Set Theory Lecture Review Flashcards

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Vocabulary-style practice flashcards reviewing core set theory concepts, roster forms, interval representations, and subset calculations from the lecture.

Last updated 6:56 AM on 8/28/26
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10 Terms

1
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Cardinality of Disjoint Set Difference n(AB)n(A - B)

For two disjoint sets AA and BB, the value of n(AB)n(A - B) is equal to n(A)n(A). For example, if n(A)=4n(A) = 4 and n(B)=2n(B) = 2, then n(AB)=4n(A - B) = 4.

2
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Roster Form of Prime Numbers in Universal Set U={1,2,3,4,5,6,7,8}U = \{1, 2, 3, 4, 5, 6, 7, 8\}

The roster form of set A={x:xU and x is a prime number}A = \{x : x \in U \text{ and } x \text{ is a prime number}\} is {2,3,5,7}\{2, 3, 5, 7\}.

3
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Proper Subsets Element Formula

The number of proper subsets of a set with nn elements is given by 2n12^n - 1. If a set has 6363 proper subsets, solving 2n1=632^n - 1 = 63 gives n=6n = 6 elements.

4
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Roster Form of Integers Between 3-3 and 77

The roster form of set A={x:x is an integer and 3<x<7}A = \{x : x \text{ is an integer and } -3 < x < 7\} is {2,1,0,1,2,3,4,5,6}\{-2, -1, 0, 1, 2, 3, 4, 5, 6\}.

5
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Empty Set Cardinality Example

For set A={x:x is a natural number,x<5 and x>7}A = \{x : x \text{ is a natural number}, x < 5 \text{ and } x > 7\}, no natural number satisfies both conditions simultaneously, so n(A)=0n(A) = 0.

6
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Set-Builder Form of Open Interval (6,12)(6, 12)

The set-builder representation of the open interval (6,12)(6, 12) is {x:xR,6<x<12}\{x : x \in \mathbb{R}, 6 < x < 12\}.

7
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Union of a Subset and Its Container Set

If AA and BB are two sets such that ABA \subset B, then their union ABA \cup B is equal to BB.

8
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Subsets Count for Prime Numbers Less Than 1010

The set A={x:x is a prime number less than 10}A = \{x : x \text{ is a prime number less than } 10\} consists of 44 elements: {2,3,5,7}\{2, 3, 5, 7\}. The total number of subsets is 24=162^4 = 16.

9
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Number of Subsets of Set A={1,2,3}A = \{1, 2, 3\}

For a set AA with 33 elements, the total number of subsets is given by 23=82^3 = 8.

10
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Number of Subsets of a Two-Element Set

If a set AA contains 22 elements, the total number of subsets is calculated as 22=42^2 = 4.