Chapter 14 - Oxidation and Reduction

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Chemistry

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30 Terms

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oxidation in terms of electron transfer

loses ie. if a substance loses electron(s), it is oxidised

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reduction in terms of electron transfer

gains ie. if a substance gains electron(s), it is reduced

Note: Reactions in which one substance is oxidised and one substance is reduced are known as redox reactions

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oxidising agent

is a substance that brings about oxidation in other substances (goes through reduction)

i.e. causes another substance to lose electrons – therefore the oxidising agent is itself reduced or gains electrons

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reducing agent

is a substance that brings about reduction in other substances (goes through oxidation)

i.e. causes another substance to gain electrons – therefore the reducing agent is itself oxidised or loses electrons

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oxidation in terms of oxidation number

increases

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Show in terms of electron transfer that the rusting of iron is a redox reaction

• Rusting involves the reaction of iron with oxygen to form an oxide of iron

4Fe + 3O2 → 2Fe2O3

<p>• Rusting involves the reaction of iron with oxygen to form an oxide of iron </p><p style="text-align: start">4Fe + 3O2 → 2Fe2O3</p>
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Give an example of an oxidising agent used in swimming pools

• Chlorine (Cl2) is added to swimming pools to disinfect them, it reacts with the water to form free chlorine species; hypochlorous acid (HOCl) and the hypochlorite ion (OCl–) which oxidise and kill micro-organisms

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Explain how oxidising agents and reducing agents are used in different bleaches

Oxidising agent: Sodium hypochlorite (NaOCl) is used in household bleaches

Example: Domestos for removing stains from clothes and acting as a disinfectant

Reducing agent: Sulfur dioxide (SO2) is used to reduce and bleach the pigment in wood in the manufacture of paper

Note: In most reactions it can be difficult to tell what is oxidised and reduced/what is the oxidising agent and reducing agent…… we use oxidation numbers

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Define oxidation number

• Oxidation number is the charge an atom has or appears to have when electrons are distributed according to certain rules

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Rules of oxidation numbers

1. In any neutral compound/molecule the sum of the oxidation numbers must equal 0

2. In any complex ion, the sum of all the oxidation numbers must equal the charge on the ion

3. A free element (An element not bonded to another element or bonded to itself) always has an oxidation number of 0

4. The oxidation number of an ion is equal to the charge on the ion

5. Oxygen always has an oxidation number of -2 in its compounds

6. Hydrogen always has an oxidation number of + 1 in its compounds

7. Fluorine always has an oxidation number of - 1 in its compounds

8. Group 1 elements always have an oxidation number of + 1 and Group 2 elements always have an oxidation number of + 2 in their compounds

9. In the case of ionic compounds, an element’s oxidation number is equal to the charge on its ion

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Exceptions to rules of oxidation numbers

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How does the oxidation number of the oxidising agent change during a redox reaction?

• The oxidising agent is itself reduced……. oxidation number decreases

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How does the oxidation number of the reducing agent change during a redox reaction

• The reducing agent is itself oxidised……. oxidation number increases

Important: When asked to identify oxidising agents and reducing agents, the entire compound is named (unless the question specifically says ‘element’ like 2020! :))

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Balancing redox equations using oxidation numbers

Note: Redox reactions typically do not show every element involved and just shows the relevant ions; therefore they cannot be just balanced by inspection, oxidation numbers need to be used

Step 1: Assign oxidation numbers to all elements in the equation

Step 2: Focus on which elements changed in oxidation number

Step 3: Write out how many electrons EACH ATOM of the element reduced gains and how many electrons EACH ATOM of the element oxidised loses

Step 4: Balance the number of electrons lost and the number of electrons gained by multiplying the substance oxidised and the substance reduced by the lowest factors possible

Step 5: Balance the remaining equation as normal by inspection

(Leave oxygen and hydrogen atoms till last if involved)

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reduction in terms of oxidation numbers

decreases

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elements on their own

0

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ions

same as charge

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charge of all elements in a compound

0

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oxygen

-2

expections: h202, na202 = -1 and of2 = +2

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hydrogen

+1

exceptions are the metal hyrbids NaH = -1

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halogens

-1 except when joined to a more electronegative element

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alkali metals

+1

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alkaline earth metals

+2

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The electrochemical series

• All metals lose electrons (are oxidised) when they react

• The electrochemical series is a table of metals arranged in order of how easily they lose

electrons (are oxidised) /their reducing abilities/how reactive they are

• The higher up the metal is the more easily it will be oxidised/reduce other substances

Potassium (K)

Sodium (Na)

Calcium (Ca)

Magnesium (Mg)

Aluminium (Al)

Zinc (Zn)

Iron (Fe)

Lead (Pb)

Hydrogen (H)

Copper (Cu)

Silver (Ag)

Gold (Au)

• A metal higher up in the series will reduce a metal lower down and displace it from a compound

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Write a balanced equation for the reaction that occurs when magnesium is placed in copper II sulfate solution. Explain this reaction and describe what is observed

• Magnesium is higher than copper in electrochemical series so has a higher reducing ability. Magnesium reduces copper (causes it to gain electrons) and displaces copper from the compound copper (II) sulfate.

• Magnesium sulfate and copper are formed

Observe: - Blue colour of copper (II) sulfate becomes colourless

- A brown precipitate of copper metal forms

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What is observed when copper is placed in dilute sulfuric acid. Explain this observation

• Copper is lower than hydrogen in the electrochemical series and will not reduce and displace it from a compound.

Observe: No reaction

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Give an application of knowledge of the electrochemical series

• Scrap iron (Iron II) can be used to reduce and displace a more useful but less reactive metal such as copper from a compound

• Copper is extremely useful in the electronics industry Example: For electrical wires

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Give an application of knowledge of the electrochemical series

• Scrap iron (Iron II) can be used to reduce and displace a more useful but less reactive metal such as copper from a compound

• Copper is extremely useful in the electronics industry Example: For electrical wires

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Which metals from the electrochemical series are found free in nature? Why?

• Lead (Pb), Copper (Cu), Silver (Ag), Gold (Au)

• These metals are at the bottom of the electrochemical series and will not oxidise easily i.e. are very unreactive

Note: Metals at the top of the electrochemical series are very reactive and are only found in compounds (not free in nature)

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Why are halogens good oxidising agents?

• Halogens (Group VII elements) usually act as oxidising agents due to their high electronegativity values – they have a strong attraction for electrons and tend to remove electrons from other substances i.e. oxidise them