved in biosynthesis of metabolites would produce strains with additional growth- factor requirements

  • Beadle and Tatum demonstrated that one mutation resulted in the loss of one enzyme activity

  • The experiment:


1. They used the fungus Neurospora crassa.
Normal wild-type Neurospora can grow on minimal medium because it can synthesise all the metabolites it needs.

2. They exposed the fungus to a mutagen.
This created random mutations in its genes.

3. They allowed the fungus to undergo sexual reproduction and collected haploid spores.
The fact that the spores were haploid was really useful because each gene only had one copy. So if that copy contained a recessive mutation, its effect could be seen immediately.

4. They first grew the mutants on complete medium.
Complete medium contains lots of nutrients, vitamins and amino acids, so even mutants that couldn't synthesise something themselves could still survive.

5. They then tested each mutant on minimal medium.

Most could grow:

Minimal medium → grows → can make everything it needs.

But some couldn't grow:

Minimal medium → no growth → mutation has probably blocked a metabolic pathway.

6. They added specific nutrients to figure out what was missing.

For example, suppose a mutant couldn't grow on minimal medium:

Minimal medium

But then:

Minimal + vitamin X → grows

That tells you the mutation prevented the fungus from making vitamin X (or something in that pathway).

By studying many mutants, Beadle and Tatum found that particular mutations could eliminate particular enzyme activities.

The conclusion

This led to the one gene–one enzyme hypothesis:

One gene controls the production/function of one enzyme, and that enzyme controls a particular step in a metabolic pathway.

So:

Gene mutation → enzyme doesn't work → metabolic step blocked → required product isn't produced → organism needs that product supplied externally.


Why was this such a big deal?

At this time, scientists didn't yet know that DNA was the genetic material. Proteins were still considered strong candidates for the hereditary material.

• ⁃ Fungus used: mutengenised it, grew it up, get them to make the sexual structure (like a volcano), pulled out haploid the spores from int here, plate it out, and see if they have phenotypes, tested after it grew to see if it’d grow properly even tho mutenegenised, one dint work it needed vitamin, when one is added it worked. They did this again and again again




REMEMBER AT TGIS TIME NOONE KNEW DNA WAS THE GENES WE THOGUTH PROTEIN

  • The pre-1940 beads-on-a-string concept

    • The gene was thought to control the inheritance of one attribute or phenotype

    • The gene was not thought to be subdivisible by recombination, and was therefore the smallest unit of genetic material that could be mutated


  • The modern concept of the gene

    • Controls synthesis of one polypeptide chain or RNA molecule

    • The nucleotide pair is the smallest unit that can be mutated; it cannot be subdivided by recombination 


<ol><li><p></p></li></ol><ul><li><p>Proposed that biosynthesis of essential metabolites is under genetic control</p></li><li><p>Mutations in genes involved in biosynthesis of metabolites would produce strains with additional growth- factor requirements</p></li><li><p>Beadle and Tatum demonstrated that one mutation resulted in the loss of one enzyme activity</p></li><li><p>The experiment:</p></li></ul><p></p><p><strong>1. They used the fungus <em>Neurospora crassa</em>.</strong><br>Normal wild-type <em>Neurospora</em> can grow on <strong>minimal medium</strong> because it can synthesise all the metabolites it needs.</p><p><strong>2. They exposed the fungus to a mutagen.</strong><br>This created <strong>random mutations</strong> in its genes.</p><p><strong>3. They allowed the fungus to undergo sexual reproduction and collected haploid spores.</strong><br>The fact that the spores were <strong>haploid</strong> was really useful because each gene only had <strong>one copy</strong>. So if that copy contained a recessive mutation, its effect could be seen immediately.</p><p><strong>4. They first grew the mutants on complete medium.</strong><br>Complete medium contains lots of nutrients, vitamins and amino acids, so even mutants that couldn't synthesise something themselves could still survive.</p><p><strong>5. They then tested each mutant on minimal medium.</strong></p><p>Most could grow:</p><blockquote><p>Minimal medium → grows <span data-name="check_mark_button" data-type="emoji">✅</span> → can make everything it needs.</p></blockquote><p>But some <strong>couldn't grow</strong>:</p><blockquote><p>Minimal medium → no growth <span data-name="cross_mark" data-type="emoji">❌</span> → mutation has probably blocked a metabolic pathway.</p></blockquote><p><strong>6. They added specific nutrients to figure out what was missing.</strong></p><p>For example, suppose a mutant couldn't grow on minimal medium:</p><p><strong>Minimal medium </strong><span data-name="cross_mark" data-type="emoji">❌</span></p><p>But then:</p><p><strong>Minimal + vitamin X → grows </strong><span data-name="check_mark_button" data-type="emoji">✅</span></p><p>That tells you the mutation prevented the fungus from <strong>making vitamin X (or something in that pathway)</strong>.</p><p>By studying many mutants, Beadle and Tatum found that particular mutations could eliminate particular <strong>enzyme activities</strong>.</p><p> The conclusion </p><p>This led to the <strong>one gene–one enzyme hypothesis</strong>:</p><blockquote><p><strong>One gene controls the production/function of one enzyme, and that enzyme controls a particular step in a metabolic pathway.</strong></p></blockquote><p>So:</p><p><strong>Gene mutation → enzyme doesn't work → metabolic step blocked → required product isn't produced → organism needs that product supplied externally.</strong></p><div data-type="horizontalRule"><hr></div><p> Why was this such a big deal? </p><p>At this time, scientists <strong>didn't yet know that DNA was the genetic material</strong>. Proteins were still considered strong candidates for the hereditary material.</p><p class="p1">• ⁃ Fungus used: mutengenised it, grew it up, get them to make the sexual structure (like a volcano), pulled out haploid the spores from int here, plate it out, and see if they have phenotypes, tested after it grew to see if it’d grow properly even tho mutenegenised, one dint work it needed vitamin, when one is added it worked. They did this again and again again</p><p class="p1"></p><p class="p1"></p><p class="p1"></p><p class="p2">REMEMBER AT TGIS TIME NOONE KNEW DNA WAS THE GENES WE THOGUTH PROTEIN</p><ul><li><p>The pre-1940 beads-on-a-string concept</p><ul><li><p>The gene was thought to control the inheritance of one attribute or phenotype</p></li><li><p>The gene was not thought to be subdivisible by recombination, and was therefore the smallest unit of genetic material that could be mutated</p></li></ul></li></ul><p class="p1"></p><ul><li><p>The modern concept of the gene</p><ul><li><p>Controls synthesis of one polypeptide chain or RNA molecule</p></li><li><p>The nucleotide pair is the smallest unit that can be mutated; it cannot be subdivided by recombination&nbsp;</p></li></ul></li></ul><p></p>
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  1. RECOMBINATION WITHIN A GENE



  • Intragenic recombination: Pete Oliver demonstrated recombination between different mutant sites within the lozenge (lz) gene of Drosophila. Mutations such as spectacle (lzs) and glassy (lzg) affect the compound eye. When flies carrying different mutations within the same gene were crossed, rare wild-type recombinants could be recovered, demonstrating that recombination can occur within a gene. This showed that the gene is not an indivisible unit of recombination. Decades later, Charles Yanofsky, studying the trpA gene of E. coli, demonstrated genetic resolution down to extremely closely spaced nucleotide sites, further establishing that genes consist of many independently mutable and recombinable sites.


  • Pete Oliver described recombination within the lozenge gene of Drosophila, done in male flies. They could make a female with BOTH the LZg mutant

  • Shows genes can have recombincation

  • Mutants have severe compound eye perturbations

  • Can you get recombination within a gene? If so, WT recombinants should be obtainable from a cross of spectacle (lzs) and glassy eye (lzg) mutants

• ⁃ Charles Yanofsky described recombination between adjacent nucleotide pairs in the trpA gene of E. coli decades later

<ul><li><p><strong>Intragenic recombination:</strong> Pete Oliver demonstrated recombination between different mutant sites within the <strong>lozenge (lz) gene of <em>Drosophila</em></strong>. Mutations such as <strong>spectacle (lzs)</strong> and <strong>glassy (lzg)</strong> affect the compound eye. When flies carrying different mutations within the same gene were crossed, rare <strong>wild-type recombinants</strong> could be recovered, demonstrating that recombination can occur <strong>within a gene</strong>. This showed that the gene is not an indivisible unit of recombination. Decades later, <strong>Charles Yanofsky</strong>, studying the <strong><em>trpA</em> gene of <em>E. coli</em></strong>, demonstrated genetic resolution down to extremely closely spaced nucleotide sites, further establishing that genes consist of many independently mutable and recombinable sites.</p></li></ul><p></p><ul><li><p>Pete Oliver described recombination within the lozenge gene of Drosophila, done in male flies. They could make a female with BOTH the LZg mutant</p></li><li><p>Shows genes can have recombincation</p></li><li><p>Mutants have severe compound eye perturbations</p></li><li><p>Can you get recombination within a gene? If so, WT recombinants should be obtainable from a cross of spectacle (lzs) and glassy eye (lzg) mutants</p></li></ul><p class="p2">• ⁃ Charles Yanofsky described recombination between adjacent nucleotide pairs in the trpA gene of E. coli decades later</p>
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How protein made:

Collinearity means that the linear order of coding sequences in a gene corresponds to the linear order of amino acids in its polypeptide product.

<p>Collinearity means that the linear order of coding sequences in a gene corresponds to the linear order of amino acids in its polypeptide product.</p>
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PROKARYOTIC GENE:

• ⁃ Polysistzonic mrna, each has start stop, start stop. So does one by one







<p></p><img src="https://assets.knowt.com/user-attachments/7eca0b69-bd36-4248-b26a-4e3c536c96cf.png" data-width="50%" data-align="center" style="display: block; width: 50%; margin-left: auto; margin-right: auto;"><p></p><p></p><p></p><p></p><p></p>
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EUKARYOTIC GENE:

One single but with introns. No one knows where introns come from

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GENES WITHIN GENES IN BACTERIOPHAGE X174:


shows overlapping



  • Circular, single stranded DNA

  • 5386 nucleotides

  • Encodes 11 proteins that together contain 2300 amino acids (2300*3)

  • The genome contiains overlapping genes and genes within genes

  • Never say never!


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ALTERNATIVE SPLICING CAN PRODUCE PROTEIN ISOFORMS FROM A SINGLE GENE:

Alternative splicing: A single eukaryotic gene can produce multiple different protein isoforms through alternative splicing. The gene is first transcribed into a primary RNA transcript containing its exons and introns. During RNA processing, the introns are removed, but different combinations of exons can be retained and joined together, producing a family of different mature mRNAs from the same gene. These different mRNAs are then translated into different polypeptide isoforms. Therefore, one gene can produce multiple different protein products, increasing protein diversity without requiring additional genes.

<p><strong>Alternative splicing:</strong> A single eukaryotic gene can produce multiple different protein isoforms through <strong>alternative splicing</strong>. The gene is first transcribed into a primary RNA transcript containing its exons and introns. During RNA processing, the introns are removed, but <strong>different combinations of exons can be retained and joined together</strong>, producing a family of different mature mRNAs from the same gene. These different mRNAs are then translated into <strong>different polypeptide isoforms</strong>. Therefore, <strong>one gene can produce multiple different protein products</strong>, increasing protein diversity without requiring additional genes.</p>
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core concept

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MODULE TWO!

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WHO HAS A GENOME?

  • All living entities

    • Bacteria

    • Archaea

    • Eukaryotes (fungi, plants, animals, protists)

  • Some non-living entities

    • Viruses

    • Plasmids

  • Entire communities (“metagenome”)


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FUNCTIONS OF THE GENOME:

  • It is the storage unit 

  • The genetic material must replicate, control the growth and development of the organism, and allow the organism to adapt to changes in the environment

  • Genotypic function:

    • Replication

  • Phenotypic function

    • Gene expression

  • Evolutionary function

    • Mutation

• ⁃ Adaptations etcetc if + change

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DOES SIZE MATTER?

No.


A flower has more than a lizard and baby.



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THE GENOMES OF PROKAY. AND VIRUSES. mono vs haploid vs doploid

  • Bacterial and viral genomes are monoploid

    • What is the difference between monoploid, haploid and diploid?:




  • Bacterial and viral genomes are monoploid

  • Most viruses and bacteria have single set of genes stored in a single chromosome

  • This means that bacteria and viruses dont have the allelic complexity that comes with inheritance of chromosomes from two different parents

  • Bacteria also contain plasmids and transposable DNA elements



<ul><li><p>Bacterial and viral genomes are monoploid</p><ul><li><p>What is the difference between monoploid, haploid and diploid?:</p></li></ul></li></ul><p></p><p></p><p></p><ul><li><p>Bacterial and viral genomes are monoploid</p></li><li><p>Most viruses and bacteria have single set of genes stored in a single chromosome</p></li><li><p>This means that bacteria and viruses dont have the allelic complexity that comes with inheritance of chromosomes from two different parents</p></li><li><p>Bacteria also contain plasmids and transposable DNA elements</p></li></ul><p class="p2"></p><p></p>
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E.coli: genome plasmids:

Fertility, resistance, col



<p>Fertility, resistance, col</p><p></p><p></p>
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Structure of bacterial genomes:

  • Just shows the many changes bacterias go through. 

• ⁃ Operon is helps sit all these genes. It controls it all (genes), operon makes it all on or all off, it depends but if an operon is on it, that is what it is for, more efficient


<ul><li><p>Just shows the many changes bacterias go through.&nbsp;</p></li></ul><p class="p1">• ⁃ Operon is helps sit all these genes. It controls it all (genes), operon makes it all on or all off, it depends but if an operon is on it, that is what it is for, more efficient</p><p class="p1"></p>
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Gene content in bacterial genes: 

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Virus genomes:

  • Can only reproduce by infecting living host cells

  • Outer capsid protein enclosing genetic materials- DNA, ssDNA, ds RNA, ssRNA

  • Linear and circular genomes

  • Most viruses are bacteriophages a virus that infects bacteria and arches

• ⁃ Very high coding density






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Why should we use viruses and bacteria to study for genetics?

Why should we study viruses and bacteria for genetics?

Such a system would also be useful for finding out fundamental things about gene expression, DNA replication, intra

  • cell DNA strand exchange events, DNA repair, transcription, and translation

High repilicaiton rate

No ethics issue

Simple genetic structure (not rlly why but yeah)

Can culture them




<p>Why should we study viruses and bacteria for genetics?</p><p class="p1">Such a system would also be useful for finding out fundamental things about gene expression, DNA replication, intra</p><ul><li><p>cell DNA strand exchange events, DNA repair, transcription, and translation</p></li></ul><p class="p1">High repilicaiton rate</p><p class="p1">No ethics issue</p><p class="p1">Simple genetic structure (not rlly why but yeah)</p><p class="p1">Can culture them</p><p class="p1"></p><p class="p1"></p><p class="p1"></p>
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BACTERIAS CLONAL REPLICATION AND A SIMPEL CELL CYCLE:

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phenotypes in bacteria are:

(i) defined by the genome

(i) ways to see that genes have been inherited and expressed

(ii) things that can be used for selection in genetic screens


WHAT ARE SOME USEFULL PHENOTYPIC CHARACTERICS THAT WE CAN USE FOR SELCTION OR OBSERVATION

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Is bacterial genuine static or labile (mobile and plastic)?

Know how to write genes vs phone

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PROTOTROPHS VS AUXOTROPHIC

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Testing for nutritional requirements:

Horizontal vs vertical transfer

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PANASEXUAL PROCESSES: FORU TYPES

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lecture seven review














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Review three parasexual mechanisms of dna:\ in bacteria:

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The discovery of transformation:



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How know what it is:

Agglutination: